Grade 11 physics: SPH3U1-01 | Physics Lab Report | Specific Heat Capacity of Brass | | Jin Jin Shi | 2012/12/6 | Instructor: Mr. Nailer | I. Introduction The amount of heat required to raise the temperature of a solid body depends on its change in temperature (ΔT)‚ its mass (m)‚ and an intrinsic characteristic of the material forming the body called specific heat (cp). The heat is calculated from the equation II. Purpose The purpose of this laboratory is to determine
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of the cartilaginous fish. 3. Draw and identify the external and internal features. 4. Describe the function for each feature. METHODOLOGY 1. The briefing on the experiment is given by the demonstrator. 2. The full images of the specimens and other important features are taken for identification purposes by using white slate board as the background. 3. Ruler is used as a scale. 4. A shark is dissected by the demonstrator. The external and internal features are identified
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Rate (μmol O2/m2/min) (correct to 3 decimal places) Phase 1 0.032 281.026 Phase 2 0.045 395.193 Phase 3 0.035 307.372 Phase 4 (Dark) 0.026 228.333 Table 1 Conclusion In this experiment‚ we found that the highest rate of photosynthesis is phase 2 and the O2 concentration in the chamber didn’t reach steady state in the light but decline gradually when the light was turned off. Questions to answer (i) The highest photosynthetic rate is in Phase 2. (ii) Estimate the CO2 concentration in the chamber
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Biosphere Lab Report A biosphere can be defined a lot of different ways. Our interpretation of a biosphere is the area in which life can be contained within. In the case of the earth‚ it means as high as a bird can fly and as deep as fish can swim in the ocean. A biosphere is a closed system that has a constant flow of energy between the organisms living within it and it needs nothing outside of itself but sunlight to continue to be sustained. At the University of Arizona‚ they attempted to build
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LAB REPORT HYPOTHESIS 1: Plants transpire the most when the environment has light and less humidity JUSTIFICATION: Water evaporates more readily because light stimulates the opening of the stomata and photosynthesis would occur. HYPOTHESIS 2: Transpiration would occur the second most when there’s light and lots of humidity. JUSTIFICATION: The light would allow photosynthesis to occur and the stomata to open but little if any diffusion of water out the leaf would occur. HYPOTHESIS 3:
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Colleen Doyle Lab report 4 Gender Roles John Tucker Must Die John Tucker Must Die is a movie about the classic stereotypical male athlete in high school. John Tucker is the star basketball player who is sexy‚ talented and good with his words. Every girl in high school wants to date John Tucker. With his reputation‚ John dates 3 girls at once. He dates such stereotypical girls including the cheerleader‚ the “slut”‚ and the smarty-pants. Because of his name‚ he gets away this. But‚ all of this
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Thermodynamics- Enthalpy of Reaction and Hess’s Law December 5‚ 2011 Kylie Case‚ Emma McKee‚ Rebecca Smith Purpose: In this lab‚ the purpose was to verify Hess’s Law. Theory: Four main topics were covered during this experiment including enthalpy of reaction‚ heat of formation‚ Hess’s Law‚ and calorimetry. The first being enthalpy of reaction‚ ΔHrxn‚ which is the heat or enthalpy change for a chemical reaction. The energy change is equal to the amount of heat transferred at a constant
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go through the whole process of osmosis. Also‚ a lot of the experiment was rushed as we were under pressure to finish as quickly as possible. Unfortunately the time constraint was caused by and outside influence unrelated to the lab itself‚ and so next time we could do a lab under normal conditions where there are no outside disturbances. There were weight differences in the potatoes which could have caused thicker potatoes to absorb more than others. It was a little impossible to obtain the same
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CHM130 Lab 4 Calorimetry Name: Data Table: (12 points) ALUMINUM METAL Pre-weighed Aluminum metal sample mass (mmetal) 20.09 g Temperature of boiling water and metal sample in the pot (Ti(metal)) dsdfa(Ti 99°C Temperature of cool water in the calorimeter prior to adding hot metal sample (Ti(water)) 24°C Maximum Temperature of water/metal in calorimeter after mixing (Tf) 28°C LEAD METAL Pre-weighed Lead metal sample mass (mmetal) 20.03g Temperature of boiling water and metal sample
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and the results are as follows: Diameter (mm) Mass (kg) 2 0.04 3 0.075 4 0.11 To find out the densities of the three balls‚ the following formula was used: Density= (mass of the ball)/(Volume of the ball)= mass/(4/3 π r^3 ) Density of 2mm ball = (0.04⁄1000)/(4/3 π 〖(0.001)〗^3 )=9551 kg/m^3 Density of 3 mm ball = (0.075⁄1000)/(4/3 π 〖(0.0015)〗^3 )=5305.16 kg/m^3 Density of 3 mm ball = (0.11⁄1000)/(4/3 π 〖(0.0020)〗^3 )=3282.57 kg/m^3 Accordingly‚ the average density of the
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