Hydrogen peroxide and iodide ions Aim: To determine the rate equation for the reaction between Hydrogen peroxide and iodide ions‚ and to investigate the effects of a catalyst and temperatures on the reaction and to derive the activation enthalpy. Background knowledge: 1Hydrogen peroxide reacts with iodide ions producing iodine‚ when in an aqueous acid solution. H2O2 (aq) + 2I- (aq) + 2H3O+(aq) I2 (aq) + 2H2O(l) To detect iodine you can look at the color shown by the addition of starch
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find the rate equation of the reaction of hydrogen peroxide and iodide ions. This will be achieved by using an iodine clock method and colorimetric analysis. 2. Draw a graph of rate against concentration for each reactant (Hydrogen peroxide‚ potassium iodide and H+ ions). 3. Finding the order for each reactant 4. Finding the rate-determining step. 5. Proposing a mechanism for the reaction. 6. Using Arrhenius’ equation to find the activation enthalpy. Background The basic reaction for this
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Reaction of catalase with hydrogen peroxide AIM: I aim to find the rate of reaction between catalase and hydrogen peroxide. Enzymes such as Catalase are protein molecules that are found in living cells. They are used to speed up specific reactions in the cells. Each enzyme just performs one particular reaction so they are all very specific. Catalase enzymes found in living cells e.g. in yeast‚ potato or liver‚ speed up (in our case) the breaking down of hydrogen peroxide. The lock and key analogy…
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An investigation to compare the reaction rates between potato and hydrogen peroxide against liver and hydrogen peroxide through loss in mass. Background information: Catalase is an enzyme that is found in all cells. This means that it is an intracellular enzyme. And enzyme is a biological catalyst. A catalyst is some thing that speeds up a reaction without being changed itself. Because of this enzymes and catalysts can be used again and again. Enzymes are protein chains that have a primary‚ secondary
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Hydrogen Peroxide & Inorganic Peroxy Compounds Hydrogen Peroxide Hydrogen peroxide (H2O2) is the simplest peroxide (a compound with an oxygen-oxygen single bond). It is also a strong oxidizer. Hydrogen peroxide is a clear liquid‚ slightly more viscous than water. In dilute solution‚ it appears colorless. Reactions Decomposition Hydrogen peroxide decomposes exothermically into water and oxygen gas spontaneously: 2 H2O2 → 2 H2O + O2 This process is thermodynamically favorable. It has
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Kinetics of Hydrogen Peroxide February 22‚ 2007 Chem. 1130 TA: Ms. Babcock Room 1830 Chemistry Annex PURPOSE OF THE EXPERIMENT Kinetics of Hydrogen Peroxide The major purpose of this experiment is to determine the rate law constant for the reaction of hydrogen peroxide and potassium iodide. In this experiment‚ the goal will be to try to measure the rate law constant at low acidity‚ since at low acidity‚ anything less than 1.0 x 10-3M‚ the effect of the hydrogen ion is negligible. To calculate
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An Investigation on the rate of reaction of the enzyme Catalase on the substrate Hydrogen peroxide. Plan Aim: To investigate the rate of the effect of Catalase on hydrogen peroxide. Introduction This investigation will be carried out to investigate the rate of reaction of the enzyme catalase on the substrate hydrogen peroxide. Enzymes are biological catalysts‚ which speed up the rate of reaction without being used up during the reaction‚ which take place in living organisms. They do this by
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Investigating Factors that Affect the Rate of Reaction of the Decomposition of Hydrogen Peroxide Emilio Lanza Introduction- In this experiment‚ the rate of reaction‚ calculated in kPa sec-1‚ of the decomposition of hydrogen peroxide will be investigated to see how the change in concentration of hydrogen peroxide and the change in temperature affect the rate of reaction. The data will be collected by measuring the gas pressure. The product of Hydrogen Peroxide is oxygen in a gas state thus it is
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Abstract The aim of this study was to test the rate of reactivity of the enzyme catalase on hydrogen peroxide while subject to different concentrations of an inhibitor. The hypothesis was that hydrogen peroxide will be broken down by catalase into hydrogen and oxygen‚ where a higher concentration of inhibitor will yield less oxygen‚ resultant of a lower rate of reaction. Crushed potato samples of equal weight were placed in hydrogen peroxide solutions of various temperatures. The results showed
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The purpose of this experiment was to determine the speed at which a reaction took place between an iodine and hydrogen peroxide solution. In addition to a change in concentration‚ a change in temperature and a catalyst variable was also introduced to conclude whether or not their presence affected the overall speed of the reaction. In order to determine the effects of these variables‚ several iodine and hydrogen peroxide reactions were prepared‚ (all at varying temperatures‚ volumes‚ and concentrations)
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