Time =40 z= (40-43)/2.38 = -1.26 Cumulative probability= 0.1038 or ~ 10% The critical activities are B‚ C‚ E‚ F‚ H‚ J and K. The project should be completed (earliest finish) in 43 weeks - therefore R.C. Coleman’s 40 week completion time cannot be achieved. The probability of R.C. Coleman meeting the 40 week deadline is ~10%. This is a low chance‚ so they should be cautioned if they make 40 weeks their deadline. 2. 80% of a probability of ~0.7995 has a z score of 0.84. Thus
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heads 4 times in a row. Let A represent the probability of rolling 4 heads. Therefor the probability of rolling a head four times is . b) There are 16 possible outcomes when tossing a coin 4 times. There are exactly 6 ways of tossing exactly 2 heads: Let A represent the probability of rolling exactly 2 heads. Therefor the probability of rolling exactly 2 heads is c) p’(rolling exactly 2 heads)=1-p(rolling exactly 2 heads) Therefor the probability of not rolling exactly 2 heads is 44.a)
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IEEE TRANSACTIONS ON WIRELESS COMMUNICATIONS‚ VOL. 8‚ NO. 11‚ NOVEMBER 2009 5601 A Comprehensive Analysis of Low-Power Operation for Beacon-Enabled IEEE 802.15.4 Wireless Networks Yu-Kai Huang‚ Student Member‚ IEEE‚ Ai-Chun Pang‚ Senior Member‚ IEEE‚ and Hui-Nien Hung Abstract—ZigBee‚ a unique communication standard designed for low-rate wireless personal area networks‚ has extremely low complexity‚ cost‚ and power consumption for wireless connectivity of inexpensive‚ portable‚ and moving
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10000 Total 1000 5‚970 129520 a. b. c. The probability that a bar containing $50 or $100 bill is purchased is 30 / 1000 = 0.03 Hence customer have to buy 100 bars of soap‚ so that he or she has purchased three bars containing a $50 or $100 bill. d. Given n=1000‚ E(X) = 5.97‚ SD(x) = 9.68912 The probability that a soap contains a bill of $20 or above is 100 / 1000 = 0.0.1 Binomial with n =8‚ p = 0.1 Hence the probability that at least one of these bar contains a bill of $20
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Hicks .5 MULTIPLE CHOICE Find the indicated probability. | 1) The table below describes the smoking habits of a group of asthma sufferers. 1) | | Light | Heavy | | Non-smoker | Smoker | Smoker | Total | Men | 431 | 44 | 41 | 516 | Women | 378 | 37 | 48 | 463 | Total | 809 | 81 | 89 | 979 | If two different people are randomly selected from the 979 subjects‚ find the probability that they are both heavy smokers. A) 0.0001262
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What is the probability that at least two students were born on the same day of the year? For simplify the math‚ without changing the result significantly‚ let’s assume that year is always 365 days long (no February 29 birthdays) and let’s assume that a person has an equal chance of being born on any day of the year‚ although some birthday may be slightly more likely than others. If the students are 366 the probability would be equal to 1. If there is just 1 student the probability would be
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A students is selected at random. What is the probability that his/her score on Exam 2 is over 75? b) Suppose you’re told that a student got a 80 on Exam 1. What is the probability that his/her score on Exam 2 is over 75? c) Suppose you’re told that a student got a 66 on Exam 1. What is the probability that his/her score on Exam 2 is over 75? d) Suppose you’re told that a student got a 70 on Exam 2. What is the probability that his/her score on Exam 1 is over 80? e)
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科目：企業決策 Case: Starting Right Corporation |1. Sue Pansky | |Alternatives |States of Nature | | |Profit or loss in |Profit or loss in | |
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............................. 8 3. Chebyshev’s Rule & The Empirical Rule................................................ 13 4. Introduction to Probability ....................................................................... 15 5. Unions‚ Intersections‚ and Complements ................................................ 23 6. Conditional Probability & Independent Events..................................... 28 7. Discrete Random Variables.......................................................
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completion time is 45.83 days. The expected completion is very close to the realtor’s due date for project completion. Required probability analysis will also be performed that the project will be completed‚ as follows as per the probability analysis Moore Contractors Probability Analysis Assuming that all activities and paths are independent following is the probability calculation. In addition
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