water and add 20 drops of blue dye #1 and stir. Add more drops of blue dye to solution if it is not darker than your commercial dye. (I added an extra 20 to make mine darker) This gave me a concentration of 5.2x10-4. Record concentration Step #2:Place a 12 well strip on a white sheet of paper and number 1-10 starting from the left. Step #3: Using the 1mL fine tip pipet add the appropriate number of drops of blue dye solution to each well. (refer to data table 1 in lab assistant section) Rinse pipet
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big is osmosis‚ and how it had the overall impact in this excitement a little on osmosis. Osmosis takes place when two solutions of different concentrations are separated by a semi-permeable membrane in which the solvent can pass through but not the solute. In our experiment‚ we used a sucrose solution that will be a hypotonic concentration of solute. This tells us that the solution has a lower concentration of water than does the cells. Therefore‚ due to osmosis‚ the cells will gain water weight also
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which consisted of ten drops of fish blood in a test tube containing 10mL of 0.7% NaCl. Eleven other solutions‚ (erythritol‚ xylose‚ monacetin‚ diacetin‚ triacetin‚ urea‚ thiourea‚ glycerol‚ ethylene glycol‚ glucose and fructose) all isosmotic but not necessarily isotonic with the cytoplasm of the erythrocyte‚ were combined with a 0.2mL of well-mixed stock suspension were added to 0.27M of each solution‚ one at a time‚ and timed how long it took for hemolysis to occur with a stop watch. As soon as the
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exactly 3 minutes as instructed in the lab manual (Scott et al‚ 2016) and we tried avoid denaturing the enzyme. The benzoquinone had a greater absorption at acidic pH levels because the acidic solution denatures catechol oxidase‚ causing it to lose its secondary and
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The first solution was tube 1 which was made with 1 mL of EDTA‚ 1 mL of CO‚ and 5 drops of CAT. Tube 2 was made with 1 mL of PTU‚ 1 mL of CO‚ and 5 drops of CAT. Tube 3 was made with 1mL of distilled water‚ 1 mL of CO‚ and 5 drops of CAT. After mixing each solution and putting a piece of Parafilm on Tube 1‚ we set tube 3 as our blank and then measured the change in absorption at 400nm of
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engine. We have to use a liquid that can absorb all that heat. A homogeneous mixture consisting of a solute and a solvent based on colligative properties‚ which means solution’s properties will differ depend on the proportion of solute present. Solutions have both a lower freezing point and a higher boiling point than pure solvent. The more solute is present the bigger the difference between the freezing point and the boiling point. To explain furthermore‚ we need to understand that temperature is
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Exercise June ‘04 The Uptake of Glucose in Yeast Cells Glucose is absorbed across the cell surface membrane (plasma membrane) of most cells. A convenient way to investigate this is to use a solution of glucose and a suspension of yeast cells. The amount of glucose taken up from the glucose solution by yeast cells in a fixed length of time can be measured. At the end of the fixed length of time‚ further uptake of glucose is prevented by transferring the yeast suspension to a boiling water bath
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situation as a company that we could produce solutions for. It was interesting to realize building a case is quite difficult and must be articulated very carefully. Approaching the solutions to the problem at hand was a bump on the road‚ however were clear after a while. I had some trouble really understanding what the assignment was telling me and I found the instructions to be a little vague. I had some issues trying to really grasp what the correct solution was in order to get the best possible outcome
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water. The next step is to get a tool that absorbs the water from the first tube which is the tube with the concentrated bacteria. Aliquot is a measured substance dissolves in another substance.Serial Dilution includes solution ‚ solute‚ and
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1. Determining the concentration of KMnO4 from the solution created by the stockroom. 16H+ + 2MnO4- (aq) + 5C2O42- (aq) → 2Mn2+ (aq) + 10CO2 (g) + 8H2O (l) Volume of potassium manganate (KMnO4) = 32.5 mL Mass of Sodium Oxalate (NaC2O4): 0.104 [KMnO4] Calculation: = (0.104g of NaC2O4)(1 mol NaC2O4 /134.0g)(2 mol KMnO4 / 5 mol NaC2O4)(1/32.5 mL)(1000 mL /1L) = 0.00955 M KMnO4 2. Using the standardized concentration of KMnO4 calculated above to find the mass percentage of the oxalate ion Equation:
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