and scientific thoughts that have been recently challenged 5. Conduct research into how authorities in the sixteenth and seventeenth centuries responded to Galileo’s experiments and published works. Provide one example. Galileo once wrote a book about how the earth was moving around the sun. At this time this was considered wrong. Authorities were outraged and put Galileo on trial as a suspect of heresy. In court‚ Galileo was forced to state that all of his findings were wrong which sentenced him
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Physics “FORMULAS LIST “ | | | | | | | Quantity |Symbol |Formula | |% Error | |% Error = ( |A-M| ) x 100 /A | |% Uncertainty | |% Uncertainty = (Uncertainty
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Lecture Outline Chapter 2 Physics‚ 4th Edition James S. Walker Copyright © 2010 Pearson Education‚ Inc. Chapter 2 One-Dimensional Kinematics Copyright © 2010 Pearson Education‚ Inc. Units of Chapter 2 • Position‚ Distance‚ and Displacement • Average Speed and Velocity • Instantaneous Velocity • Acceleration • Motion with Constant Acceleration • Applications of the Equations of Motion • Freely Falling Objects Copyright © 2010 Pearson Education‚ Inc. 2-1 Position
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Raymond Ye Mr. Pettibone IB Physics 2 November 2013 Internal Assessment DESIGN Aspect 1: How does the time a rubber band spends stretching a force of 12.5 N affect the force required to break/snap the rubber band? IV- The time spent stretching the rubber band 12.5 N DV- The force required to break/snap the band Units for Independent Variable- Minutes Units for Dependent Variable- Newtons Aspect 2: Variables that will be kept the same include: -The force of the stretch -Conditions
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km 5 93 3 106 mi 3.8 3 105 km 5 2.4 3 105 mi 3500 km < 2160 mi 1.4 × 106 km < 864‚000 mi LibraryPirate PHYSICS LABORATORY EXPERIMENTS S e v e n t h E d i t i o n Jerry D. Wilson Lander University Cecilia A. HernÁndez-Hall American River College Australia • Brazil • Japan • Korea • Mexico • Singapore • Spain • United Kingdom • United States LibraryPirate Physics
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Wilson‚ College Physics‚ 6th Edition Chapter 9 Exercises MC = Multiple Choice Question‚ CQ = Conceptual Question‚ and IE = Integrated Exercise. Throughout the text‚ many exercise sections will include “paired” exercises. These exercise pairs‚ identified with red numbers‚ are intended to assist you in problem solving and learning. In a pair‚ the first exercise (even numbered) is worked out in the Study Guide so that you can consult it should you need assistance in solving it. The second exercise
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Therefore the sum of all the energies in the system is a constant. TMEinitial=TMEfinal 3. Explain the basic ideas that govern the design and operation of a roller coaster. A roller coaster is operated and designed through the application of Physics. The law of Conservation of Energy governs the changes in a coaster ’s speed and height. Simply put‚ the higher an object is off the ground‚ the more potential energy it has - that is‚ potential to gain speed as it falls. As it falls toward the ground
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1.1 GRAVITY AND GRAVITATIONAL FIELDS 1.1.1 Define weight as the force on an object due to a gravitational field. Weight is the force experienced by an object due to the presence of a gravitational field. This force is directly related to the strength of the gravitational field acting on an object and the mass of that object. m = mass‚ g = acceleration due to gravity m = mass‚ g = acceleration due to gravity Fg = mg Fg = mg 1.1.2 Explain that a change in gravitational
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PHYSICS PROJECT TO STUDY THE OPTICAL LENS OF A HUMAN EYE Eyes are organs that detect light‚ and convert it to electro-chemical impulses in neurons. The simplest photoreceptors in conscious vision connect light to movement. In higher organisms the eye is a complex optical system which collects light from the surrounding environment; regulates its intensity through a diaphragm; focuses it through an adjustable assembly of lenses to form an image; converts this image into a set of electrical signals;
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Kinematics / Projectiles x =?vt ?v = (v + vo)/2 v = vo + at x = vot + ½at2 v2 = vo2 + 2ax y =?vt ?v ’ ½(vo + v) v = vo – gt y = vot – ½gt2 v2= vo2 – 2gy R = (v02/g)sin(2θ) Forces Fnet = ma Fgravity = mg Ffriction ≤ μsN Ffriction = μkN Circular Motion Fnet = mv2/r ac = v2/r v = 2πr/T f = 1/T T = 1/f Gravitation F = GM1M2/R2 g = GM/R2 T2/R3 = 4π2/GM = constant GM = Rv2 Energy W = Fdcosθ KE
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