strong evidence that the gambler’s claim is true? a. Specify the null and alternative hypothesis for this problem. p = probability gambler guess correctly for an individual roll null (Ho): p = 1/6 alternative (Ha): p > 1/6 b. Find the test statistic and calculate the p-value. What do you conclude? pˆ = 0.2 so z = (0.2-0.1667)/ .1667(.8333) /100 = 0.894. From the table the p-value is between 18% and 19%. The null hypothesis is a reasonable explanation of this data so we do not have strong evidence
Premium Normal distribution Statistical hypothesis testing Statistics
Introduction to Personality Student PSY 405 Date Professor Introduction to Personality Personality Defined Personality is difficult to describe‚ but nearly impossible to define in a universally acceptable way. Throughout history many definitions of personality have been proposed but none universally accepted. This is because of the reality that each individual’s definition comes with a unique spin placed upon it by that individual’s life experience‚ surroundings‚ and personal viewpoint.
Premium Psychology Personality psychology Person
there are approximately 126‚000 abortions conducted each day throughout the world. This website includes the abortion statistics of the world and breaks the data down to the demographics of the United States. It also discusses the decisions to have an abortion and the use of contraceptives in the United States. This was an informative website and included detailed statistics conducted by the Alan Guttmacher Institute. According to the website http://www.bls.gov/cps in 2000‚ gon average there
Premium Statistical hypothesis testing Unemployment Demographics
for a year ( 12 months). We calculate the variance for both and define the “degrees of freedom’ (n-1= 11) and then we can build the F-distribution. F statistic (): Defined as the ratio of the dispersions of the two distributions‚ in other words it is the value calculated by the ratio of two sample variances . F always >=1. The F statistic can test the null hypothesis: (1) that the two sample variances are from normal populations with a common variance; (2) that two population means are equal;
Premium Normal distribution Student's t-test
G036 * Yes because the p-value is less than 0.05 or No‚ because the p-value is greater than 0.05 * The coefficient of variation is the standard deviation of a data set‚ divided by the mean of the same data set. * Z score = x -ms * The Independent part is what you‚ the experimenter‚ changes or enacts in order to do your experiment. The dependent variable is what changes when the independent variable changes - the dependent variable depends on the outcome of the independent variable
Premium Normal distribution Statistics Student's t-test
Statistics is defined by Bennett‚ Briggs‚ & Triola (2009)‚ as “the science of collecting‚ organizing‚ and interpreting data” (p. 1). Almost every profession uses statistics in some way to guide in making good decisions based on current research. The nursing profession relies heavily on current research to guide patient care with the integration of evidenced-based practice. Statistics provide valuable information to caregivers to help them understand‚ plan‚ evaluate‚ and improve the quality of patient
Premium Patient Health care Health care provider
QNT351~WK5 Individual Assignment: Real Estate Data DUE SUNDAY‚ MAY 21st Resources: Appendix A1 at the end of Basic Statistics for Business and Economics (See attached Chapters 10 & 13 to answer questions below) QUESTION #1: Answer question 58 in the Data Set Exercises from Ch. 10 of Basic Statistics for Business and Economics. Exercise #58: Refer to the Real Estate data‚ which report information on homes sold in Phoenix‚ Arizona‚ last year. a. A recent article in The Arizona
Premium Real estate Real property Property
A. What is the mean age of this sample? What is the standard deviation? The mean age is 47.5 years old. The standard deviation is 10.74832 years. http://www.calculator.net/standard-deviation-calculator.html Sample Standard Deviation‚ s: 10.748316881702 Sample Standard Variance‚ s2 115.52631578947 Total Numbers‚ N 20 Sum: 950 Mean (Average): 47.5 Population Standard Deviation‚ σ 10.476163419878 Population Standard Variance‚ σ2 109.75 If it follows the normal distribution The
Premium Standard deviation Arithmetic mean Statistics
Descriptive Statistics Carlos Duran QNT/561 April 28‚ 2015 Steven Marantz Descriptive Statistics Sales (in USD) Central Tendency: Mean = 42.824 dollars Dispersion: Standard Deviation = 9.073 dollars Number: 100 Min/Max: MIN IS $23.00; MAX IS $64.00 Confidence Interval: $1.06 to $44.62 The histogram is present in appendix A; the descriptive statistics are present in appendix B. Age Distribution: State if not normally distributed Central Tendency: Median = 35 years Dispersion:
Premium Standard deviation Normal distribution Median
Nutritional support in Amyotrophic Lateral Sclerosis ABSTRACT: Aim: This review aimed to discuss the nutritional assessments and the perceived benefits of available enteral nutrition interventions in terms of nutritional status‚ survival‚ safety and complications in ALS patients. Findings: Nutritional assessments for ALS patients involve the diagnosis of malnutrition‚ bulbar dysfunction and respiratory impairment. There are no guidelines about the indication and formulation for enteral nutrition
Premium Amyotrophic lateral sclerosis Body mass index Obesity