In most academic and business studies‚ KMO & Bartlett’s test play an important role for accepting the sample adequacy. While the KMO ranges from 0 to 1‚ the world-over accepted index is over 0.6. In our research‚KMO measure of sampling adequacy is 0.799 which is in acceptable range. Bartlett test of Sphericity comes out to be significant. Values in the table
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Exercise 2: Sample Design and Evaluation The information can be summarized as follows: N1= N2 Standard Deviation= 15 Difference in Performance= 5 Power= .8 After entering the given information‚ the window looks as follows‚ which shows us that N1= N2= 142 In the window above‚ change the power to .9‚ then N1= N2 = 190 In the window above‚ change the sigma1=15‚ sigma2=12‚ and don’t select Egual Sigmas checkbox‚ thus I get N1= N2= 156 In the window above‚ change the N1=200
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This revealed that the researcher adequately collected data by distributing at least twice the targeted sample size to address the research questions. Therefore the data collected on the effectiveness of the ZDF BF internal controls could be justified. Figure 4.4 displays the subjects’ response rate. Figure 4.5: Response rate. Source: Primary Data. 4.2 The Nature and Type of Available ZDF BF Internal Control System The discussion‚ on the evaluation of ICS in the dissertation‚ was mostly based
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weighted average of the above mentioned components. Harrigan University is concerned that it is not getting enough of the best students and furthermore it is concerned that most of its selected best students opt for Harrigan’s main rival. Based on the sample information of 178 students(from all acceptable students from past several years)‚ we need to determine whether Harrigan University has a legitimate concern. Summary/Results:- 1. Find a 95% confidence interval for the proportion of all acceptable
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To study the morphological and morphometric variations in foramen Vesalius in dry adult human skulls. MATERIALS and METHODS: One hundred and fifty dry adult human skulls were studied for variations in size‚ shape‚ bilateral symmetry‚ presence/absence and any duplication/multiplication of the foramen Vesalius. RESULTS: The mean maximum dimension of foramen Vesalius was 0.98±0.67 mm on right side and 1.12±0.73 mm on left side. Foramen Vesalius was present in ninety skulls out of one hundred and fifty
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main purpose of this experiment was to observe and record the various protein samples’ absorbency values through the calibrated readings of a spectrophotometer (595 nm calibration). Using the standard curve equation (y = 1.6147x + 0.0968) derived from determining the regression equation of different protein concentrations of BSA‚ an accurate form of protein concentrations were obtained for three different given samples‚ including an unknown. A notable empirical observation found in this experiment
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reference set are including 7 solutions (members) that is shown in the figure above. In genetic algorithm‚ two solutions are selected randomly from the population and a crossover operator used for the production of one or more children. GA are including a sample population of 100 elements that are selected randomly to create crossover. But in scatter search‚ two or more of the reference set in a systematic approach in order to produce new
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average person‚ you believe this might not be correct. You take a sample of 30 Kaplan students and give them the SFIT. Using the data from this administration you determine the sample mean to be 109 and the sample standard deviation to be 11.8. Using StatCrunch‚ "Z Statistics--One Sample-- with summary" you get the following output: 90% confidence interval results: μ : population mean Standard deviation = 11.8 Mean | n | Sample Mean | Std. Err. | L. Limit | U. Limit | μ | 30 | 109 | 2.1543753
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researching how the pace of runners changes during the course of a race. a. He takes a simple random sample of 20 athletes running an 800m race. The 800m race consists of two laps round a 400m track. What statistical test should he perform to determine whether there is a difference between population average completion times for the first lap and the last lap? b. He takes another simple random sample of 20 athletes running a 1200m race. The 1200m race consists of three laps round a 400m track. How
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between a random sample and the population. Chapter 8 #34 Information from the American Institute of Insurance indicates the mean amount of life insurance per household in the United States is $110‚000. This distribution follows the normal distribution with a standard deviation of $40‚000. a. If we select a random sample of 50 households‚ what is the standard error of the mean? SE = sd/sqrt(N) = 40000/sqrt(50) = 5656.85 b. What is the expected shape of the distribution of the sample mean? It will
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