Chem 201 /HW#10 Chapter 9 Electronegativity Table: use this table to answer Q [pic] 1. Bromine tends to form a monatomic ion which has the electronic configuration of a noble gas. What is the electron configuration of that noble gas? a. 1s2 2s2 2p6 3s2 3p6 3d10 4p6 b. 1s2 2s2 2p6 3s2 3p6 4p6 4d10 c. 1s2 2s2 2p6 3s2 3p6 4s2 4p6 d. 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 e. 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 2. Which ion of
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Experiment 13: Synthesis of 1-Bromobutane An SN2 Reaction Experiment #13: Synthesis of 1-Bromobutane an SN2 Reaction Introduction: In order to synthesize 1-Bromobutane an alkyl halide must be present to undergo a nucleophilic substitution reaction of an alcohol. Since 1-butanol is a primary substrate it will undergo an SN2 reaction with sodium bromide in order to convert the alcohol group to water which is a better leaving group and will in the end produce 1-bromobutane. Experimentally
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Reminder: These notes are meant to supplement‚ not replace‚ the laboratory manual. A Diels-Alder Reaction History and Application: The 1950 Nobel prize in chemistry was awarded to Otto Paul Hermann Diels and Kurt Alder for their breakthrough work on the discovery and development of [4 + 2] cycloaddition reactions i. This set of reactions are enormously useful in the synthesis of six membered rings in a single stepii. These are used in many pharmaceutical applications. Tamiflu® is a drug which
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2-phenylethanol to get (2-bromoethyl)benzene. Using NaBr in an acidic solvent of H2SO4 with H2O present‚ this synthesis was possible. Subsequent evaluations using TLC and then analyzed samples by Gas Chromatography were done to evaluate the results. Using SN2 reactions‚ primary alcohol is going to be converted to alkyl halide. Since the reaction can be reversed‚ the strong sulfuric acid was to make sure the product would indeed be an alkyl halide. This is necessary for a shift towards alkyl halide because
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is clearly depicted in Figure 3‚ where the alteration of the amount of t-butyl chloride being added to the reaction vessel clearly produced a different rate constant. The findings from Part B of the experiment proved that the reaction followed the SN1 mechanism‚ with the increased concentration of water in the water/acetone mixture causing the reaction rate to increase due to the usage of polar solvents to stabilize the carbocation being produced during this mechanism in the slow‚ rate-determining
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oxidation number increases and it undergoes reduction. D. Its oxidation number increases and it undergoes oxidation. (2) 4. The following reactions are spontaneous as written. Fe(s) + Cd2+(aq) → Fe2+(aq) + Cd(s) Cd(s) + Sn2+(aq) → Cd2+(aq) + Sn(s) Sn(s) + Pb2+(aq) → Sn2+(aq) + Pb(s) Which of the following pairs will react spontaneously? I. Sn(s) + Fe2+(aq) II. Cd(s) + Pb2+(aq) III. Fe(s) + Pb2+(aq) A. I only B. II only C. III only D. II and III only (2) 5. What species are produced
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Mapua Institute of Technology Organic Chemistry Laboratory 2 Final Report Factors Affecting the Relative Rates of Electrophilic Aromatic Substitution Reaction Justiniano‚ Priscilla Raiza N. School of Chemical Engineering and Chemistry‚ Mapua Institute of Technology‚ Intramuros‚ Manila‚ Philippines Experiment No.1‚ Submitted on August 6‚ 2011 at N402. Abstract EXPERIMENT NUMBER ONE IS ALL ABOUT THE ELECTROPHILIC SUBSTITUTION OF AROMATIC COMPOUNDS. AROMATIC COMPOUNDS ARE THOSE ORGANIC
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Laboratory Experiment pubs.acs.org/jchemeduc NMR Kinetics of the SN2 Reaction between BuBr and I−: An Introductory Organic Chemistry Laboratory Exercise T. Andrew Mobley* Department of Chemistry‚ Grinnell College‚ Grinnell‚ Iowa 50112‚ United States S Supporting Information * ABSTRACT: A simple organic chemistry experiment is described that investigates the kinetics of the reaction between 1-bromobutane (BuBr) and iodide (I−) as followed by observing the disappearance of BuBr and the appearance
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Review Sheets for Chapter 20.1 1. Assuming the following reaction proceeds in the forward direction‚ 3 Sn4+(aq) + 2 Cr(s) 3 Sn2+(aq) + 2 Cr3+(aq) 4+ a. Sn (aq) is the reducing agent and Cr(s) is the oxidizing agent. b. Cr(s) is the reducing agent and Sn2+(aq) is the oxidizing agent. c. Sn4+(aq) is the reducing agent and Sn2+(aq) is the oxidizing agent. d. Cr(s) is the reducing agent and Cr3+(aq) is the oxidizing agent. e. Cr(s) is the reducing agent and Sn4+(aq) is the oxidizing agent. 2. The
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Introduction to Alkane Nomenclature A. Determining the Priority of Functional Groups. What’s in a name? 3-ethyl-5-(1-methylpropyl)-4‚4-dimethylnonane Too big a subject to cover on one sheet! This paper will focus on alkanes. Determining functional group priority will be the subject of a subsequent sheet. suffix http://masterorganicchemistry.com D. Applying the Lowest Locator Rule F. Dealing With Branched Substituents (the IUPAC Way) Number the chain from one end so as
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