distillation can separate the alcohol from the wine. Results: Density of Brandy=0.88g/ml; Alcohol in Brandy 64%; Proof Rating of Brandy is 128 proof New Terms: 1) Distillation- is a method of separating mixtures based on differences in volatilities of components in a boiling liquid mixture. Equipment: graduated cylinder‚ thermometer‚ distillation flask‚ wire gauze‚ iron ring‚ jaw clamp and clamp fastener‚ condenser‚ long-stem funnel Questions Questions 1. Discuss the phenomenon
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Polymer Chemistry Classification of Polymers – Notes prepared by The most common way of classifying polymers is to separate them into three groups - thermoplastics‚ thermosets‚ and elastomers5. The thermoplastics can be divided into two types - those that are crystalline and those that are amorphous. You may click on the words in the diagram below to learn more about these classifications. Thermoplastics Molecules in a thermoplastic are held together by relatively weak intermolecular
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Sustainable Chemistry Terry Collins* Chemistry has an important role to play in achieving a sustainable civilization on Earth. The present economy remains utterly dependent on a massive inward flow of natural resources that includes vast amounts of nonrenewables. This is followed by a reverse flow of economically spent matter back to the ecosphere. Chemical sustainability problems are determined largely by these economy-ecosphere materials flows (see the figure‚ below)‚ which current chemistry education
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Making Connections: Chemistry Assignment By. Sujay Sukumar 5. a) When analyzing the graph‚ a relationship between the hydrocarbon chain of the alkane and its corresponding boiling point can certainly be noticed. There is a increasing correlation which can be explained using the theory that as each hydrocarbon chain gets bigger‚ there are more atoms and thus more electrons which contributes to higher dispersion forces and therefore a higher boiling point which is clearly seen through the graph.
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Iron‚ Salt and Sand Separating a mixture is an example of a physical change. There are several ways to separate a mixture. The use of one’s hands in pulling the parts of a mixture apart is one example. Filtration is another way to separate mixtures. Filtration is the separation of a heterogeneous (not alike‚ different) mixtures‚ by adding a solvent and passing the resulting mixture through a fine mesh or filter. Evaporation of a homogeneous (alike‚ same) mixture will reveal any solid particles
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| |Chemistry paper | | | | | | |Class: Ten |Roll No: |Subject: Chemistry | |Student’s
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Reactions of some Hydrocarbons Equipment Required: -4 Test tubes -Dropper - Cyclohexane (C6H12) (3ml) - Cyclohexene (C6H10) (3ml) - Toluene (CH3C6H5) (3ml) - Potassium Permanganate solution (KMnO4) .01 mol L-1 (4ml) - Sulfuric Acid (H2SO4) 2mol L-1 (2ml) - Bromine Water (Br2) (5ml) Procedure: Reaction of hydrocarbons with acidified permanganate: 1) Into three separate‚ labeled test tubes place 1 ml of cyclohexane‚ cyclohexene and toluene respectively. 2) In a separate test
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Calculations 1. Rounding Examples *0.1356 (4 significant figures) -> Round answer to 2 significant figures *0.1356 -> 0.14 *314.705 (6 significant figures) -> Round number to 4 significant figures. *314.705 -> 314.7 *0.0035771 (5 significant figures) -> Round to 3 significant figures. *0.0035771 -> 0.00358 *500‚000 (1 significant figure) -> Write this number to have 3 significant figures. *500‚000 - 5.00 x 10^5 *39.501 -> Round to 2 significant figures. *39‚501
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of the Upper Nepean Catchment. The following is a summary of factors that affect water quality. Water may contain several ions‚ namely anions and cations which are toxic to humans. Hardness is the scum on water surface from significant concentrations of calcium and magnesium ions. Total dissolved solids is the measure of dissolved solids that are ionic in water. Turbidity is the presence of suspended solids in water which reduces penetration of light‚ resulting in a decrease concentration of
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CHE 242 Tutorial 3: Problems & Answers Week 4: Feb 2- 6‚ 2009 1. Consider a gas that occupies 1.00 dm3 at a pressure of 2.00 bar. If the gas is compressed isothermally at constant external pressure‚ Pext‚ so that the final volume is 0.500 dm3‚ what is the smallest value Pext can have? Calculate the work involved using this value of Pext. Solution For compression to occur‚ the value of Pext must be at least as large as the final pressure of the gas. P1 = 2.00 bar‚ V1 = 1.00 dm3‚ V2 = 0.500
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