Yield to Maturity Kindra Hill University of Phoenix MMPBL/503 Wk 5 June 27‚ 2010 Scenario: A coworker of yours was discussing her investments with a broker. Your coworker was confused because she had purchased a 10% bond but the broker kept repeating that it had a 9% yield to maturity. Explain the concept of yield to maturity. This paper will explain the concept of yield to maturity in reference to bonds. It will allow for understanding of the difference in the stated rate of
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measured to the center of the object’s mass and the acceleration due to gravity “g”. By rearranging this expression it s possible to derive the following. As seen from the expression‚ a plot of pendulum length verses its period squared will yield a straight line. The slope will be dependent upon the local acceleration due to gravity (9.803 m/s2) Procedure: Since the length to be used in this experiment is the distance to the center of the pendulum’s mass‚ the diameter of the bob is estimated
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Abstract: All the materials were measured and weighed. It was found in the experiment that the yield of copper hydroxide in 40%. Introduction: The copper (II) sulphate is then placed in 100 mL of distilled water. Then 20 mL of CuSO4 is measured and placed 100 mL of distilled water. This can later be weighed to determine the mol of CuSO4 and the mol/L concentration. Then this was used to find out how many mL of 0.5 NaOH solution is needed to react completely with all the copper (II)
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be: 2Fe (Ш) + 3CuCl2 (aq) → 3Cu + 2FeCl2 In addition‚ we will need to find the percent yield of copper. Percent yield is a measure of the mass of what was produced ("experimental yield") divided by the mass of what should have been produced ("theoretical yield"). Hence‚ the equation will be: Percent yield= experimental yield theoretical yield We will need to substitute the experimental yield and the theoretical yield of copper after we have found out the actual equation. Purpose Since there are
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benzocaine and stabilizes the neuronal membrane which decrease its permeability to sodium ions.1 In this experiment‚ the synthesis of benzocaine is carried out by the acid-catalyzed esterification of 4-aminobenzoic acid with ethanol.2 Theoretical Yield: 1.25g/MW 137 = .009 moles C2H6O 20mL / MW46 =0.435 moles C9H11O2N .009 X 165.19 = 1.49g Purpose Statement: The purpose of this experiment is to synthesize benzocaine by esterification using 4-aminobenzoic acid with ethanol. Experimental
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Chem 201 Lab October 21‚ 2011 Lab #6: Preparation of 2-chloro-2-methylbutane – an Sn 1 Reaction Purpose The purpose of this experiment was to prepare an alkyl halide‚ 2-chloro-2-methylbutane by reacting 2-methyl -2-butanol (t-amyl alcohol) with hydrochloric acid. Alkyl halides are of wide interest because they are widespread and have diverse beneficial and detrimental impacts .The overall reaction is given below: Procedure 1 ml of 2-methyl-2-butanol was measured using 1 ml syringe and
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complete) 1 2 3 4 5 Abstract 1 2 3 4 5 Introduction 1 2 3 4 5 Reaction Scheme and Curly arrow mechanism 2 4 6 8 10 Table 1 2 3 4 5 Experimental Procedure 1 2 3 4 5 Calculation (percentage yield and composition of isolated materials) 1 2 3 4 5 Results and Discussion (include GC) 1 2 3 4 5 Completion/participation of the Experiment 1 2 3 4 5 Total Comments /50
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reactions will occur to yield alum. Calculations: Aluminum foil: 0.5035 grams Alum & Watch Glass: 21.7691 grams Watch Glass: 15.1560 grams Alum: 6.6131 gram Theoretical Yield of Alum: 2Al(s) + 2KOH(aq) + 4H2SO4 + 22H20 -> 3H2(g) + 2KAl(SO4)2 + 12H2O(s) 0.5035gAl x 1molAl/ 26.98gAl = 0.0186 mol Al 0.0168molAl x 2molAl / 2mol KAl(SO4)2 = 0.0186mol KAl(SO4)2 0.0186mol KAl(SO4)2 x 258.2g/ mol KAl(SO4)2 = 4.8 gKAl(SO4)2 Theoretical yield = 4.8g KAl(SO4)2 Percent Yield Alum: 6.6131gKAl(SO4)2
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theoretical yield of your product? Theoretical yield of the CaCO3 is expected to be .69g. B. According to your data table‚ what is the actual yield of the product? The mass of the filter paper was 1.1g‚ and the total mass of the filter paper when dried with the CaCO3 was 1.8 total. Thus the actual yield of the product was .70g. C. What is the percent yield? Percentage yield is actual yield over the theoretical yield x100. Actual yield: .70gTheoretical yield: .69g percentage yield: 101%
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(oxalate)ferrate(III) trihydrate in a two step process‚ to learn new laboratory techniques such as decantation‚ recrystallization‚ gravity and suction filtration. Also the purpose of the experiment is to determine the actual‚ theoretical‚ and percent yields of product‚ and characterize the final compound by determining the number of waters of hydration by gravimetric analysis List of Observations: After adding (15 mL distilled water/5 drops of 3 M H2SO4) to ferrous ammonium sulfate hexahydrate
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