IB Physics Internal Assessment Andy Tang Research Question In this internal assessment‚ I am given a cantilever to find the physical properties of it. I decide to investigate the relationship between the force I act on one side of the cantilever and the maximum acceleration the tail can reach. This experiment will be also showing the elasticity of the cantilever. Since I pull down one side of it and fixed the other side‚ when I cut the string‚ it will bounce up and down until all the internal
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Y 1 12 2 24 3 36 4 48 Once again‚ you can also flip this the other way and originally have the table above and the points in it‚ and then using that information make the linear function by finding the constant rate of change‚ or the slope‚ which in this case would be (+)12. Then‚ you’d plug that into the the common form for linear functions‚ f(x) = ax+b. In this form‚ f(x) is like the y‚ a is the rate of change‚ and b is the point at which you would start. In this case‚
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1. ht= -4.9t2+ 450‚ where t is the time elapsed in seconds and h is the height in metres. a) Table of Values t(s) | h(t) (m) | 0 | ht= -4.9(0)2+ 450= 450 | 1 | ht= -4.9(1)2+ 450= 445.1 | 2 | ht= -4.9(2)2+ 450= 430.4 | 3 | ht= -4.9(3)2+ 450= 405.9 | 4 | ht= -4.9(4)2+ 450=371.6 | 5 | ht= -4.9(5)2+ 450=327.5 | 6 | ht= -4.9(6)2+ 450= 273.6 | 7 | ht= -4.9(7)2+ 450= 209.9 | 8 | ht= -4.9(8)2+ 450= 136.4 | 9 | ht= -4.9(9)2+ 450=53.1 | 10 | ht= -4.9(10)2+ 450= -40 |
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To investigate how selected parameters change downstream on the Afon Caerfanell. Hypothesis: 1. The velocity of Afon Caerfanell increases downstream 2. The velocity of the river increases down the stream as the angle of the slope increases. RIVER DEFINITION A river is the natural course of the water‚ which goes from a higher point‚ to the lowest point‚ usually the sea‚ ocean‚ lake or another river. There are few cases where the river simply flows
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students can visit the center if the operating cost is to be at most $1‚000? The students at the center found many linear functions. Find an equation for each line. a. The line passes through the points (0‚ 8) and (4‚ 13). b. The line has slope –3 and passes through the point (1‚ 4). c. The line passes through points (1‚ 1) and (3‚ 9) At Metropolis Middle School‚ the student government earns money by recycling cans and bottles after school events. The graph shows some sample (attendance
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relationship. Whenever the concentration increases‚ the transmittance decreases. It can also be reversed‚ so when the concentration decreases‚ the transmittance increases. For this graph‚ the line should not touch the origin because it is a negative slope. In order for the concentration to be 0‚ the transmittance level must be at exactly 100%. This means that all the light particles are transmitted directly through the object without any levels of concentration. Y = 1.4599x – 0.0068 .07 = 1.4559x
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earth’s crust that is broadly bent downward. Zones of downwarp and platform slope -Northern Punjab monocline -Southern Punjab monocline -Cholistan shelf -Panno Aqil graben -Nawabshah slop -Lower Indus trough -Nabisar slope The Jacobabad –Khairpur high divides the Indus Platform into two segments. The lower segment is comprised of the Lower Indus trough. It is bound by Nawabshah and Nabisar slopes‚ which are inturn flanked by Thatta-Hydterabad and Tharparkar highs. The upper
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4/28/2008 Spatial filtering fundamentals by Gleb V. Tcheslavski: gleb@ee.lamar.edu http://ee.lamar.edu/gleb/dip/index.htm Spring 2008 ELEN 4304/5365 DIP 1 Mechanics of spatial filtering Considering frequency domain filtering‚ the effect of LPF applied to an image is to blur (smooth) it. Similar smoothing effect can be achieved by using spatial filters (spatial masks‚ kernels‚ templates‚ or windows). We discussed that a spatial filter consists of a neighborhood and a pre-defined operation
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intentionally stunt a child’s growth regardless of the end goal. However‚ it did show how much a child could learn with the right practice and motivation. Seeing the way Johnny could climb up a forty two degree slope at only ten months‚ or the way he could coast down a five degree slope on roller skates and be able to turn with such balance and control was nothing short of incredible. But the most amazing part of the study might be the “manipulating pedestals” portion of the test. Although Johnny
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three graphs show this movement with a negative sloping and then a positive sloping in Acceleration halfway through Region B which in turn makes velocity slope upwards. For 3.2 seconds the cart moves away from the sensor until it reaches 1.6 meters. Net force is equal to Ffan. Velocity and Position graphs show this movement with a positive slope. Acceleration graph becomes moderately straight until the cart is about to be stopped towards the end of Region C.
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