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    Chemistry Lab

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    TITLE: THE EFFECT OF HEATING DIFFERENT SUBSTANCES INTRODUCTION: In this exercise‚ it was required to observe carefully what happened when certain substances were heated in a burner‚ and to note the appearance of the residue after heating. AIM: To observe the effects of heating different substances. MATERIALS:  Hard glass test tubes  Powered samples of  Lead (II) nitrate  Copper (II) sulphate  Ammonium chloride  Zinc sulphate  Basic copper (II) carbonate‚ CuCO3. Cu(OH)2

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    Chemistry Dilutions

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    Name‚ Date‚ Hour Lesson Objective: Key Vocabulary: Lesson pH and dilutions Science Starter: Determine the pH of .0103M H3PO4 solution in water. Remember to look at the H+ count. Box 1 In a dilution‚ the number of solute particles does not change‚ just the concentration with respect to the volume. This relationship is _____________________ proportional. Initially‚ there is 275mL 0.125M stock solution of a substance. -Determine the amount of moles of solute present. -What is the concentration

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    Chemistry work

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    HW: p.491(1-7) 1. Compare the general properties of acids with the general properties of bases. Acids: Aqueous solutions of acids have a sour taste. Acids change the color of acid-base indicators. Some acids react with active metals and release hydrogen gas‚H2. Acids react with bases to produce salts and water. Acids conduct electric current. Bases: Aqueous solutions of bases taste bitter. Bases change the color of acid-base indicators. Dilute aqueous solutions of bases feel slippery

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    3.07 chemistry

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    Copy the following questions into your assessment document. You may copy and paste the table‚ or create a similar table in the document.) After completing the molecular models‚ fill in the table below: (18 points) Molecule What is the central atom of this molecule? Number of lone pairs on the central atom Number of atoms bonded to the central atom Molecular geometry Bond angle (based on VSEPR theory) CCl2F2 C Zero 4 Tetrahedral 109 degrees HCN C Zero 2 Linear 180 degrees

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    Chemistry Research

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    Periodically Puzzling Here are some questions about the elements‚ their properties‚ and periodicity. In each case‚ the correct answer is the name of an element (one of the two given). Write the answer in the appropriate space at the right‚ placing the first letter in the first blank. There are more than enough blanks to fit either element name‚ so the number of letters in the name cannot be used as a clue. When the puzzle is complete‚ the Periodic Law will be displayed in the highlighted column

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    Chemistry and Biology

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    CHAPTER 7 LIMITS AND CONTINUITY Focus on Exam 7 1 (a) |x + 3| = { -x - 3‚ x < -3‚ x + 3‚ x ≥ -3. (x + 1)(-x - 3) x+3 = -x - 1 (x + 1)(x + 3) For x ≥ -3‚ f (x) = x+3 =x+1 Hence‚ in the non-modulus form‚ -x - 1‚ x < -3‚ f (x) = x + 1‚ x ≥ -3. For x < -3‚ f (x) = { (b) The graph of f(x) is as shown below. y = −x − 3 y 2 y=x+1 1 −3 −2 −1 x O −1 −2 (c) lim f (x) = 2 x → -3- lim f (x) = -2 x → -3+ (d) lim f (x) does not exist

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    Questions on Chemistry

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    CUSTOMER CHARTER ACHIEVEMENTS 20131 Statistics complaint is related only to complaints against claims / benefits process in the month of January 2013. Category 1 Pay Temporary Disablement Benefit to the employee within 7 days after all required information and documents received complete. Number of case payments‚ (January 2013) - 4‚470 Number of cases of paid within 7 days‚ (January 2013) - 4‚429 Percentage fee within 7 days‚ (January 2013) - 99.08% Real Case: Men seizures disappointed Sosco

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    Perfume Chemistry

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    Imperialism in the late 19th and early 20th centuries Pre Imperialism: Alaska purchase and sig Reason: remove Russian threat from N America‚ get raw materials Purchase: Sec of State Will Seward finalized with $7.2mil “Seward’s folly/ice box” Sig: Russian threat removed from N America Imperialistic Concepts (large/strong takes small/weak) Reasons for Imperialism: $ (economy)‚ naval bases‚ colonies b/c of overpopulation‚ humanitarian reasons “Influence of Sea Power upon History 1660-1783”

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    Chemistry (Redox)

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    Experiment 1 : Redox Titration Using Sodium Thiosulphate Abstract This experiment is to determine the concentration of oxidizing solution using the iodine/ thiosulphate titration where the reducing solution is potassium iodate solution and the oxidizing solution is sodium thiosulphate solution. Potassium iodate solution which is an oxidizing agent is added into an excess solution of acidified potassium iodide. This reaction will release iodine. Potassium iodide is acidified with sulphuric acid

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    chemistry research

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    Lime scale form when hot water is heated about 61’C. All the acids listed about remove lime scale because the ions in the acids react with the calcium ions in limescale to then form a soluble salt. The acids also react with the carbonates in lime scale to produce water and carbon dioxide. Then the whole solution washes out taking away as much lime scale and possible. Sulfamic acid The advantages of using sulfamic acid as a de-scaler are that it is the faster de-scaler which means it can give

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