Chemistry Coursework Rates of Reaction Investigation Introduction In this investigation I am going to be investigating the reaction between marble chips and hydrochloric acid‚ and to see what differences in the rate of this reaction arise when different concentrations of acid are used. Below is the word equation for this reaction: Calcium Carbonate + Hydrochloric Acid = Calcium Chloride + Carbon Dioxide + Water Below is the fully balanced chemical equation for this reaction. CaCo3 + HCl
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Chemistry F332 Notes Ions in solids and solutions: Structure of an ionic lattice (Sodium Chloride): * Consists of sodium ions (Na+) surrounded by six chloride ions (Cl-) * Chloride ions also surrounded by six sodium ions. * Held together by attraction of oppositely charged ions. * Giant ionic lattice. * Electrostatic bonds hold lattices together. * Structure is simple cubic. * Some ionic crystals contain water. * Known as water of crystallisation. * These crystals
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Purpose: To determine the effect of various factors on the rate of reaction between an enzyme andits substrate‚ and also to determine the optimal ranges under which the enzyme activity ismaximized. Also to determine whether saline and alcohol are inhibitors or activators Hypothesis: PH factor prediction: I predict that as the pH increases so the activity of the enzyme willincrease until it reaches optimum pH range (pH 7) because the enzyme is less denaturedwhen it reaches the preferred pH level
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determine the rate law of chemical reactions Introduction: The aqueous solution of potassium peroxydisulphate can oxidize potassium iodide as follow: Equation: K S 0 (aq) + 2KI (aq)->2K S0 (aq)+I (aq) 2 2 8 2 4 2 KI(aq) +I (aq) -> KI (aq) 2 3 _________________________________________________ K S 0 (aq) +3KI(aq) -> 2K S0 (aq)+ KI (aq) 2 2 8 2 4 2 The rate law of this reaction can be represented as follow: Rate=k[S208 2-]^a [I-]^b When the concentration of peroxydisulphate ions is fixed‚ the
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Hypothesis: I hypothesis that the enzyme concentration will affect the rate of reaction but only up until a certain point because there is a limited supply of substrate. Enzymes are protein molecule that acts as biological catalyst by increasing the rate of reactions without changing the overall process. They are long chain amino acids bound together by peptide bonds. Enzymes are seen in all living cells and controlling the metabolic processes in which they converted nutrients into energy and new
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Demonstration of the Rates of Reaction Between Sulphuric Acid (25mL ±0.5mL) and Magnesium (0.02g ±0.01g) Changing Due to Different Surface Areas By Chania Baldwin Introduction: When sulphuric acid and magnesium are added together‚ magnesium sulphate and hydrogen gas is created. To create such a reaction the atoms must collide with a sufficient amount of energy. Every reaction requires a different amount of energy to create the reaction‚ which is called the activation energy; when there is not enough
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table List of Polyatomic Ions that Must be Memorized for General Chemistry Polyatomic Cation: NH4+ ammonium ion Polyatomic Anions Ionic Charge: Oxyanions: ClO4– perchlorate ion ClO3– chlorate ion – ClO2 chlorite ion ClO– hypochlorite ion -1 Ionic Charge: Oxyanions that Contain Hydrogen: HCO3– bicarbonate ion or hydrogen carbonate ion HSO4– bisulfate ion or hydrogen sulfate ion NO3– NO2– nitrate ion nitrite ion MnO4– permanganate ion H2PO4– Others: CN–
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In my coursework I will investigate about enzymes in potatoes reacting with Hydrogen Peroxide. In particular I will investigate the effects of changing the surface area of a potato when added to Hydrogen Peroxide. This is because‚ when increasing the surface area of the potatoes it will increase the rate of reaction because there will be more surface area on which particles from the potato and the Hydrogen Peroxide will collide on‚ and with more surface area there would be more particles carrying
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How different concentrations of hydrogen peroxide would affect the activity of catalase? 1. Variables Independent Concentration of hydrogen peroxide Dependent Volume of oxygen gas evolved Control Amount of liver used Location of liver sample obtained from the liver Type of liver used Possible enzymes transferred from hands during making liver homogenate Deterioration of liver Endpoint identification Volume of hydrogen peroxide added Reading on the syringe Room temperature
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Peroxodisulphate and Iodide practical – exemplar Skill A – Chemical Ideas Reaction between Peroxodisulphate and Iodide The reaction between peroxodisulphate and iodide ions is given by the following equation: S2O¬82- (aq) + 2 I- (aq) 2 SO42- (aq) + I2 (aq) The structure of the peroxodisulphate ion‚ with oxidation states‚ is shown below: (Structure) The changes in oxidation state within the reaction are as follows: Element Oxidation state in reactant Oxidation state in product Oxidised or
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