[pic] Drops |Water(HcL) |Water(NaOH) |Liver(HcL) |Liver(NaOH) |Egg White(HcL) |Egg White(NaOH0) |Potato(HCl) |Potato(NaOH) |Buffer(HCl) |Buffer(NaOH) | |0 |7 |4 |7.4 |5 |8.2 |7 |6.9 |4 |10.7 |10 | |5 |4.5 |7 |6.9 |6 |7.5 |8 |6.2 |5 |10.5 |10 | |10 |2.7 |9 |6.3 |6 |7 |9 |5.7 |5 |10.4 |11 | |15 |2.6 |12 |5.8 |6 |6.4 |9 |5.3 |6 |10.3 |12 | |20 |2.5 |12 |5.4 |6 |4.5 |10 |4.9 |7 |10.2 |12 | |25 |2.4 |13 |5.1 |6 |3.5 |10 |4.6 |8 |10.1 |13 | |30 |2.3 |13 |4.8 |6 |3.3 |11 |4.2 |8 |10 |13 | | 1.
Free PH Acid dissociation constant
Thymol Blue REAGENT ADDED STRESS (ION ADDED) COLOR OBSERVATION DIRECTION OF EQUILIBRIUM SHIFT HCl (Step 3) HCl (Step 4) NaOH (Step 5) NaOH (Step 6) Table 2 Equilibrium Involving Thiocyanatoiron (III) Ion REAGENT ADDED STRESS (ION ADDED) OBERSERVATION DIRECRTION OF EQUILIBRIUM SHIFT KCl (test tube B) Fe(NO3)3 (test tube C) KSCN (test tube D) NaOH (test tube E) Table 3 Equilibrium Involving Cobalt (II) Complexes STRESS OBSERVATION DIRECTION
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Lab 1: Observation of Chemical Changes Name: Tyler Lee Lab Partners: none Date of Experiment: Feb 26 2015 Location: My House Course Number: CHE111 Abstract: The point of this lab was to test and observe chemical changes when mixing chemicals together and also through heating chemicals. Experiment and Observations: The experiment performed in the first part of this lab was to mix various chemical solutions together and then observe and record the chemical changes‚ also if a chemical
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GRAND STRATEGY MATRIX 37 4. IE MATRIX 38 5. BCG 39 MATRIX ANALYSIS AND TOWS SUMMARY 40 DECISION STAGE 41 STRATEGIC IMPLEMENTATION 43 5. STRATEGIC IMPLEMENTATION: 44 STRUCTURE & CULTURE 44 RESOURCES 44 STRATEGY # 1: TAURINE FREE RED BULL 44 STRATEGY # 2: DIVERSIFYING INTO SPORTS DRINKS MARKET 45 SYNERGIES IN VALUE CHAIN 46 PITFALLS IN STRATEGIC IMPLEMENTATION 46 SCORE CARD 48 DIAGNOSTIC SURVEY OF PRIMARY AND SECONDARY MANAGEMENT PRACTICES: 49 BIBLIOGRAPHY: 55 “MISSION
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November 3‚ 2014 Chemistry 1411- 106 Pre Lab Experiment #8 Objective: This Lab will help us to understand oxidation reduction and double displacement through finding the percent composition of pennies. We will also once again be working with titration in this lab. We will titrate the solution until we are only left with a solid form which will tell us about the composition of pennies. Introduction: The weight of a post 1982 penny is 2.5 grams‚ and the percent of zinc is 97.5% leaving only 2.5% copper
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1M of NaOH = 23g/mol + 16g/mol + 1g/mol = 40g/mol 1M = 40g/mol dissolved in 1L and 20g dissolved in 500ml 20g of NaOH was used to prepare 500ml of 1M NaOH. Part B Molecular weight of 1M of HCl = 35.5g/mol + 1g/mol = 36.5g/mol Specific gravity = 1.19kg/L 37% HC1 × 1.19kg/L = 0.44kg/L Convert w/v to mol/v = = 12mol/L = (12mol/L) = (1M)250ml = 20.83ml ≈ 21ml 21ml of concentrated HC1 is used to prepare 250ml of 1M of HC1. Part C For 0.1N of NaOH : For 0.1N of HC1 : (1M) = 50ml of NaOH (1M)
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Abstract: The Enzyme Lab results where when the liver was frozen‚ its reaction was fast‚ and when it was hot‚ it was slow‚ and the liver that was at room temperature reacted slowly to medium. Introduction: The Enzyme Lab is to conduct investigations to determine the most favorable conditions for the most efficient enzyme activity. Variables to be used testing include temperature‚ pH values and surface area. Enzymes are proteins that speed up the rate of chemical reactions‚ which would otherwise
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Titration Lab Introduction The purpose of this lab is reach and be able to calculate the equivalence point when we use titration to neutralize a base with acid. The process of the lab was determining the volume of a solution needed to react with a given mass or volume of a sample is called titration. The equivalence point is when the same number of moles of acid and moles of base has been added. Phenolphthalein is used as an indicator because it will have a color change when the equivalence point
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9.5 – 5.0 = 4.5. Therefore 4.5 mL of NaOH was needed to neutralize HCl. Table 3: The amount of NaOH (mL) needed to neutralize HCl in Condition 1‚ 2 ‚ and 3 and their 3 trials. Trial 1 (mL) Trial 2 (mL) Trial 3 (mL) Condition 1 4.5 4.0 4.0 Condition 2 8.0 8.0 9.0 Condition 3 9.5 9.0 9.5 2. Sample Average Calculation of Condition 1: Table 4: The average volume (mL) of HCl & NaOH in each Condition Average Volume of HCl & NaOH Condition 1 9.2 Condition 2 16.5
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The full strength 1M HCl acid had a pH level of 3.12 (Table 3.1). Sample A2 to A4 remained in the pH 3 level‚ while sample A5 and A6 had a pH range of 4 (Table 3.1). The pH level for 1M HCl dilutions slightly increased between each sample (Table 3.1). The diluted solutions of 1 M NaOH showed a few unexpected results. The original solution of 1 M NaOH was at a pH level of 11.50 (Table 3.1). However‚ the pH of sample B2 increased to 12.81 (Table 3.1). The remaining samples had a decreasing pH pattern
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