(a) Define the term equilibrium potential and use the Nernst equation (see Appendix) to show how the equilibrium potentials for both sodium and potassium are calculated. Equilibrium potential is the potential of the membrane when there is no net flow of ions from one gradient to the other gradient. The ions are equal and are opposite of each other but not moving from one side to the other. Sodium: Ena=2.303((8.31 J m-1 K-1)(310K))/((1(= 9.65 x 104 c m-1))(log(150/15))= 61.54 mV Ek=2.303((8
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Solving Part A: Center of Mass in One Direction 1. Since the mass of the plate is a uniform‚ the center of mass is in the center of the plate. The plate has diameter d = 28 cm‚ thus the center of mass is 14 cm from the edge of the plate. In the lab‚ two scenarios will be analyzed; 1) when the glass is standing up‚ and 2) when the glass is laying on its side. When the glass is standing up‚ its mass is uniform about the axis of symmetry. Therefore‚ the horizontal center of mass will be at the exact
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Central Philippine University ILOILO CITY‚ PHILIPPINES MATHEMATICS and PHYSICS DEPARTMENT Experiment No.___________________ Name _________________________________________ Course and Year ______________ I. Objective: -To determine and to identify the motion which the metal ball undergoes as it rolls down the acceleration board. II. Materials: Acceleration board‚ cornstarch‚ iron stand‚ clamp with iron bar‚ brass ball‚ PVC pipe‚ meter stick III. Procedure: 1. Using
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Phil Yu Electrostatics Lab Data Chart Part 1: Trial | Material | Material | Charge (+ or -) | q (nC) | 1 | Glass | Fur | + | 3.108 | 2 | Clear Plastic | Fur | + | 45.07 | 3 | Yellow Plastic | Fur | - | 81.57 | 4 | Glass | Silk | + | 1.979 | 5 | Clear Plastic | Silk | + | 19.60 | 6 | Yellow Plastic | Silk | - | 75.49 | 7 | Glass | Green Cloth | + | 2.914 | 8 | Clear Plastic | Green Cloth | + | 31.09 | 9 | Yellow Plastic | Green Cloth | - | 90.30 | Data Chart Part 2:
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Lab 1 – Measurement of Space and Time Anthony Lucci Lab Partner: Amy Hayes Question 4: Both the height and diameter of the cylinder were taken to find the volume; five times for both measurements. Vernier calipers were used to get these measurements by clamping the cylinder between the jaws of the calipers. By looking at the mark of the zero‚ in relation to the main scale‚ the line best lined up with a line from the main scale was taken down. Getting
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CROATICA CHEMICA ACTA CCACAA 78 (1) 99¿103 (2005) ISSN-0011-1643 CCA-2984 Original Scientific Paper Acid Value Determination in Vegetable Oils by Indirect Titration in Aqueous-alcohol Media Elena Kardash* and Yakov I. Tur’yan National Physical Laboratory of Israel (INPL)‚ Givat Ram‚ Jerusalem 91904‚ Israel RECEIVED JANUARY 16‚ 2004; REVISED JULY 21‚ 2004; ACCEPTED OCTOBER 28‚ 2004 Keywords acid value vegetable oils indirect titration A new method of acid value determination in
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Grade 9 Science – Trolley Lab -‐ Luca Weller – AOI: Environment – 17/9/13 D.4 Materials: -‐1 trolley that will be accelerated -‐1 string to connect the trolley and the weights (ca. 2m) -‐1 set of weights that will accelerate the trolley (up to 5N) -‐1 a.m
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Purpose Determine the acceleration in a quick sprint. Question What would the participant’s acceleration be if he/she sprints forward in a positive direction? Hypothesis/Prediction When a person sprints forward‚ it means he/she speeds up. Consequently‚ the acceleration should be positive. When the velocity accelerates at a constant rate‚ the acceleration should remain constant. Therefore‚ if the participant is moving toward a positive direction and the speed increases‚ then the acceleration
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(Be sure to look over all your notes and be sure to know the following things) 1. Define Temperature‚ thermal energy and heat. 2. A 1.00 x 10²g mass of tungsten at 100°C is placed in 2.00 x 10²g of water at 20.0°C. The mixture reaches equilibrium at 21.6°C. Calculate the specific heat of tungsten. Cw = 4180 J/kg°C C= 171 J/kgOC 3. A certain metal has a specific heat of 400 J / kg oC. It absorbs 8000 J of thermal energy which causes its temperature to raise 10oC. How much mass of the
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FRICTION Problem 507 The 2225-N block shown in Fig. P-507 is in contact with 45° incline. The coefficient of static friction is 0.25. Compute the value of the horizontal force P necessary to (a) just start the block up the incline or (b) just prevent motion down the incline. (c) If P = 1780 N‚ what is the amount and direction of the friction force? Solution 507 Part (a) – Force P to just start the block to move up the incline The force P is pushing the block up the incline. The push
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