02XXX-WTP-001-A March 28‚ 2003 NRZ Bandwidth (-3db HF Cutoff vs SNR) How Much Bandwidth is Enough? White Paper Introduction A number of customer-initiated questions have arisen over the determination of the optimum bandwidth for any transimpedance amplifier and subsequent filter employed in a fiber optic receiver module using NRZ coding. When asked what the optimum bandwidth for such a system‚ most engineers will respond with a number between 0.7 and 0.75 times the NRZ bitrate. The real answer
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narrowed down as the condition of being oneself and not another. You have to know yourself well and be able to reflect upon all the things that happen in your life to know who you are or who you could strive to become. In Sherman Alexie’s movie Smoke Signals‚ he emphasizes that you will get caught in trying to find your true identity if you run away from the obstacles in your life instead of facing them. Through the movie‚ the audience gets to know the teenage Cour d’Alene Indian Victor‚ whose dad left
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10πt Solution: ∧(5) cos 10πt = 0 Question 2: [6 points] An input signal x(t) = sinc (4t) is applied to to an LTI system with impulse response h(t) = sinc (6t). Let the output of the LTI system is y(t). (a) What type of signal is x(t) ? Energy-type or Power-type? Solution: Energy-type (b) Find the energy or power of the input signal x(t)? Solution: ∞ −∞ 1 4 2 ⊓ f 4 df = 1 4 (c) Find the energy or power of the signal y(t)? Solution: Y (f ) = H(f )X(f ) = 1 24 ⊓ f 4 . Thus
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words‚ where carry signals are generated at some positions. Depending on the position at which a carry signal has been generated‚ the propagation time can be variable. Carry Skip Adders take advantage both of the generation or the propagation of the carry signal. They are divided into blocks‚ where a special circuit detects quickly if all the bits to be added are different (Pi = 1 in the entire block). The signal produced by this circuit will be called block propagation signal. If the carry is propagated
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engineering in our institute. I have handled Digital Signal Processing and Advanced Digital Signal Processing‚ in the fifth and sixth of her undergraduate studies. She has consistently performed well and stands within the top 5 in her class of 66. She has a good understanding of the fundamentals in these subjects which will help her a great deal in furthering her skills during the graduate studies in her proposed field of communications and signal processing She is articulate and can express herself
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B.Tech. (Computer Science and Engineering) S E M E S T E R C O U R S E FIRST CHM101 PHY101 PHY102 MTH101 HSS-I-1/ ENG112N ESC101 PE101 SECOND TA101 PHY103 MTH102 ESC102 CS100 PE102 THIRD MTH203 CHM201 CS220 ESO-1 ESO211 FOURTH HSS-I-2 TA201 CS201 CS355 OE-1 FIFTH CS330 CS340 ONE OUT OF CS350‚ CS425‚ CS455 SIXTH CS335 CS345 ONE OUT OF CS315‚ CS365‚ CS422 SEVENTH CS498 EIGHTH CS499 In addition to above‚ the student must complete
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of Communications Technology and Mathematical Sciences Digital Signal Processing Part 3 Discrete-Time Signals & Systems Case Studies S R Taghizadeh <srt@unl.ac.uk> January 2000 Introduction Matlab and its applications in analysis of continuous-time signals and systems has been discussed in part 1 and 2 of this series of practical manuals. The purpose of part 3 is to discuss the way Matlab is used in analysis of discrete-time signals and systems. Each section provides a series of worked examples
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related with amplitude of carrier wave being altered or modulated by information signal. When binary ‘1’ is appeared‚ the signal is transmitted and it is stopped when binary ‘0’ is appeared. The binary ‘0’ and ‘1’ are represented the shifting value between the two selected amplitude. 2) Frequency Shift Keying (FSK) FSK is a modulation technique that related with the frequency shifting or changes of carrier signal to transmit the digital information. In simple cases of FSK modulation‚ one of the
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where xn are the Fourier Series coefficients of periodic signal x(t)‚ and G(f ) is the Fourier Transform of a single period of x(t). • “Convolution of a signal of width w1 with a signal of width w2 results in a signal of width w1 + w2 .” • From the Fourier Transform table: k=∞ n=∞ w(t) = k=−∞ δ(t − kT ) ⇐⇒ W (f ) = 1/T n=−∞ δ(f − n/T ) 2 1. 10% dB problem: The output signal power of an ideal amplifier is 17 dBm. The input signal power is 2 milliWatts. Find the power gain of the amplifier
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needed to make the signal proper and allow for no noise on the line. This is what we call signal to noise ratio. Some of the hardware needed is some basic things‚ a modem is needed at a home or business‚ this turns analog to digital and vice versa. There is also components called DAC which means a digital to analog converter along with a ADC‚ which stands for analog to digital converter. These devices are needed to ensure the right signal and clear as well. The main thing digital signal uses are the binary
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