Lab Experiment 8: Oxidation Puzzle Post Lab Report for 2-ethyl-1‚3-hexandiol Calculations Theoretical yield: 1.857g Product Yield: 1.055g ----> Percent yield = (1.055g/1.87g) x 100% = 56.41% Starting amount of diol: 1.184g ----> Percent Yield = (1.184g/1.87g) x 100% = 63.32% Spectroscopy O-H (Stretch‚ H-bonded) C-H (Stretch) C-H (2720-2820 cm-1) Carbonyl C-O (Stretch) Product wavelength cm-1 3422 Strong‚ Broad 2877‚2936‚2964 Strong‚ Medium None Present 1705 Strong
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cause systematic alkalosis b. Should not be a laxative or cause constipation c. Should exert rapid effect and should last long d. Should not cause a large evolution of gas (flatulation) e. Buffer range of 4 – 6 pH f. Should inhibit pepsin 1. SODIUM BICARBONATE Disadvantages: • highly water soluble • short duration of effect • gastric pH of 7 or above • can cause belching and flatulence Benefits: • sparkling flavor 2. ALUMINUM HYDROXIDE Forms: a. Aluminum Hydroxide Gel (suspension)
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Section A (Answer ALL questions in this Section.) 1. Rubidium (Rb) and potassium belong to the same group in the Periodic Table. The relative atomic mass of rubidium is larger than that of potassium. (a) Explain whether rubidium is more reactive than potassium. (b) Write a chemical equation for the reaction between rubidium and water. (State symbols should be given.) (c) Suggest how rubidium can be stored safely in the laboratory. (d) Suggest ONE safety precaution for handling
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The color of the dye comes from the delocalization of electrons in the πbonding system (Exton‚ 149). Bleach is an aqueous solution that contains sodium hypochlorite (NaOCl). The hypochlorite of bleach breaks the double bonds of the food dye through oxidation‚ forming molecules that do not absorb visible light and thus bleaching the product. During this process‚ hypochlorite is reduced to chloride and hydroxide ions. OCl (aq) + H2O (l) + 2e → Cl (aq) + 2OH (aq) Our goal in this experiment was to observe the reaction and concentration changes between
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With Calcium Hypochlorite and Acetone When chlorine is passed into boiling alcohol‚ both chlorination of the methyl group and oxidation of the primary alcohol group to an aldehyde occur‚ giving trichloro-acetaldehyde or chloral: When chloral is treated with caustic alkali‚ fission of the C-C linkage occurs‚ giving chloroform and a formate. Acetaldehyde and also many ketones‚ such as acetone‚ containing the CH3CO- group behave similarly when treated with calcium or sodium hypochlorite‚ chlorination
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purpose of this lab was to find the molar ratio of NaClO and an unknown substance labeled solution “B”. Using the method of continuous variation the ratio of the two solutions were changed but kept equal to 50 mL. The reaction was an exothermic oxidation-reduction and the temperature change was measured to determine which ratio of NaClO to solution “B” was optimal. The ratio with the highest temperature change was 40mL of NaClO to 10 mL of solution “B”. Once simplified‚ this means the ratio is 4:1
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Alkali Metals Introduction Alkali metals refer to six elements belonging to the Group IA of the long form of the Modern Periodic Table‚ viz. Lithium (Li)‚ Sodium (Na)‚ Potassium (K)‚ Rubidium (Rb)‚ Cesium (Cs) and Francium (Fr). Fr is a radioactive element. These elements are called so because they form strongly alkaline oxides and hydroxides. Electronic Configuration of Alkali Metals Each of the alkali metals has one electron in their outermost (valence) shell‚ which is just outside an inert
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SOAP & DETERGENT I) Definition of Soap o Soap are sodium or potassium salts of long-chain carboxylic acids o The general formula of a soap : RCOO Na / RCOO K • R is an alkyl group which contain 12 to 18 carbon atoms. II) The history of soap manufacturing. ▪ Solvay Process - Carbon dioxide ( obtained from heating CaCo ) is passed into concentrated NaCl solution which is saturated with ammonia . NaCl +NH +H
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State University- San Marcos in room 117 of the chemistry building. The concentrations used in the experiment were both .5 M sodium hypochlorite and sodium thiosulfate. The concentrations of the solutions found in the dumpster were calculated to be .806 M (both sodium hypochlorite and sodium thiosulfate as well). This was found by taking the 6.0% (by mass) sodium hypochlorite and multiplying it by 1 gram of solution‚ 1000 mL and 1 mol NaClO. This result was then divided by the result of 100g of solvent
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performed at Texas State University – San Marcos in the Chemistry lab. The concentrations used in the experiment were 0.5M of sodium hydroxide and 0.5M of sodium hypochlorite. The concentrations of the solutions found in the dumpster were calculated to be .806 M (both sodium hypochlorite and sodium thiosulfate as well). This was found by taking the 6.0% (by mass) sodium hypochlorite and multiplying it by 1 gram of solution‚ 1000 mL and 1 mol NaClO. This result was then divided by the result of 100g of
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