Area of a parallelogram-__________ Area of a trapezoid-__________ Area of a circle-__________ Area of a triangle-__________ 1.) (Parallelogram) Find height when base is 7ft and area is 56ft squared. 2.)(Parallelogram) Find base when h=12 and A=216in squared. 3.)(Triangle) Find base when h=9ft and A=35ft squared. 4.)(Trapezoid) Find height when A=25m squared‚ b1=3m‚ and b2=7m. 5.)(Circle) Find radius when A=314ft squared. (Round to the nearest whole number). 6.) Base=12ft Height=12ft
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by (∏ x 3 squared) Height = 6.01 round of to 6cm Allowing 1 extra cm for room Top and bottom of cylinder = 6cm + 1cm = 7cm Height= 6cm + 1cm = 7cm Total surface Area= area of base + area of top + Area of circle = (∏r squared) + (∏r squared) +( ∏ x Diameter x height) = (∏ x 3.5 squared) +(∏ x 3.5 squared) +(∏ x7x7) = 230.90cm cubed 1b The net of package
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rate on different surface areas‚ depending on different types of water solution An investigation showing the effect of surface area on osmosis rate‚ including some different types of water concentration. Osmosis is a type of passive (not requiring energy) transport of water molecules across partially permeable membrane‚ from an area of high water concentration into area of low water concentration. But how does surface area affect rate of osmosis? Surface area plays important role in osmosis
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least have to pick r and h such that pi r^2 h = 355. That means h = 355 / (pi r^2). The surface area of a cylinder is the top (pi r^2) plus the bottom (also pi r^2) times the lateral side (2 pi r h). So the total surface area is 2 pi r^2 + 2 pi r^2 + 2pi r h‚ or 4 pi r^2 + 2 pi r h. Substitute h = 355 / (pi r^2) into this to get the surface area in terms of just r. Now that you have the surface area in terms of just r‚ you can find the value of r that minimizes this by taking the derivative‚ stetting
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Sample Question Paper 349 Sample Question Paper Mathematics (211) Time : 3 Hours Maximum Marks : 100 Note : 1. Question Numbers (1–16) are Multiple Choice Questions. Each question carries one mark. For each question‚ four alternative choices are given‚ of which only one is correct. You have to select the correct alternative and indicate it in the box provided against each question by writing A‚ B‚ C or D as the case may be. 2. Question Numbers (17–26) carry 3 marks each. 3. Question
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red pigment from a beetroot cell and the surface area. To do this successfully I will need to alter the surface area of the beetroot cells accurately and then measure if any and how much dye is let out. I can hopefully then look at my results and then find a relationship between the two factors and be able to explain exactly why any changes took place. PREDICTION For this experiment I would expect the leakage of dye to increase as the surface area increases and this is based on the knowledge of
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investigate the effect of the surface area to volume ratio on the rate evaporation of water in different sized containers. By measuring the time it takes for the whole amount of water to evaporate‚ a conclusion can be made about the validity of the surface to volume ratio in regards to the biological process of diffusion. Research Question: What is the effect of the surface area to volume ratio on the evaporation of water? Variables: - Independent: o Surface area in cm2 of the top most surface of
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and comparative analysis of place characteristics‚ along with the quantitative and visualized analysis of child behavior‚ the relationship between these two aspects was determined‚ and the effect of spatial elements in the selected residential areas on such a relationship was clarified. Additionally‚ the designing of a comprehensive landscape space that satisfies children’s needs was also discussed. The conclusions are as follows: (1) Waterside is the element that most significantly affects child
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=1; for a non-spherical particle‚ the sphericity is defined as Dp: equivalent diameter of particle Sp: surface area of one particle vp: volume of one particle The equivalent diameter is sometimes defined as the diameter of a sphere of equal volume. For fine particles‚ Dp is usually taken to be the nominal size based on screen analysis or microscopic analysis. The surface area is found from adsorption measurements or from the pressure drop in a bed of particles. For many crushed materials
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the only body‚ no matter how small‚ of water on campus. The lagoon dissects a vast expanse of land where several glades can be found. The area thus serves as a botanical reserve planted to narra‚ banaba‚ kapok‚ mahogany‚ royal‚ rubber‚ acacia and mango trees‚ and bamboo‚ among others. There was a time when flocks of sheep and other wildlife would graze the area lending it a most pastoral scene on a lazy afternoon on campus. The lagoon itself is more than a meter deep. It was once home to different
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