EXERCISE 1 1. Write the following as full (decimal) numbers in SI units: (a) 286.6 mm‚ (b)85 V (c) 760 mg‚ (d) 60.0 ps‚ (e) 22.5 fm‚ (f) 2.50 GV. 2. A typical adult human lung contains about 300 million tiny cavities called alveoli. Assume that the alveoli are spherical‚ and that the volume of a typical human lung is about 2 liters‚ estimate the average diameter of a single alveolus. 3. Two vectors have length and What are the maximum and minimum magnitudes of their vector sum? 4. is a vector
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QUIZ NO. 2 : RESPIRATORY DISORDERS DIRECTION: Select the best answer by encircling the corresponding letter. 1. The patient is recovering from a left partial lobectomy. Which of the following nursing actions is most likely to result in the positive re-expansion of the affected left lung? a. Positioning the patient in a right side-lying position b. Encouraging the patient to deep breathe and coughing every hour c. Regularly assessing the patient’s ability to inhale and exhale comfortably d.
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Fluid Mechanics 2nd Year Mechanical and Building Services Gerard Nagle Room 387 gerard.nagle@dit.ie Phone Number: 01 402 2904 Office Hours: Wednesday’s‚ 2.00pm to 5.00pm Fluids In every day life‚ we recognise three states of matter‚ Solid‚ Liquids and Gas. Although different in many respects‚ liquids and gases have a common characteristic in which they differ from solids; they are fluids‚ lacking the ability of solids to offer permanent resistance to a deforming force. Fluids flow under the
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Mechanics Adapting to New Found Technology in Automobiles Mechanics are required to learn more as more technology is put into modern automobiles. In the past education was not necessary in order to be able to work on cars‚ but now due to all the technology available in today’s automobiles‚ automobiles have become more complex in structural integrity. The advances of technology make mechanics require more training in order to deal with newer modeled vehicles. According to Jack Trompert at talent-101
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Respiratory complication is one of the common causes of death‚ and my grandfather passed away from aspiration pneumonia couple years ago. Although we inadvertently breath air for granted‚ I observed many patients who had a difficulty breathing like my grandfather while shadowing a physician in ICU. Some of them had a lung surgery‚ while others were able to recover from a minimally invasive procedure using bronchoscopy. Certainly‚ my interest towards this field might change as I encounter new physicians
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Tino Estose WA #4 16 April 2013 Basketball (Mechanics of the game‚ College‚ and Professional) Social Media (Twitter and Facebook)‚ Television‚ Basketball Video Games Factors about the medium | Factors about the message | Factors about the audience | -The most prominent characteristic of at least two of these particular mediums (Twitter and Sports Television) is the delivery of information. These two genres are specifically instant in terms of delivering information or whatever message
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For this phase‚ and the majority of the fight‚ the tank should hold Shiva in the center circle‚ facing her towards the North side of the room. The rest of the raid should loosely stack behind her‚ reacting to her attacks as they come out. Shiva’s main mechanic is what I like to call “Shiva’s Arms”. Shiva has access to three different weapons she can switch between throughout the fight‚ and each type of weapon causes her to use different attacks. The order in which she uses these forms is semirandom
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there is a correlation between age and reading ability. For example‚ the population date may be gathered from several cities and used to determine the growth of a city or state. The future growth will be calculated using the descriptive research. Ex post facto‚ or “after the fact” designs‚ attempt to identify a natural impetus for specific outcomes without actually manipulating the independent variable. This type of design is often utilized when it is not possible to control the experience‚ exposure
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Chapter Objectives To show how to use the method of sections for determining the internal loadings in a member. To introduce the concepts of normal and shear stress. To analyse and design members subject to axial load and direct shear. To define normal and shear strain‚ and show how they can be determined for various types of problems. Copyright © 2011 Pearson Education South Asia Pte Ltd In-Class Activities • • • • • • • • Reading Quiz Applications Normal Stress Shear Stress Normal
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the slope of the f vs. x plot. Problem 1.49 1.49 x=[0‚.3‚.46‚.7‚.75‚1.05‚1.14‚1.36‚1.55]; f=[0:200:1600] p=polyfit(x‚f‚1) xfit=[0:.1:1.5] ffit=polyval(p‚xfit) plot(x‚f‚’o’‚xfit‚ffit)‚xlabel(’x-cm’)‚ylabel(’f-N’) 1600 1400 1200 1000 800 600 400 200 0 -200 f-N 0 0.2 0.4 0.6 0.8 x - cm 1 1.2 1.4 1.6 1.59 x=[0.03:0.03:0.18] f=[45‚102‚165‚245‚360‚512] xs=[-x‚0‚x] fs=[-f‚0‚f] p=polyfit(xs‚fs‚3) (if “0” is included‚ it will wind up being put in 2 times) (makes
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