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biggest one. This real case now can be simplified as 1-dimensional motion in the experiments. During the lab‚ the Motion Lab&VideoRECOREDER was used to record the motion of the cart. After that‚ the accelerations were gained by calculating the slope of Velocity VS. Time graph. The accelerations and the relationship among them in every stage are gained from the graph. Prediction It was predicted that the acceleration would be a constant‚ as long as the angle‚ θ‚ between the track and the desk did not
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of design will experience three phases of apparent weight: the lifting‚ falling and braking stages. At first‚ the rider will feel heavier as the carriage accelerates. Then‚ as the velocity is constant‚ the apparent weight will equal that of the real weight. Finally‚ as the ride slows at the top‚ the decreasing velocity will result in a lighter feel. During free fall‚ riders will feel weightless‚ before experiencing a dramatic increase in apparent weight during the braking stage. As the ride climbs
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Modern Physics Fall/Winter 1900‚ Max Planck’s paper “Ueber das Gesetz der Energieverteilung im Normalspectrum”‚ Annalen der Physik IV‚ 553 (1901) – peak in 1920s/30s Two major parts: modern relativity‚ first 4 - 6 lectures Quantum mechanics and its applications‚ rest of the course –also main content of Phys 312 to follow next quarter ---------------------------------------------------------- What is Physics all about? concepts and their connection‚ i.e. mathematically formulated equations/laws
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After 2 s‚ a second ball is thrown straight downwards. What should be the initial velocity of the second ball so that both hit the water simultaneously ? 1) 2.45 ms-1 2) 49 ms-1 3) 14.5 ms-1 4) 24.5 ms-1 3. Which of the following are true ? 1. A body having constant speed can have varying velocity. 2. Position time graphs for two objects with zero relative velocity are parallel. 3. The numerical ratio of velocity to speed of an object can never be more than one. 1) 1 only 2) 2 and 3 3) All 4) None
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if it takes a curved path. 7 (a) Length of the path = 0.8 × 120 = 96 m (b) No matter which path the ball takes‚ its displacement remains the same. (b) Length of AB along the dotted line 96 = 30.6 m = (c) Magnitude of Jack’s average velocity 30.6 × 2 = = 0.51 m s–1 120 Practice 1.3 (p. 23) 1 B Total time 5000 5000 = + = 9821 s 1.4 0.8 5000 + 5000 = 1.02 m
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a north–south direction across a desert. At 06:00 each crew sets out from their base camp which is situated at the origin (0‚ 0). One crew is in a Toyundai vehicle and the other in a Chryssault vehicle. The Toyundai has velocity vector km h–1‚ and the Chryssault has velocity vector km h–1. (a) Find the speed of each vehicle. (2) (b) (i) Find the position vectors of each vehicle at 06:30. (2) (ii) Hence‚ or otherwise‚ find the distance between the vehicles at 06:30. (3) (c) At this
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smoke to flow through any gaps present. By altering these pressure differences we can control the movement of smoke. The two BASIC PRINCIPLES of smoke control were defined by JH KLOTE (Ref 2) as:a) Airflow can control smoke movement if the average VELOCITY is of sufficient magnitude. b) A PRESSURE difference across a barrier can act to control smoke movement. Although
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the earth curves downward by approximately 5 metres over 8000 metres along the horizon‚ satellites launched with a horizontal speed of 8000 m/s can take orbit. At this speed‚ thanks to earth’s curved surface and a satellite’s constant horizontal velocity‚ the satellites‚ which are in free fall once projected‚ keep falling toward the earth‚ but always miss it. Thus‚ under the influence of gravity‚ satellites maintain motion in a circular pattern at a uniform speed. Most satellites are launched
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things get done in physics. It is such a useful technique that we will use it over and over again. Our goal in this section‚ is to derive new equations that can be used to describe the motion of an object in terms of its three kinematic variables: velocity‚ displacement‚
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