Centripetal force (from Latin centrum "center" and petere "to seek"[1]) is a force that makes a body follow a curved path: its direction is always orthogonal to the velocity of the body‚ toward the fixed point of the instantaneous center of curvature of the path. Centripetal force is generally the cause of circular motion. In simple terms‚ centripetal force is defined as a force which keeps a body moving with a uniform speed along a circular path and is directed along the radius towards the centre
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Chapter 20 Driving Forces Analysis Ch20. Driving Forces • • • • • • • • • Short Description Background Strategic Rationale & Implications Strengths & Advantages Weaknesses & Limitations Process for Applying Technique Summary Case Study: Digital Music Industry FAROUT FT Press 2007. All Rights Reserved. Business and Competitive Analysis. By C. Fleisher & B. Bensoussan. Ch20.2 Ch20. Driving Forces Short Description • Driving forces analysis (DFA) is a way
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Hours: before and/or after class by appointment Conference calls also possible Textbook: Assembled readings and case studies Course Description The objectives of this course are to improve your understanding of the role of the sales force in the achievement of a firm’s business objectives‚ and to enhance your decision-making skills in the development and management of sales programs. The course is divided into four sections; 1. Customer Interface Strategies and Selling Effectiveness
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Latihan 5: Magnetism Magnetic Fields 1. An electron gun fires electrons into a magnetic field directed straight downward. Find the direction of the force exerted by the field on an electron for each of the following directions of the electron’s velocity: (a) horizontal and due north; (b) horizontal and 30° west of north; (c) due north‚ but at 30° below the horizontal; (d) straight upward. 2. (a) Find the direction of the force on a proton moving through the magnetic fields in Figure
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equilibrium of forces was investigated through the use of different weights attached to cords which were connected to a central ring‚ while pulleys supported them. This assembly facilitated the force band system to demonstrate that equilibrium will be attaining regardless of disturbances. However‚ due to errors in the experiment‚ the sum of the x and y component did equate to zero as predicted. The graphical solution of the experiment yield a polygon that is completed indicating that all the forces are in
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Centripetal force From Wikipedia‚ the free encyclopedia Jump to: navigation‚ search Not to be confused with Centrifugal force. This article contains many unreferenced sections and needs additional citations for verification. Please help improve this article by adding citations to reliable sources. Unsourced material may be challenged and removed. (January 2011) Roller coaster cars are forced through a loop by the track applying a centripetal force on them. A reactive centrifugal force is applied
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Engineering Mechanics: Statics in SI Units‚ 12e 2 Force Vectors Part 2 Copyright © 2010 Pearson Education South Asia Pte Ltd Chapter Objectives • Cartesian vector form • Dot product and angle between 2 vectors Copyright © 2010 Pearson Education South Asia Pte Ltd Chapter Outline 1. 2. 3. 4. 5. Cartesian Vectors Addition and Subtraction of Cartesian Vectors Position Vectors Force Vector Directed along a Line Dot Product Copyright © 2010 Pearson Education South Asia Pte
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Abstract: The previous lab explored the effect of gravity on free fall. It was determined that acceleration is always constant under free fall. However‚ in this lab‚ acceleration was observed under different forces‚ other than just gravity. Therefore‚ depending on how strong the forces being exerted were‚ acceleration differed. It wasn’t constant anymore. Using a glider on a air track and a pulley‚ different masses were attached at the end of the string and the glider was allowed to move on the
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questions: force and motion I problem 1 The figure below is an overhead view of a 12 kg tire that is to be pulled by three ropes. One force (Fl‚ with magnitude 50 N) is indicated. Orient the other two forces F2 and F3 so that the magnitude of the resulting acceleration of the tire is least‚ and find that magnitude if (a) F2 = 30N‚ F3= 20 N; (b) F2= 30 N‚ F3 = 10 N; and (c) F2 = F3 = 30 N. problem 2 A weight-conscious penguin with a mass of 15.0 kg rests on a bathroom scale (see figure below).
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The electric field depicts the surrounding force of an electrically charged particle exerted on other electrically charged objects. The concept of an electric field was introduced by Michael Faraday. The electric field is a vector field with SI units of newtons per coulomb (N C−1) or‚ equivalently‚ volts per metre (V m−1). The SI base units of the electric field are kg⋅m⋅s−3⋅A−1. The strength or magnitude of the field at a given point is defined as the force that would be exerted on a positive test
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