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    Normal Distribution

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    decimal places) 2. Find the value of z if the area under a Standard Normal curve a) to the right of z is 0.3632; b) to the left of z is 0.1131; c) between 0 and z‚ with z > 0‚ is 0.4838; d) between -z and z‚ with z > 0‚ is 0.9500. Ans : a) z = + 0.35 ( find 0.5- 0.3632 = 0.1368 in the normal table) b) z = -1.21 ( find 0.5 – 0.1131 = 0.3869 in the normal table) c ) the area between 0 to z is 0.4838‚ z = 2.14 d) the area to the

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    service delivery

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    Introduction: The major factor which determines the success of a health and social care organization‚ is its effectiveness of service delivery. The way they offer their services to their customers‚ the quality of those services‚ the expectations of the service quality in the minds of the people‚ etc are really important‚ when considering the effectiveness of service delivery. The service delivery and associated service operations play a very critical role in achieving customer satisfaction. Only

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    Infection Control

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    Infection Control Summary: Infection control in a health care facility is the prevention of the spread of microorganisms between patient to patient‚ patient to staff member‚ and staff member to patient. Health care workers. All health care workers who have contact with patients and equipment must all adhere to the Infection Control Policies and Procedures to prevent from spreading infection to one another. In most of the health care facilities‚ many ill people are being treated and cared for

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    Professional Career Action Plan Renika Johnson HCS/449 October 22‚ 2012 Urmi Bhaumik Professional Career Action Plan The professional career action plan gives in details my career goals‚ rather than the personal goals. This professional career action plan will give an insight into the professional strengths and weaknesses‚ the health care organization to work at‚ and the knowledge gaps that exist‚ and professional resume. In this paper will speak on professional

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    Care transitions is described as a process when patient’s care shifts from being provided in one setting to another‚ for instance moving from a hospital to a patient’s home.46 Patients with complex care needs often require care at different settings. During care transitions‚ these patients often experience difficulties in managing their care and face problems of care fragmentation. Managing care transitions is important since inadequate management contributes to $25 to $45 billion in wasteful spending

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    Normal Distribution

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    Normal Distribution:- A continuous random variable X is a normal distribution with the parameters mean and variance then the probability function can be written as f(x) =   - < x < ‚ - < μ < ‚  σ > 0. When σ2 = 1‚ μ = 0 is called as standard normal. Normal distribution problems and solutions – Formulas: X < μ = 0.5 – Z X > μ = 0.5 + Z X = μ = 0.5 where‚ μ = mean σ = standard deviation X = normal random variable Normal Distribution Problems and Solutions – Example

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    Normal Distribution

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    Normal Distribution It is important because of Central Limit Theorem (CTL)‚ the CTL said that Sum up a lot of i.i.d random variables the shape of the distribution will looks like Normal. Normal P.D.F Now we want to find c This integral has been proved that it cannot have close form solution. However‚ someone gives an idea that looks stupid but actually very brilliant by multiply two of them. reminds the function of circle which we can replace them to polar coordinate Thus Mean

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    Chains of Infections

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    Chain of Infection As described above‚ the traditional epidemiologic triad model holds that infectious diseases result from the interaction of agent‚ host‚ and environment. More specifically‚ transmission occurs when the agent leaves its reservoir or host through a portal of exit‚ is conveyed by some mode of transmission‚ and enters through an appropriate portal of entry to infect a susceptible host. This sequence is sometimes called the chain of infection. Figure 1.19 Chain of Infection Image

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    Breast Cancer Care Plan

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    Joanne’s GP requested that she has some community care The G.P Joanne first went to her GP because she felt a pain in her right breast‚ she had a feel of the breast and came across a lump‚ The GP examined the breast and referred her to the specialist breast clinic When the wound has healed‚ Joanne can begin radiotherapy 5x week for 4 weeks. This will be done to ensure that all the cancer cells have died. This treatment will be done by a therapeutic radiographer Pharmacy for her repeat

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    Critical Care Nursing: Sickle Cell Anemia Critical Care Nursing 10/15/2009 Sickle cell anemia affects millions of people worldwide. Sickle cell anemia is a disease in which your body produces abnormally shaped red blood cells. They don’t last as long as normal‚ round red blood cells‚ which leads to anemia. Sickle cells contain abnormal hemoglobin that causes the cells to have a sickle shape. Sickle-shaped cells don’t move easily through your blood vessels. They’re

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