Grade 11 physics: SPH3U1-01 | Physics Lab Report | Specific Heat Capacity of Brass | | Jin Jin Shi | 2012/12/6 | Instructor: Mr. Nailer | I. Introduction The amount of heat required to raise the temperature of a solid body depends on its change in temperature (ΔT)‚ its mass (m)‚ and an intrinsic characteristic of the material forming the body called specific heat (cp). The heat is calculated from the equation II. Purpose The purpose of this laboratory is to determine
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Physics notes Force is an agent which produces or tends to produce motion in an object‚ stops or tends to stop ‚ motion of an object Newton’s 1st law of motion: If an object is at rest‚ will remain at rest until or unless an external force act on it. If an object is in motion ‚ it continues its motion until or unless an external force act on it Newton’s 1st law of motion is also called first law of inertia. Inertia: The tendency of an object to resist any change in its state of motion
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只限閱卷員參閱 FOR MARKERS’ USE ONLY May 4‚ 2012 香港考試及評核局 HONG KONG EXAMINATIONS AND ASSESSMENT AUTHORITY 2012 年香港中學文憑考試 HONG KONG DIPLOMA OF SECONDARY EDUCATION EXAMINATION 2012 物理 香港中學文憑考試 試卷一乙 PHYSICS HKDSE PAPER 1B 本評卷參考乃考評局專為今年本科考試而編寫，供閱卷員參考 之用。閱卷員在完成閱卷工作後，若將本評卷參考提供其任教 會考班的本科同事參閱，本局不表反對，但須切記，在任何情 況下均不得容許本評卷參考落入學生手中。學生若索閱或求取 此等文件，閱卷員/教師應嚴詞拒絕，因學生極可能將評卷參 考視為標準答案，以致但知硬背死記，活剝生吞。這種落伍的 學習態度，既不符現代教育原則，亦有違考試著重理解能力與 運用技巧之旨。因此，本局籲請各閱卷員/教師通力合作，堅 守上述原則。 This marking scheme has been prepared by the Hong Kong
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all of the views are good. The sport of football is viewed by many as a cruel and primitive sport‚ however every aspect within the sport of football is based in the field of physics. To begin to understand the complexity that is the game of football one can start by looking at how the punter needs to know the laws of physics to kick far. A punter’s job is to execute a drop kick (holding the football out and dropping it‚ then kicking the ball in midair) so as to give the other team the worst field
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Practical Investigation: The Simple Pendulum Background The period of a pendulum is the time for one complete swing. The equation for the period of a pendulum is; Aim To investigate the factors which affect the period of oscillation of a simple pendulum. Equipment -Stand & Clamp -1 Meter Ruler -Pendulum Bob -Nylon
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Investigatory Project in Physics Submitted by : Jay Loteyro Anecito Trongcoso Submitted to: Ms. Matilde Macawile Balloon Powered Car When it comes to powering a race car‚ there are a ton of different options. Some cars are powered by gasoline‚ diesel‚ or other combustible fuels‚ or you can even power miniature race cars using a mousetrap! In the Balloon Powered Car‚ we’ll show you how to build a racer that uses the power of air pressure to roll across a room. Objectives:
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Experiment-5 Thermal physics is the combined study of thermodynamics‚ statistical mechanics‚ and kinetic theory. This practical is done to measure the temperature drop of water over a period of time (30 minutes). Research question- What is the rate of temperature change over a period of 30 minutes? Independent variable- time Dependent variable- the temperature of water Controlled variables- the amount of water in the calorimeter - The stop watch
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Resources for Physics Essay Nikola Tesla "Nikola Tesla | Inventor." Lucidcafé Interactive Café and Information Resource. Web. 18 Apr. 2012. "Nikola Tesla | Inventor." Lucidcafé Interactive Café and Information Resource. Web. 18 Apr. 2012. <http://www.lucidcafe.com/library/96jul/tesla.html>. "Nikola Tesla | Inventor." Lucidcafé Interactive Café and Information Resource. Web. 18 Apr. 2012. <http://www.lucidcafe.com/library/96jul/tesla.html>. Basic information about Nikola’s life and
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What is the potential energy stored in this capacitor when a potential difference 4.0 V is applied between the inner and outer cylinder? (k = 1/4??0 = 8.99 × 109 N ? m2/C2) 2‚236 answers DontAngryMe00 2‚236 answers Top Subjects: Precalculus‚ Physics‚ Chemistry C = 2πεL/ln(r2/r1) (ε= 8.85x10^-12F/m) = [2π(8.85x10^-12)*150]/ln(0.008/0.004) = [2π(8.85x10^-12)*150]/ln2 = 1.2x10^-8 F PE = 0.5CV^2 = 0.5*[1.2x10^-8]*4^2 = 9.6x10^-8 J Energy density (u) = (€oE^2)/2‚
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References: AdU College of Sciences Physics Dept.”College Physics 1”
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