Contribution of Dominant Family values were 18.12 ± 8.01 above‚ 18.87 ± 4.55 at‚ and 18.92 ± 8.29 below (Figure 11) Figure 1 Mean and Standard Deviation of Water Temperature at Pricket’s Creek Marion County‚ WV Fall 2012 Figure 2 Mean and Standard Deviation dissolved oxygen content at Pricket’s Creek Marion Conuty‚ WV Fall 2012 Figure 3 Mean and Standard Deviation pH Pricket’s Creek Marion County‚ WV Fall 2012 Figure 4 Mean and
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Ordering cost = $20 per order gaskets Turning to R‚ the Normal Distribution appendix shows that a 95% cycle-service level corresponds to a z = 1.65. We then use the EG151 data to find the standard deviation of demand. Standard deviation in weekly demand () = 2.86 gaskets Standard deviation in demand during lead time R = Average demand during the lead time + Safety stock = 2(102) + 1.65(4.04) = 210.66‚ or 211 gaskets b. Cost comparison After developing their plan‚ students can compare its
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125 150 72 97 113 138 121 146 165 190 118 143 88 113 79 104 96 121 (a) Find the mean‚ median‚ standard deviation‚ first and third quartiles‚ and the 95th percentile for family incomes in both years. For 1980: mean: 62.7‚ median: 59‚ sd: 39.7‚ 1st quartile: 29.25‚ 3rd quartile: 93.5‚ 95th percentile: 132.2 For 1990: mean: 67.12‚ median: 57.5‚ sd: 48.09‚ 1st quartile: 57.5‚ 3rd quartile: 98.25‚ 95th percentile: 157.2 (b) It seems that the country was better off in 1990 than in 1980‚ because
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| 850 | 11.64 | | | Recreation | 1200 | 16.44 | | | Others | 1180 | 16.16 | Total | 7300 | 100 | Table 1 PIE CHART BAR CHART LINE GRAPH COMMENTS/SUMMARY (PART A) i. Determining the mean and standard deviation The mean and standard deviation of allocation of income cannot be determined;
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extent to which the observations are scattered. Objectives: * To use summary statistics to describe collection of data. * To use the mean‚ median and mode to describe how data “bunch up” * To use the range‚ variance and standard deviation to describe how data “spread out”. MEASURES OF CENTRL TENDENCY Measures of central tendency include three important tools – mean (average)‚ median and mode. Mean The arithmetic mean is the most common measure of central tendency. For a data set
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ASSIGNMENT 1- BU1007 Question 1 (i) The following data represent the cost of electricity during July 2006 for a random sample of 50 one-bedroom apartment in a large city Electricity Charge ($) | 96 | 157 | 141 | 95 | 108 | 171 | 185 | 149 | 163 | 119 | 202 | 90 | 206 | 150 | 183 | 178 | 116 | 175 | 154 | 151 | 147 | 172 | 123 | 130 | 114 | 102 | 111 | 128 | 143 | 135 | 153 | 148 | 144 | 187 | 191 | 197 | 213 | 168 | 166 | 137 | 127 | 130 | 109 | 139 | 129 | 82 | 165
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7% Expected Return 41.3% Expected standard deviation 21.4% Sharpe Ratio 1.60 1. Then we try the following actions and try to understand their consequences: a. Suppose that GM has decided to become a diversified conglomerate‚ much like GE‚ so that its correlation with GE will be 0.80 instead of 0.26. Weighting GM -61.4% MRK 21.1% GE 140.2% 100.0% Risk-free rate 5% Expected Return 53.2% Expected standard deviation 23.6% Sharpe Ratio 1.96 The weight of
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This is file Q8IM13D - The fourth of five files for solutions to this chapter. 23. The sample means and standard deviations gathered in a calibration project by the Weighrite Corporation were observed for sample sizes of 10‚ as show in worksheet Prob. 13-23. Construct - and s-charts and discuss the results. Answer 23. See data and control charts below and spreadsheet Prob.13-23XSWeigh.xls for details. For the Weighrite Corporation‚ the center line‚ CL: = 8.659; CLs : = 7.474 a. Control limits
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two very different conclusions from the same set of data. 2. Quantitative & Categorical Data – Two different types of data. 3. Categorical Graphs – Bar graphs & pie charts. 4. “Center” & “Spread” for Quantitative Data – Mean‚ median‚ standard deviation‚ etc. 5. Quantitative Graphs – DotPlots‚ StemPlots‚ Histograms‚ BoxPlots‚ Ogives. 6. Describing Quantitative Graphs – Shape‚ center‚ spread‚ symmetric vs. skewed‚ etc. 7. Comparative Plots – Graphs comparing two sets of data. 8. Reasoning – Propose
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Question 1: To compute the standard deviation‚ it is used the EXCEL STDEV ( ) Function and the expected return is equal to the sum of return rates in 24 months divided by 24. Stock | Vanguard 500 | California REIT | Brown Group | Standard Deviation | 4.61% | 9.23% | 8.17% | Expected Return | 1.10% | -2.27% | -0.67% | Question 2: To compute the standard deviation in a portfolio‚ it follows the formula SD= ( ) 1/2
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