this answer booklet. 8360/2 Mark Formulae Sheet Volume of sphere = 4 3 r 3 r Surface area of sphere = 4r 2 Volume of cone = 1 2 r h 3 Curved surface area of cone = r l l h r In any triangle ABC C 1 Area of triangle = ab sin C 2 Sine rule a b c = = sin A sin B sin C 2 2 a b A c B 2 Cosine rule a = b + c – 2bc cos A cos A = b2 c2 a2 2bc The Quadratic Equation The solutions of ax 2 + bx + c = 0‚ where
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Geometry Final Exam Review #1 Semester 2 Name:________________________ Hour:_______ GEOMETRY SEMESTER 2 FINAL REVIEW #1 1. The ratio of the side lengths of ΔOMN to ΔHGI is 4:3. Find x and y. 2. Find f. 3. The triangles are similar. Which choice below is NOT a correct statement? (A) B F (B) ΔBAC~ΔFDE BA FE (C) BC FD AC BC (D) DE FE (E) A D 4. Which of the following statements is not true? (A) ΔABC ~ ΔEDC by SAS~ (B) ΔABC ~ ΔEDC by AA~ (C) ΔABC ~ ΔEDC by SSS~ (D) ΔCDE ~ ΔCBA by SAS~
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Mock AIME Series Thomas Mildorf November 24‚ 2005 The following are five problem sets designed to be used for preparation for the American Invitation Math Exam. Part of my philosophy is that one should train by working problems that are more difficult than one is likely to encounter‚ so I have made these mock contests extremely difficult. The idea is that‚ once you become acclimated to them‚ the real AIMEs will seem easier‚ and you will approach them with justifiable confidence. Therefore‚ do not
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Research Question: How has the Ancient Greek Philosopher Pythagoras impacted our modern day perception of knowledge‚ being and conduct in Mathematics? Introduction: The Civilization of Ancient Greece has played a vital role in how our modern world functions. Located on the Balkan Peninsula with the Aegean Sea on its East‚ the Mediterranean Sea to its South and the Ionian Sea to its West. The Ancient Greeks have helped us to understand topics ranging from art‚ astronomy‚ mathematics and philosophy
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Conjecture - If a point is on the bisector of an angle‚ then it is equidistant from the sides of the angle. C9- Angle Bisector Concurrency Conjecture - The three angle bisectors of a triangle are concurrent (meet at a point). C10- Perpendicular Bisector Concurrency Conjecture - The three perpendicular bisectors of a triangle are concurrent. C11- Altitude Concurrency Conjecture
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Theorems Definitions Name Complementary Angles Supplementary Angles Theorem Vertical Angles Transversal Corresponding angles Same-side interior angles Alternate interior angles Congruent triangles Similar triangles Angle bisector Segment bisector Legs of an isosceles triangle Base of an isosceles triangle Equiangular Perpendicular bisector Altitude Definition Two angles whose measures have a sum of 90o Two angles whose measures have a sum of 180o A statement that can be proven Two angles formed
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z=2(cos(5π/6) + i sin(5π/6)) Apply De Moivre’s Theorem‚ z-10 = (√3 – i)-10 =2-10 (cos(10*5π/6) + i sin(10*5π/6)) = ...... And‚ I think you should be able to get the answer for (√3 – i)-10. 19. Sketch triangle and find other five ratios of θ. sin θ = 3/5 Step 1‚ we sketch a right triangle to specify the angle θ. Step 2‚ since we are given sin θ = 3/5‚ mark the opposite and hypotenuse as the graph below. Step 3‚ find out the missing length by using Pathagorean Theorem. 32 + adjacent2
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Mathematics Quiz 11 (CH11 Applications in Trigonometry) Name:_____________ Class: 5___ Class No: ___ Marks: ____ / ____ Answer all questions Section A (1 mark each) 2011-CE-MATH 2 Q24 1. The figure shows a prism ABCDEF with a right-angled triangle as the cross-section. The angle between BE and the plane ABCD is A. ABE. B. CBE. C. DBE. D. EBF. 2011-CE-MATH 2 Q50 2. In the figure‚ ABCDEFGH is a cuboid. If FHG = x‚ BFG = y and HBG = z‚ then tan z = A. tan x tan y. B. . C. . D
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GREATSCOREon the GMAT‚ you have to go with MANHATTAN GMAT." - Student at top 5 b-schoo] Strategies For Top Scores IPart I: General I 1. POLYGONS In Action Problems Solutions ::M.anfiattanG MAT·Prep the new standard 11 19 21 2. TRIANGLES & DIAGONALS In Action Problems Solutions 25 35 37 3. CIRCLES & CYUNDERS In Action Problems Solutions 41 49 51 4. UNES & ANGLES In Action Problems Solutions 55 59 61 5. COORDINATE PLANE In Action Problems Solutions 63
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perimeter of the Classic/Variation Snowflakes to find the total area and perimeter of the final snowflake for each. For both the Classic and Variation Koch Snowflake‚ an equilateral triangle is used to start. We will be using basic arithmetic based on what we know about triangles to find the perimeter and area of the starting triangle. The information gathered here is crucial in our implementation of a sequence for finding the perimeter of the first five/final
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