Probability and Statistics Research Project Name: Lakeisha M. Henderson ID: @02181956 Spring 2007 Abstract Table of Contents Principle Component Analysis (PCA) Definition .4 Uses of PCA 5 Illustrative Example of PCA 5 Method to Determine PCA ..6 Basic Analysis of Variance (ANOVA) Purpose and Definition of ANOVA 12 Illustrative Example of ANOVA
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of Hume’s (1748) An Enquiry Concerning Human Understanding. Namely‚ section six‚ Of Probability‚ and‚ section seven‚ Of the Idea of Necessary Connexion‚ focusing on the text’s key points. Hume starts section six by asserting that there is no such thing as chance in the world. Instead‚ it is our ignorance of the causes of events that lead us to believe in chance. Nevertheless‚ Hume posits that there is probability‚ that is‚ a greater chance of something taking place than a contrary. Here‚ Hume uses
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Purpose of Investigation The purpose of this investigation is to find out the general trends of the Olympic gold medal height each time the event is held. It also could be used to predict the next gold medal height in the upcoming Olympic events. We could know as well what functions can be used to plot the graphs. People could also analyze the pattern of rise or decrease in height of the winning height in the Olympic game. This investigation also allows future participants to find out
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exponentially distributed with mean 10 minutes‚ λ = 1/10. What is the probability that a customer will spend more than 15 minutes in the bank? What is the probability that a customer will spend more than 15 minutes in the bank given that he is still in the bank after 10 minutes? Solution: P (X > 15) = e−15λ = e−3/2 = 0.22 P (X > 15|X > 10) = P (X > 5) = e−1/2 = 0.604 2 – Failure rate (hazard rate) function r(t) r(t) = f (t) 1 − F (t) – P (X ∈ (t‚ t + dt)|X > t) = r(t)dt. – For
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True/False Questions 1. The standard deviation of any normal random variable is always equal to one. Answer: False Type: Concept Difficulty: Easy 2. For any normal random variable‚ the probability that the random variable will equal one is always zero. Answer: True Type: Concept Difficulty: Medium 3. The graph of a standard normal random variable is always symmetric. Answer: True Type: Concept Difficulty: Easy 4. The formula will convert any normal
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subject as per your requirement. Project Reports Available Betel Nut (Supari) processing Khaini Chewing Tobacco (Raja Type) Pan Masala Darbari Type Khaine (Chewing Tobacco) Kimam Chewing Tobacco Nicotine from Tobacco Waste Pan Masala Pan Masala‚ Meetha‚ Saada‚ Zarda Making(Gutkha) and Packing Scented Supari Sweet Scented Supari Tobacco Zarda Zafrani Baba type Zarda Kimam N. 60‚ 120‚ 160‚ 240‚ 300‚ 400 Zarda Kimam (Tobacco) Zarda Kimam‚ No. 60‚90 120‚ 160‚ 240‚ 300 & 400 Tobacco
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PROBABILITY QUESTIONS Q1). You draw a card at random from a standard deck of 52 cards. Neither you nor anyone else looked at the card you picked. You keep it face down. Your friend then picks a card at random from a remaining 51 cards. a) What is the probability that your card is ace of spades? 1/52 b) What is the probability that your friend’s card is ace of spades? (Hint: Construct the sample space for what your friend’s card can be.) 1/51 c) You turn over your card and it is 10 of
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model for collaborative filtering. Machine Learning‚ Proceedings of the Twenty-first International Conference (ICML 2004)‚ Banff‚ Alberta‚ Canada Neal‚ R. M. (1993). Probabilistic inference using Markov chain Monte Carlo methods (Technical Report CRG-TR-93-1) Nowlan‚ S. J.‚ & Hinton‚ G. E. (1992). Simplifying neural networks by soft weight-sharing. Neural Computation‚ 4‚ 473–493. Raiko‚ T.‚ Ilin‚ A.‚ & Karhunen‚ J. (2007). Principal component analysis for large scale problems with lots of missing values
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True/False Indicate whether the sentence or statement is true or false. __F__ 1. Two events that are independent cannot be mutually exclusive. __F__ 2. A joint probability can have a value greater than 1. __F__ 3. The intersection of A and Ac is the entire sample space. __T__ 4. If 50 of 250 people contacted make a donation to the city symphony‚ then the relative frequency method assigns a probability of .2 to the outcome of making a donation. __T__ 5. An automobile dealership is
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EXERCISES (Discrete Probability Distribution) EXERCISES (Discrete Probability Distribution) P X x n C x p 1 p x BINOMIAL DISTRIBUTION n x P X x n C x p 1 p x BINOMIAL DISTRIBUTION n x 1. 2. 3. The probability that a certain kind of component will survive a given shock test is ¾. Find the probability that exactly 2 of the next 4 components tested survive. The probability that a log-on to the network is successful is 0.87. Ten users
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