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    Cellular Respiration Lab

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    other hand‚ lactic acid is a waste product of certain bacteria (Lactobacillales)‚ which is utilized to create many dairy products such as yogurt and cheese. In addition‚ humans can resort to lactic acid fermentation when oxygen is limited‚ so it is used as an extra source to obtain oxygen. In our experiment we will be using yeast‚ a single-celled organism that utilizes sugar as a food source‚ and it produces energy substances through the breakdown of sugar molecules. Specifically‚ the type of sugar as

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    Ap Bio Respiration Frq

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    40) Describe the structure of a mammalian respiratory system. Include in your discussion the mechanisms of inspiration and expiration. In mammals‚ oxygen first passes through the nasal cavity. The nasal cavity is covered with mucus and cicilia to filter the air. The nasal cavity leads to the pharynx. The pharynx consists of the eustachian tube and the tonsils. The inhaled air then passes to the larynx‚ trachea‚ and bronchi. The bronchi lead to the bronchioles in the lungs. In the lungs the pleural

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    Ap Biology Enzyme

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    substance with‚ 1.5 ml of H2O2‚ 1.5ml of H2O and different amounts of enzyme drops‚ to determine how much oxygen gas is produced during the reaction since the pressure of the test tube will get higher as more oxygen gas is accumulated during the reaction. 2) If more drops of the enzyme are added to the substance with‚ 1.5 mL of H2O2 and 1.5mL of H2O‚ the reaction will accumulate more oxygen gas which will lead to an increase of pressure (kpa) in the test tube. It will also affect the average slope

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    depending on the availability of oxygen and their biological make-up. In many cases the cells are in an oxygen-rich environment. For example‚ as you sit and read this sentence‚ you are breathing in oxygen‚ which is then carried throughout your body by red blood cells. But‚ some cells grow in envi¬ronments without oxygen (yeast in wine-making or the bacteria that cause botulism in canned food)‚ and occasionally animal cells must function without sufficient oxygen (as in running sprints). In this activity

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    Lab 5 Cellular Respiration

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    Lab 5Cellular Respiration Introduction: Cellular respiration is an ATP-producing catabolic process in which the ultimate electron acceptor is an inorganic molecule‚ such as oxygen. It is the release of energy from organic compounds by metabolic chemical oxidation in the mitochondria within each cell. Carbohydrates‚ proteins‚ and fats can all be metabolized as fuel‚ but cellular respiration is most often described as the oxidation of glucose‚ as follows: C6H12O6 + 6O2 → 6CO2 + 6H2O + 686 kilocalories

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    Water and Bonding

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    “WATER IS A GOOD SOLVENT” Water is very unique in all facets of its nature. The chemical formula for water is H2O as a water molecule consists of two atoms of the chemical element hydrogen (H) and one atom of the element oxygen (O). Water is the most abundant chemical compound on earth as its mass all exists together‚ naturally‚ in its gaseous‚ liquid and solid state. It is the most precious natural resource to man and is essential to life for all discovered living organisms. One of the unusual

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    Abstract The decomposition of hydrogen peroxide (H2O2) in a whole and diced wedges by with The enzyme catalase was observed. The catalase was able to break down the hydrogen peroxide In the diced banana wedge better than the whole banana because after the banana was diced that Increases the surface area allowing the breakdown to flow. The effects of temperature on enzyme In a liver sample were observed under iced‚ boiling‚ 37 degrees‚ and room temperature Conditions. The enzymes became completely

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    temperatures (above 400’C) it decomposes poto tassium chloride and elemental oxygen‚ according to the following equation: 2 KCIOB(s) -----+ 2 KCI(s) + 3 Ork) The relative amounts of oxygen and potassium chloride are measured by heating a weighed sample of potassium chlorate and determining the amount of residue (potassium chloride) remaining. The decrease in mass brought about by heating represents the amount of oxygen originally present in the sample. From the experiment we obtain the following

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    Catalase Lab

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    handout attached to the back of lab Observations Table 1: The mL of oxygen produced with increase of catalase 30secs 60secs 90secs 120secs 150secs 180secs Disks: 2 17ml 16ml 21ml 26ml 31ml 35ml Disks: 4 8ml 19ml 27ml 35ml 44ml 53ml Disks: 6 15ml 23ml 32ml 44ml 54ml 65ml Disks: 8 25ml 42ml 70ml 90ml 100ml at 2:20 secs Disks: 10 29ml 58ml 87ml 100ml at 1:46 secs Table 2: The mL of oxygen produced with increase of H202 30secs 60secs 90secs 120secs

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    atomic number = 74)? a) 30.0 g FeWO4 b) 304 g FeWO4 c) 82.6 g FeWO4 d) 188 g FeWO4 d) FeSO4 4. A compound contains 20.2% magnesium‚ 39.8% titanium‚ and 40.0% oxygen by mass. What is the empirical formula of this compound? a) MgTiO b) MgTi2O3 c) Mg2TiO4 d) MgTiO3 5. Which of the following DOES NOT contain 4.00 moles of oxygen atoms? a) 2.00 moles of CO2 b) 128.0 g of SO2 c) 0.40 moles of P4O10 d) 4.00 moles of KClO3 6. A compound has an empirical formula of C2HBr. If the molar mass

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