Electrical Interview questions Electrical interview question: What is electric traction? Answer: Traction means using the electric power for traction system i.e. for railways‚ trams‚ trolleys etc. electric traction means use of the electricity for all these. Now a day‚ magnetic traction is also used for bullet trains. Basically dc motors are used for electric traction systems. Electrical interview question: How can you start-up the 40w tube lite with 230v AC/DC without using any choke/Coil
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The five bases of power are divided into two groups; formal power and personal power‚ and further subdivided into five specific categories under each group. Categories of formal power are coercive power‚ reward power‚ and legitimate power‚ and they come from the authority of one person over another. Categories of personal power are expert power and referent power‚ and they come from one’s characteristics rather than one’s authority. “Coercive power base depends on fear of the negative results from
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Analytical Essay: Power In the United States of America‚ the government follows the structure of a Democracy. Which means there is a president‚ a man who has a large say in whatever decisions are made. Once it’s time for a new man to take in the honor of being president‚ it is up to that person to decide how they want to use their newly granted power. In the novel‚ Lord of the Flies written by William Golding‚ the power shifts back and forth between Jack and Ralph multiple times. Just like every
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Super Thermal Power Project. I am deeply indebted to our training coordinator Sh. Anurag Sinha and Sh.N .K.Singh (DGM ‚HR) and all seniors for giving us all valuable support and information which was instrumental in all stages of our training at Barh STPP. I thank this opportunity to extend our heartfelt thanks to NTPC Ltd. INDEX 1. INTRODUCTION TO BARH STPP 2. KEY DATA 3. BRIEF SYSTEM DESCRIPTION AND GENERAL INFORMATION 4. 400/132 KV switchyard 5. Transformers 6. 11
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1 (POWER SUPPLY) SUBMITTED BY: Michael Vincent Montero Crisdane Dave Caldea Leo Cantomayor Kevin Bocatera Joe Mar Flores 3-BSCpE INTRODUCTION A power supply is a device that supplies electric power to an electrical load. The term is most commonly applied to electric power converters that convert one form of electrical energy to another‚ though it may also refer to devices that convert another form of energy (mechanical‚ chemical‚ solar) to electrical energy. A regulated power supply is
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STUDY OF STG-TRANSFORMERS IN VEMAGIRI POWER GENERATION LIMITED DISSERTATION SUBMITTED TO FACILITATE FULFILMENT OF THE INDUSTRIAL TRAINING SPECIFIED IN THE ACADEMIC CIRRICULUM OF ELECTRICAL AND ELECTRONICS ENGINEERING OF UNDER THE ESTEEMED GUIDANCE OF MR. P. BHOLA SHANKER EXECUTIVE ENGINEER (MECHANICAL) GMR-VPGL‚ VEMAGIRI RAJAHMUNDRY‚ ANDHRA
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Smart Grid Rohit Moghe‚ Student Member‚ IEEE‚ Frank C. Lambert‚ Senior Member‚ IEEE‚ and Deepak Divan‚ Fellow‚ IEEE Abstract—Rapid increase in electric power demand‚ introduction of RPS mandates‚ and a push towards electrification in the transportation sector is expected to increase power system stresses and disturbances. To tackle these power system issues and maintain high system reliability‚ it is essential to have information about the condition of assets present on the grid. Presently‚ due
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1-INTRODUCTION:- The increasing demand of electrical power in cities and industrial centres necessitates the installation of a compact and efficient distribution and transmission network. High voltage gas insulated switchgear (GIS) is ideal for such applications. The range of application of SF₆ Gas Insulated Switchgear extends from voltage ratings of 72.5 kV up to 800 kV with breaking currents of up to 63 kA‚ and in special cases up to 80 kA. Both small transformer substations and large load- centre substations
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encircle your final answer. 1. In a 25-kVA‚ 2000/200 V‚ single phase transformer‚ the iron and full load copper losses are 350 W and 400 W respectively. Calculate the efficiency at unity power factor on a) full load‚ b) half full-load. 2. If P1 and P2 be the iron and copper losses of the transformer on full load‚ find the ratio of p1 and P2 such tat maximum efficiency occurs at 75% full load. 3. A 5-kVA‚ 2300/230 V‚ 50 Hz transformer was tested for the iron losses with normal excitation and copper
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Number of turns per volt = N_T/V =7/A =7/3.75=1.87turns/volts The power Rating for the Inverter transformer (KVA) = 2.0KVA‚ E2= 24V Assuming the efficiency of transformer= 85%: Then Input rating =output/Efficiency= 2000VA/0.85=2353VA …………..equation 17 I_p=P_1/V_P VP = 280V …………..equation 18 I_P=2353/280=8.4A
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