molecular size and mass. When the equations for combustion of these alcohols are listed in the order of increasing number of carbon atoms‚ Methanol 1 CH3OH(l) + 3/2 O2(g) ⋄ 1 CO2(g) + 2 H2O(l) Ethanol 1 C2H5OH(l) + 3 O2(g) ⋄ 2 CO2(g) + 3 H2O(l) Propanol 1 C3H7OH(l) + 9/2 O2(g) ⋄ 3 CO2(g) + 4 H2O(l) Butanol 1 C4H9OH(l) + 6 O2(g) ⋄ 4 CO2(g) + 5 H2O(l) Pentanol 1 C5H11OH(l) + 15/2 O2(g) ⋄ 5 CO2(g) + 6 H2O(l) The number of CO2 molecule increases in a linear fashion‚ as well as H2O. In the formation
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the quantity and concentration of the combustion that is released and how can that be measured in other (more coherent) means? These are the fuels that were seasoned throughout the experiment: * Butanol (C4H10O) * Ethanol (C2H5OH) * Propanol (CH3CH2CH2OH) * Methanol (CH3OH) * Pentanol (C5H11OH) Costs; they’re always a problem or a benefit. And when they are a problem‚ they must be dealt with accordingly. Fuel is a common problem associated with money‚ and unfortunately‚ it is
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Other Important Topics in Column Design Outline Sub-Flowsheets Thermodynamic model (Fluid Package) selection Solver selection Sub-flowsheets HYSYS has a multi-flowsheet architecture. A big flowsheet can be split up into smaller sub-flowsheets. Each sub-flowsheet has its own streams‚ operations‚ PFD and an independent fluid package. The column in HYSYS is a sub-flowsheet where independent operations are possible H83 PS1/H84 CFL Templates A template
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Organic Chemistry II Laboratory (ABCT357) Although studying fundamental theories of chemistry in the class is important to understand the concept of chemistry‚ carrying out experiments to corroborate the theories is also important. It is very important for students to get used to experiments in order to speed up their experiments. Expt.1. Acetylation of α-D-glucopyranose Add slowly 2.5 g (0.014 mol) of powdered D-glucose in small portions (roughly in 7-10 portions and 5 min for each addition)
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CHEM 104: General Chemistry II Spring 2014 Exam 1 Version A Instructions: 1. Do NOT open this exam until you are told to do so. Opening the exam before the start of the exam is considered an act of Academic Dishonesty. 2. All answers must be bubbled into the scantron answer sheet. 3. No credit will be given for answers written on this exam. 4. You must use a #2 pencil to bubble in the answers on your scantron. 5. This is a multiple choice exam consisting of 30 questions (7 pages). Each question
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Unit 2 Lesson 5 16. a) 1‚2‚5 trimethylhexane b) 3 ethyl 2‚4‚6‚7 tetramethyloctane c) 2‚2 dimethylpentane 17. a) b) c) 18. C7H16 (l) + 11O2 (g) ---------> 7CO2 (g) + 8H2O Heptane + oxygen carbon dioxide + water * Takes 11 molecules of oxygen and 1 molecule of heptane to make 7 molecules of carbon dioxide and 8 molecules of water 19. a) A reason for this trend is that oil deposits were being found all around the world during the time period between 1910 and 2000
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proper number of sig figs. 1 Exercise 5.5b pg 201 Given The vapour pressure of 2-propanol (Mw‚p = 60.1 g/ mol) is 50.00 kPa at 338.8◦ C‚ but it fell to 49.62 kPa when mu = 8.69 g of an involatile organic compound was dissolved in mp = 250 g of 2-propanol. In terms of given variables‚ this is written: Mw‚p = 60.1 g/ mol T = 338.8◦ C p∗ = 50.0 kPa p pp = 49.62 kPa Pressure of pure 2-propanol solvent Pressure of solution containing unknown mu = 8.69 g mp = 250 g Find Calculate
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This affects the intermolecular attractions because the more polar a molecule is the stronger its attraction to other polar molecules will be. The next two alcohols were ethanol and propanol which followed the predicted pattern at 13.2 ºC and 5.3 ºC respectively. Butanol had the smallest change in temperature‚ 2.5 ºC which indicates much less evaporation. This leads to believe that butanol has the strongest intermolecular forces of the
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Properties of Alcohols and Phenols Experiment #3 Objectives: To observe the solubility of alcohols relative to their chemical structure‚ to perform chemical tests to distinguish primary‚ secondary and tertiary alcohols‚ and a color test for phenol. Introduction The general formula of an alcohol is ROH in which the R is an aliphatic hydrocarbon group. Alcohols may be looked upon as derivatives of water‚ HOH. One hydrogen of water is substituted by an alkyl group‚ R. Like water‚ alcohols show hydrogen
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SYNTHESIS OF TRANS-9-(2-PHENYLETHENYL) ANTHRACENE (A WITTIG REACTION) Introduction: The purpose of this experiment is to convert carbonyl compounds to alkenes using Wittig reaction. In this case we will be synthesizing Trans-9-(2-phenylethenyl) anthracene from benzyltriphenylphosphonium chloride and 9-anthraldehyde. We will also aim to obtaining a high percent yield and purity for the synthesis of Trans-9-(2-phenylethenyl) anthracene. The mechanism for this reaction goes thus:
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