"Reaction of lead oxide with hydrochloric acid" Essays and Research Papers

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    between the surface area and rate of reaction to be realised. That is‚ that the greater the surface

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    (Fe3+ ) form. Ferric form is not usually absorbed in the body. In the stomach‚ there is low pH of 2 due to presence of gastric acids such as Hydrochloric and Ascorbic acids. These acids provide an acidic environment for reduction of ferric iron to ferrous (Fe2+). Ferrous iron can be absorbed in the body system. As in following equation of iron (iii) reaction with Ascorbic acid ‚ the product is iron (ii) chloride which is soluble 2 Fe3+ (s) + C6 H8 O6 (aq) → 2 Fe2+ (aq) + C6 H6 O6 (aq) + 2 H (aq)+

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    investigation to show how the rate of reaction between hydrochloric acid and sodium thiosulphate is affected by the concentration of the acid Simple Procedure Place a conical flask on a piece of paper with a cross on it. Add hydrochloric acid and sodium thiosulphate‚ and record the amount of time taken for the cross to disappear through the solution from the top of the flask. Record this time and repeat this for different concentrations of hydrochloric acid. Fair Test The variables in this

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    Rate of Reaction Experiment Introduction : in this term in chemistry class I was learning about rate of reaction. As defined by the Britannica encyclopedia‚ a chemical reaction is a process where one or more substances (reactants) are converted to one or more different products because of the rearrangement of atoms of the reactants. For the reaction to occur‚ the particles must collide with each other and in order to succeed there must be enough energy for the collision because a collision with little

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    STANDARDISATION OF HYDROCHLORIC ACID REPORT Aim: To standardize an unknown solution of hydrochloric acid Method: See INSTRUCTIONS for practical 6.2 & 6.3 Results: Attempt No. | Titre (mL) | | 1 | 20.9 | Rough Titration | 2 | 20.5 | | 3 | 20.7 | Concordant Titres | 4 | 20.7 | | 5 | 20.7 | | (1) Tabled Results (2) Concordant Titrations Results 20.7 mL | 20.7 mL | 20.7 mL | Average of Concordant: (20.7 + 20.7 +20.7) 3= 20.7 mL Calculations:

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    Investigating The Rate Of Reaction Between Marble Chips And Hydrochloric Acid Planning I will use marble chips and different concentrations of hydrochloric acid and water to see how it affects the rate of reaction. I will use concentrations of 50cm3 using different volumes of water and acid. Introduction I am investigating how the rate of reaction between marble chips and hydrochloric acid is altered when the concentration is changed. This is the word equation for my investigation

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    the rate of reaction between Calcium Carbonate and Hydrochloric Acid. Just from looking at the aim of the investigation I already know that a salt would be formed because a carbonate with an acid forms a salt. In this investigation the substance that is formed is Calcium Chloride‚ Water and Carbon Dioxide. The symbol equation for this is: CaCo3  Ca2+ + Co32- Hcl  H+ + Cl- Add these all together to get CaCO3(s) + 2H+(aq) --> Ca++(aq) + H2O + CO2(g) The rate of reaction is just the

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    solution on the rate of the reaction when reacting with dilute hydrochloric acid. It is hypothesized that as the concentration of the sodium thiosulfate solution increases‚ the rate of the reaction will also increase proportionately. Variables The independent variable is concentration. This will be varied by increments of 10mL (10mL to 50mL) and distilled water will be added accordingly to maintain a constant volume of 50mL. The dependent variable is the rate of the reaction. This will be indirectly

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    goal by creating five reactions containing Sodium Sulfate that would confirm our compound and show its chemical properties. In each reaction‚ we replaced the presence of Sodium Sulfate with our unknown. Our first reaction was the reaction from the sulfate anion test between Sodium Sulfate and Barium Chloride. If the compound was in fact Sodium Sulfate it would produce a white precipitate and it did. The second reaction was first between Sodium Sulfate and Hydrochloric Acid‚ and then Silver Nitrate

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    and is a strong acid. Where comparing to the conductivity of distilled water to HCL would be evidently HCL. This is because distilled water doesn’t contain ions‚ hence no movement of electrons‚ furthermore no conductivity. However since we added sodium chloride‚ distilled water will have some conductivity but no where near the amount of HCL. Comparing to the conductivity of vinegar to HCL mostly relays on how acidic each other are. Since HCL is a strong acid and vinegar is a weak acid‚ this will impact

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