Investigating the Ratio Between Poly-Vinyl Alcohol and Sodium Borate to form a Bouncing Ball Timothy English Gen. Chem. 1 Lab Section: 009 Introduction: Poly-Vinyl Alcohol (PVA) is a water-soluble synthetic polymer that will be used as one element to form the well know bouncing ball‚ along with Sodium Borate (borax)‚ which has a variety of uses because of its weak base. PVA is ideal for this experiment because it is odorless‚ nontoxic‚ has high tensile strength and flexibility. The
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activity of sodium butyldithiocarbamate pentahydrate‚ C5H20NNaO5S2 Ayodele T. Odularu a‚ Peter A. Ajibade a‚ Bolhuis‚ A. b a. Department of Chemistry‚ University of Fort Hare‚ Private Bag X1314‚ Alice 5700‚ South Africa. b. Department of Pharmacy and Pharmacology‚ University of Bath‚ United Kingdom. Abstract Synthesis of sodium butyldithiocarbamate pentahydrate‚ C5H20NNaO5S2‚ entailed a one-pot synthesis. The process of synthesis involved the use of butyl amine‚ carbon(IV) sulfide and sodium hydroxide
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choice (17 marks) Do NOT Write on this section of the paper. Answer ALL questions in the table provided at the start of Section B Question 1. Which of the following best describes the structure of metals? A lattice of A. alternating positive and negative ions B. positive ions surrounded by freely moving electrons C. molecules held together by covalent bonds D. atoms held together by covalent bonds Question 2. Which of the following is not a property of most metals? A. Malleable
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Sodium From Wikipedia‚ the free encyclopedia This article is about the chemical element. For the PlayStation Home game‚ see Sodium (PlayStation Home). For the racehorse‚ seeSodium (horse). "Natrium" redirects here. For the town in West Virginia‚ see Natrium‚ West Virginia. Sodium 11Na
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Haylee McHale February 3‚ 2013 Organic Chemistry Lab 226 Section 6 Techniques Lab 1. % Recovery= grams recovered compoundgrams crude compound X 100 % Recovery= 0.040 grams0.256 grams X 100 % Recovery= 0.16 x 100=16% There are many reasons why the percent recovery is much less than 100%. For example‚ one source of error may have been that the separatory funnel containing the acidified phenylalanine and ethyl acetate may not have separated well enough after being shaken together in the
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Buffer Post Lab Calculation 1. We added too much NaOH to our buffer 1 solution. The original pH was 5.32‚ with 10mL of buffer and 10mL of DI water. We added 5mL of NaOH and the pH changed to 12.12. If 5 mL changed the pH by about 7‚ then we predict that about 2 mL of NaOH would change the pH by about 2. This prediction is based on the fact that 2.5mL is half of 5mL‚ and 3.5 is half of 7‚ so adding a little less than 2.5mL would give us a difference of about 2. For the buffer 2 solution‚ the original
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Investigating the solubility of Group II hydroxides Jiyeon Kim Aim: To investigate the solubility of Group II hydroxides (Mg(OH)2‚ Ca(OH)2‚ Sr(OH)2‚ Ba(OH)2) Research Question: What is the trend of solubility of Group II hydroxides going down the group as determined through measuring the volume of hydroxides needed to titrate with a known concentration of hydrochloric acid? Background Information: Solubility is when a solute forms a homogeneous solution by dissolving in solvent. The solubility
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Jacob Hernandez October 23‚ 2014 Hima Lahari Marneni CHEM 1411. 114 Post Lab Report 6 Introduction The purpose of this lab is to determine the concentration of HCl when titrated with a standardized NaOH solution‚ through means of the titration method. My hypothesis is When an unknown concentration of HCl is titrated with a known volume of standardized NaOH solution‚ one can gather enough data to determine the concentration of the unknown (HCl). My prediction is If an unknown concentration of HCl
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The moles of sodium thiosulphate can be determined using the average titre values and its concentration. When calculating the average titre values‚ the outliers are ignored because they are mainly created by errors and their great difference from the titres achieved in other trials will pose a great impact to the accuracy of the final result. n=v × c Where ‘n’ is the moles of sodium thiosulphate‚ ‘v’ is the average tire values sodium thiosulphate‚ and ‘c’ is its concentration
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Potassium Hydroxide (KOH) Introduction Potassium hydroxide is an inorganic compound with the formula KOH‚ commonly called caustic potash. Along with sodium hydroxide (NaOH)‚ this colorless solid is a prototypical strong base. It has many industrial and niche applications. Most applications exploit its reactivity toward acids and its corrosive nature. In 2005‚ an estimated 700‚000 to 800‚000 tonnes were produced. Approximately 100 times more NaOH than KOH is produced annually. KOH is noteworthy
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