Statics and Dynamics 1. The diagram below shows the loading on one of the horizontal floor beams and associated supporting vertical columns for a proposed building‚ sited on an incline. In order to consider the worst case‚ assume that the beam is simply supported and the column is pin jointed at either end. 1.1 Determine the beam reaction forces at each support and . Taking moments around (2 x 50) + (6 x 70) + (10 x 20) = (8 x ∴ = = 90 KN So‚ = 50 + 70 + 20 = + 90
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For this quarter we started off with a bottle rocket project. This project lead us to become more educated with Newton’s laws of motion. The bottle rockets also lead you to learn about mass‚ force‚ and acceleration. As you know the first law of motion is that if objects at rest will stay at rest‚ or objects in motion will stay in motion‚ unless acted upon by an unbalanced force. Well in order for the rocket to lift off it will need force applied to it. It is required to add water for your rocket
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Mathematics and Physical Science Department Name: Student # Score: Rye Alfonso PHYSICS 103 LECTURE Recitation Activity #2 ANSWER KEY Chapter 2: MOTION in One-Dimension‚ VECTORS DIRECTION: Please show complete solutions and box all final answers. Write the answer up to two decimal places. ☺ 1. Three horizontal ropes pull on a large stone stuck in the ground‚ producing the vector forces ‚ and given in the figure below. Find the magnitude and direction of a fourth force on the stone that will make the
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The purpose of this lab was to learn about Newton’s laws of motion by completing an experiment‚ to see how the forces act on objects. The independent variable of this experiment is the type and amount of materials used for the interior of the vehicle (out of the material list) and how they were used. The dependent variable is how and if the interior of the vehicle protected the egg from getting cracked. The controlled variables of this experiment were the height that the vehicle was dropped from
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Purpose: Predict how forces can change motion. Provide reasoning and evidence to explain motion changing or not. Answer in Complete Sentences. Open the Forces and Motion Basics simulation and play with the Friction screen for a few minutes. Set your value like the picture below. Imagine that your friend‚ Sam is trying to move a box. Using what you learned by exploring‚ try drawing arrows to predict what might happen in the pictures below. (Try this part without using the simulation.) Sam
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Background Information Terminal velocity is when a falling object reaches a constant velocity due to a balance in the forces of weight and air resistance. In this experiment‚ we dropped marbles of difference weights in 100 ml of oil to calculate their terminal velocity. Research Question How does the mass of an object effect its terminal velocity? Aim Our aim is to measure the terminal velocity‚ of marbles of different masses‚ in oil. hypothesis Objects of larger mass will take longer to reach
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Case 09-1: Velocity Cellular Page 1 D I S C U SS I O N M A T E R I A L S O b j e c t i v es o f t h e C a se This case gives students the opportunity to use accounting and auditing literature and professional judgment to research complex accounting issues effectively and efficiently. Specifically‚ students will be able to: Understand the application of the guidance in ASC 605-25‚ as amended by ASU 2009-13‚ to complex multiple-deliverable arrangements. Understand the application of the
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A graph showing the experimental results. Figure 7: shows the relationship between loft angle and linear velocity From the Figure 7‚ there is a negative relationship between the loft angle of golf club and the linear velocity of golf ball. Which means as the loft angle increases‚ the linear velocity of ball decreases. The golf ball travels with relatively fast velocity at 9.2ms-1‚ when the loft angle is 0 degree‚ but it travels relatively slower at 3.7ms-1 when the loft angle is 80 degree. Also
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reaches its so-called terminal velocity. Different objects have different terminal velocities. The terminal velocity of a human being falling through the earth’s atmosphere -- a skydiver with an unopened chute‚ for instance -- is about 120 mph (193.1 kilometers per hour). That’s surprisingly slow‚ but still fast enough that a person falling from an airplane would make a pretty big splat upon hitting the ground. The idea of a parachute is to reduce a person’s terminal velocity and make a long
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position and velocity. ⎛1⎞ ⎛1 ⎞ x = ⎜ ⎟ − ⎜ − 2 ⎟ = − 2.741 m ⎝3⎠ ⎝3 ⎠ 3 2 x = − 2.74 m ⎛1⎞ ⎛1 ⎞ v = 3 ⎜ ⎟ − 2 ⎜ − 2 ⎟ = 3.666 m/s ⎝3⎠ ⎝3 ⎠ 2 v = 3.67 m/s Vector Mechanics for Engineers: Statics and Dynamics‚ 8/e‚ Ferdinand P. Beer‚ E. Russell Johnston‚ Jr.‚ Elliot R. Eisenberg‚ William E. Clausen‚ David Mazurek‚ Phillip J. Cornwell © 2007 The McGraw-Hill Companies. COSMOS: Complete Online Solutions Manual Organization System Chapter 11‚ Solution 3. Position: Velocity: x = 5t
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