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    2D Motion Lab

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    opens‚ click on ‘Show Both’ for Velocity and Acceleration at the top of the page. Now click and drag the red ball around the screen. Make 3 observations about the blue and green arrows (also called vectors) as you drag the ball around. 1. The green line points in the direction that the ball is going to go 2. The blue line changes the direction it points. 3. The blue line also changes size depending on the speed 2) Which color vector (arrow) represents velocity and which one represents acceleration

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    Free fall and the acceleration due to gravity Problem/Question: How do you measure the acceleration of a falling object? Hypothesis: by measuring velocities of a falling ball then applying the data into equations numerous times‚ the results should approach to the acceleration. Variables: A: Independent Velocity B:Dependant Acceleration C:Constant Distance (photo gates) Materials: Photo gates‚ Clay ball‚ Photo gates machine.

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    Calculus

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    b) Average velocity for the first 2 seconds after the ball was dropped= h2-h02-0 = 430.4-4502-0 = -19.62 = -9.8 m/s c) Average velocity for the following time intervals: i. 1≤t≤4 = h4-h14-1 = 371.6-445.14-1 = -73.53 = -24.5 m/s ii. 1≤t≤2 = h2-h12-1 = 430.4-445.12-1 = -14.71 = -14.7 m/s iii. 1≤t≤1.5 = h1.5-h11.5-1 = h1.5=-4.91.52+450-445.11.5-1 = 438.975-445.11.5-1 = -6.1250.5 = -12.25 m/s = -12.3 m/s d) Instantaneous velocity at t= 1 second

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    Reaction Time Lab Report

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    The reaction time is the amount of time required to sense astimulus‚ analyze its meaning‚ and  respond.  Acceleration is the rate of change of velocity.  Velocity is speed with direction.  Displacement is  the moving of something from its place or position.  Free fall acceleration is when there is no air resistance  affecting an object.  equation for reaction time:   t= 2Δx g   constant acceleration equation:  Δx = v0 t+ 12 at  2   Velocity:

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    spring (spring with a higher spring constant k) is used in the experiment then the frequency and centripetal force will both increase. If the spring constant increases‚ the plumb bob will have to rotate at higher velocity to become perpendicular to the horizontal shaft. A higher velocity means a higher frequency since the plumb bob is moving faster and is completing each rotation in less time than before. The centripetal force will be higher because the spring requires more force to cover less distance

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    Save Tigers

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    Q. 18. Using matrix method solve the following system of linear equations: [pic] SECTION - B Q. 19. In any [pic]prove that cos [pic]with the help of vectors. Q. 22. A particle describes 650 m in 10 seconds and its velocity at the end of that is 80 m/sec. find its initial velocity and the acceleration. Q. 25. Find the equation of the plane passing through the points [pic]and perpendicular to the plane [pic]  SECTION - C  Q. 20. A bill for Rs. 1‚50‚000 was drawn on 14 th may‚2003 for 5 months

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    UNIVERSITY ENTRANCE EXAMINATION PHYSICS Duration : 2 hours Please read the following instructions carefully. 1. This paper is made up of 50 Multiple-Choice questions and comprises ELEVEN (11) printed pages. 2. Do not write on the question paper. 3. Answer all questions and indicate your answers on the answer sheet provided. Marks will not be deducted for wrong answers. 4. Do not take any paper‚ including the question paper or unused answer sheets‚ out of the examination

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    Energy Absorbing Impact Zone

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    Product Testing & Verification Coursework Energy Absorbing Impact Zone Group Number: 3A Group Members: SBC-11-1021 673654 EE Da Wei (David) SBC-11-1022 673666 EE Zhang Minhui (Park) SBC-11-1028 673661 EE Wu Yifan (Jason) SBC-11-1027 673664 EE Xiang Qi (Aaron) Submission Date: Apr. 18th 2014 Contents Introduction………..…..………………...……………………...…….....3 Mind Map …………………………..………………………...……..…….6 Process Map ……………………..……………………………………..…7 Four Original Designs………..………………..…...………

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    to the air-cart by a string and hung over pulley with the other end attached to an air-cart resting on a frictionless surface. The study of the motion of the system of masses will be used to determine the velocity of the masses from an analysis of the displacement versus time data. This velocity will then be used to calculate the acceleration of the system of masses and therefore the acceleration due to gravity. A spark timer will mark the motion at a frequency of 10 Hz (10 dots/s) on a strip of paper

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    j D) 34.0 E) 1028 ^ ^ ^ ^ 5) ^ ^ 6) An object has a position given by r = [2.0 m + (5.0 m/s)t]i + [3.0 m - (1.0 m/s 2)t2 ]j. Determine the velocity of the object as a function of time. A) 5.4 m/s ^ ^ B) (5.0 m/s)i - [(1.0 m/s2 )t]j 6) C) 5.1 m/s D) (5.0 m/s)i - (1.0 m/s2 )j ^ ^ E) (5.0 m/s)i - [(2.0 m/s2 )t]j 7) An object has a velocity v 0 (t) = (3.00 m/s)i + (1.00 m/s)j at time t = 0.00 s. The acceleration of the object is a (t) = (2.00 m/s3 )ti + (1.00 m/s4 )t2j. If the object

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