Compound 50‚ like its known analogue 3‚ involves an α‚β-unsaturated ketone‚ an acid-sensitive reactant‚ which prevents its direct synthesis in presence of protic solvents by refluxing. Despite of this characteristic‚ 50 was formed smoothly in 5 minutes by grinding chemistry‚ solely as E-isomer‚ without any evidence of decomposition after 1H and 13C MNR analysis. This synthetic approach provides easy access to such α‚β-unsaturated N-acylhydrazones‚ which are building blocks in the synthesis of nitrogen-containing
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commencing at age 60 and ending at age 67 Plan 1: V0 * (1.06)42 = 3‚000‚000 V0 = 3‚000‚000/(1.06)42 V0 = $259‚582.20 Plan 2: V0 * (1.06)17 = 3‚000‚000 V0 = 3‚000‚000/(1.06)17 V0 = $1‚114‚093.26 Plan 3: C * Annuity Compound Factor (6%‚ 37) = 3‚000‚000 C * [((1.06)37 – 1)/0.06] = 3‚000‚000 C *127.27 = 3‚000‚000 C = $23‚572.28 Plan 4: C * Annuity Compounding Factor (6%‚17) = 3‚000‚000 C * 28.21 = 3‚000‚000 C = $106‚334.41 Plan 5: C * Annuity
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Comparison between Organic and Inorganic Compounds Organic Compounds | Inorganic Compounds | *Organic Compounds are composed of few elements only.C‚ H‚O‚N‚S‚P and halogens are the most common. | * Inorganic Compounds are composed of all the known elements. | *They are generally found in living matter‚ i.e.‚ animals and plants. | *They are generally obtained from non-living matter‚ i.e.‚ minerals. | *They are usually gases‚ liquids or solids having low melting points. | *They are usually solids
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Discussion: Continuous distillation‚ a form of distillation‚ is an ongoing separation in which a mixture is continuously (without interruption) fed into the process and separated fractions are removed continuously as output streams. A distillation is the separation or partial separation of a liquid feed mixture into components or fractions by selective boiling (or evaporation) and condensation. A distillation produces at least two output fractions. These fractions include at least one volatile
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Kate Kirby June 6‚ 2013 Title: Extraction of an Unknown Compound Purpose: The purpose of this experiment was to separate a mixture of two or more unknown compounds and identify them based on their melting point and reactivity with an acid or a base. Compound studied/Reactions: The organic solvent used in this experiment was methyl t-butyl ether (MTBE‚ 2-methoxy-2-methylpropane). The unknown that dissolved in the MTBE‚ but was insoluble in water. MBTE is very volatile and flammable. It was
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Experiment 55: A Separation and Purification Scheme The final lab report/procedure write-up will consist of the following: Report guide: 1. List the names‚ structures‚ and amounts of each compound in your mixture. 2. Draw a flow chart (like pg 687 in PLKE) showing how you separated and isolated your two compounds. Be sure to include the structures of the compounds at each step. 3. Write a procedure. This should include exactly how you performed your separation. It should have enough
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Chemistry revision Atoms elements and compounds Atom-the smallest part of an element that can still be recognized as an element Element-a substance made up of only one type of atom. An element cannot be broken down chemically into any simpler substance Nucleus-middle of the atom‚ which contains protons and neutrons Electron-tiny particle‚ which surrounds the nucleus with a negative charge Compound-when two elements react and combine together which contain more than one element. There
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13.1 Compound Interest • Simple interest – interest is paid only on the principal • Compound interest – interest is paid on both principal and interest‚ compounded at regular intervals • Example: a $1000 principal paying 10% simple interest after 3 years pays .1 3 $1000 = $300 If interest is compounded annually‚ it pays .1 $1000 = $100 the first year‚ .1 $1100 = $110 the second year and .1 $1210 = $121 the third year totaling $100 + $110 + $121 = $331 interest 13.1 Compound Interest Period
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3/5/2011 EXPERIMENT EXPERIMENT 8 OBJECTIVES CONCEPTS REAGENTS PROCEDURE RESULTS DISCUSSION IR ANALYSIS 8 Objectives to differentiate various types of oxygen-bearing organic compounds to device a scheme to distinguish each functional group Analysis of Oxygen-bearing Organic Compounds alanx3@yahoo.com OBJECTIVES CONCEPTS REAGENTS PROCEDURE RESULTS DISCUSSION IR ANALYSIS to characterize an unknown sample through parallel chemical tests ARMSALCEDO ARMSALCEDO alanx3@yahoo
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Separation of a Carboxylic Acid from a Neutral Compound by Extraction Reference: Smith‚ Chapter 2 (Acids and Bases) Introduction Carboxylic acids and phenols are two families of organic compounds that contain carbon‚ hydrogen and oxygen‚ and also react with water to yield an excess of hydronium ions over hydroxide ions. Pure water has a pH of 7‚ which means it has a hydronium ion concentration‚ [H3O+] of 10-7 M (M = molarity‚ moles/Liter). The hydronium ions in pure water come from the self-ionization
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