stop? 3. where is car #1 when car #2 changes direction? 4. what is the average velocity of car #1 in km/hr? 5. estimate the instantaneous velocity (in km/hr) of car #2 at t = 43 min ? x / km car #1 20 10 car #2 0 20 10 30 40 t / min [1.2] Here is a plot of velocity versus time for an object that travels along a straight line (positive direction to the right) with a varying velocity. v/ m/s 1. at what time(s) is the object at rest? 20 2. what is the average
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Merrily We Roll Along! Purpose: To investigate the relationship between distance and time for a ball rolling down an incline. Data: Table A | Time (s) | Incline 25° | Distance (cm) | Trial 1 | Trial 2 | Trial 3 | Average | 20.5 | 0.31 | 0.32 | 0.29 | 0.31 | 41 | 0.47 | 0.27 | 0.38 | 0.37 | 61.5 | 0.51 | 0.52 | 0.31 | 0.45 | 82 | 0.67 | 0.54 | 0.45 | 0.55 | 102.5 | 0.69 | 0.90 | 0.58 | 0.72 | 123 | 0.88 | 0.67 | 0.58
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14 Higher Level Applied Maths Exam Questions Vertical Motion 15 Common Initial Velocity 17 F = ma 19 Multi-stage Problems 20 General Questions 26 Guide to answering individual higher level exam questions 2009 – 1995 28 Other miscellaneous points 33 *********** Marking Schemes / Solutions to be provided separately ************* Acceleration is the rate of change of velocity with respect to time*. The unit of acceleration is the metre per second squared
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Science 10. P 393 Investigation 13A Time (sec) Displacement (cm down) Velocity ( down) 0 0 0 0.1 0.6 = Df – Di = 0.6 – 0 = 0.6 = 0.2 1 = Df – Di = 1 – 0.6 = 0.4 = 0.3 3.3 = Df – Di = 3.3 – 1 = 2.3 = 0.4 5.9 = Df – Di = 5.9 – 3.3 = 2.6 = 0.5 7.4 = Df – Di = 7.4 – 5.9 = 1.5 = 0.6 8.7 = Df – Di = 8.7 – 7.4 = 1.3 = 0.7 10.1 = Df – Di = 10.1 – 8.7 = 1.4 = 0.8 11.4 = Df – Di = 11.4 – 10.1 = 1.3 = 0.9 12.9 = Df – Di = 12.9 – 11.4 = 1.5 = 1.0 11.8 = Df – Di = 11.8 – 12.9 = -1.1 = 1
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AP Physics Slinky Velocity Lab Group: Asaf Yankilevich‚ Lily Greenwald‚ Yaeli Eijkenaar‚ Michal Antonov 2/23/15 Materials ● Slinky ● Spring weight ● Force measurer ● Measuring Tape ● Timer Procedure 1. The first slinky’s mass was weighed‚ using a scale‚ and its tension was measured using a force measurer 2. The slinky was stretched to 4m. 3. The linear mass density was solved for‚ by dividing the mass by the length. 4. The theoretical velocity was solved for‚ using the equation
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Regents Physics Constant Velocity/ Acceleration Lab 10-3-13 Problem: Graphical Analysis of Constant Velocity and Accelerated Motion. Theory: Gravitational acceleration is constant on Earth g=9.8m/s2 Therefore‚ when the golf ball is dropped‚ the acceleration will be equal to gravitational acceleration agb=9.8m/s2 Given there is no air resistance‚ this means that when the golf ball is dropped from a given distance‚ according to the formulas‚ the golf ball will accelerate
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SCIENCE CLASS – IX SAMPLE PAPER SA – 1 General Instructions: MM: 90 The question paper comprises of two sections‚ A and B. You are to attempt both the sections. i) All questions are compulsory. ii) There is no overall choice. However‚ internal choice has been provided in all the five questions of five marks category. Only one option in such questions is to be attempted. iii) All questions of Section A and all questions of Section B are to be attempted separately. iv) Question numbers 1 to
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shot‚ you are going to need to know what projectile motion is. So really‚ what is projectile motion? Projectile motion is the curved path (also known as a parabola) an object follows when thrown near the surface of the Earth. It has an initial velocity‚ but after that‚ the only force acting on the object is gravity. In order to figure out the perfect shot‚ you are going to need to know what projectile motion is. So really‚ what is projectile motion? Projectile motion is the curved path (also
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Graphical Analysis of Motion Introduction To graphically analyze motion‚ two graphs are commonly used: Displacement vs. Time and Velocity vs. Time. These two graphs provide significant information about motion including distance/displacement‚ speed/velocity‚ and acceleration. The displacement and acceleration of a moving body can be obtained from its Velocity vs. Time graph by respectively finding the area and the slope of the graph. Data Tables – Part I Displacement (m) Time (s) 0.10 m
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percentage difference between the initial velocity calculated with kinematics and momentum are 0.0515%‚ which shows the calculation of initial velocity using the two different ways have a relatively similar answer. The percentage error between the theoretical value of initial velocity measured with photo gate and lab quest and the experimental value calculated with kinematics is 0.02473%. The percentage error between the theoretical value of initial velocity measured with photo gate and lab quest and
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