Alka-Seltzer Reaction Rates Lab What are the different factors the effect the reaction rate of Alka-Seltzer? Matthew Arkfeld Leah Gilligan Jessie Abbott Period 4 June 2nd‚ 2008 Background Research: o The objective of the experiment was to determine if different factors affect the reaction rate of Alka-Seltzer. Alka-Seltzer provides fast relief to acid indigestion‚ upset stomach‚ heartburn‚ headaches‚ body aches and pains. It is an antacid and pain relief medicine used by millions
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From the results recorded it was identified that activity A and C had exothermic reactions‚ whilst activity B had an endothermic reaction. Each of the activities had initially begun with 23.4/8/9oC‚ however‚ within one minute of adding the 2nd reactants‚ the results began showing‚ as seen from the graph. Activity A and C had risen in temperature‚ with A gaining 4oC and in total of 2 minutes having the temperature of 27.9oC along with C increasing by 2.2oC and within 2 minutes of the experiment having
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seem to be caused by adverse drug reactions to medical drugs‚ according to research. On the contrary‚ Philippines don’t have a high risk of deaths that causes these because here in our country‚ we rely on those alternative medicines or herbal medicines. It is a lot cheaper but actually‚ it doesn’t have those therapeutic claims so it has a minimal assurance of being treated with the sickness. With these‚ we choose to use Western Medicines as well. Adverse Drug Reaction (ADR) is the response of our body
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Concentration‚ Along with Varying Temperature and pH-Balanced Environments on the Enzyme-Catalyzed Reaction of pNPP Abstract: Introduction: Many of the chemical reactions‚ which take place in in living things are controlled by enzymes. In such cases‚ the enzyme is a protein in the cell which lowers the activation energy of a catalyzed reaction‚ which serves to increase the rate of the reaction. Alkaline phosphatase is made throughout the body. Its function is to remove phosphate groups
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Constant of an Unknown Ester Hydrolysis Reaction Abstract The experiments to follow determined that the equilibrium concentrations of the reaction: ester + water ↔ alcohol + acid‚ are equal to 0.0363 moles of ester‚ 0.2852 moles of water‚ and 0.0268 moles each of alcohol and acid. Using this information the equilibrium constant was determined to be 0.06938. 1. Introduction In this lab the equilibrium constant‚ Kc‚ for the acid catalyzed reaction between an unknown ester and water
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On what I have seen‚ the first experiment showed chemical reaction to be more specific‚ combustion. In the experiment the Potassium permanganate (KmnO4) was used as the oxidant‚ and obviously oil as the fuel. As the two were mixed they needed to release energy in form of heat‚ that’s where combustion occurs. I learn that Combustion is the sequence of exothermic chemical reactions between a fuel and an oxidant accompanied by the production of heat and conversion of chemical species. The release of
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SPECTROPHOTOMETRIC DETERMINATION OF EQUILIBRIUM CONSTANT OF A REACTION UNIVERSITY OF THE PHILIPPINES‚ DILIMAN QUEZON CITY‚ PHILIPPINES August 2‚ 2013 ABSTRACT The objective of this experiment is to determine the equilibrium constant‚ denoted Keq‚ for the formation of [Fe(SCN)]2+ complex which is a product of the reaction between the ions Fe3+ and SCN-. In performing this experiment‚ solutions containing FeCl3 and KSCN‚ diluted in HCl‚ were measured for their absorbance using a UV-Vis
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Purpose: In this experiment I will predict the amount of product produced in a precipitation reaction using stoichiometry by accurately measuring the reactants and products of the reaction. I will also determine the actual yield vs. the theoretical yield by calculating the percent yield. Materials: 1 Distilled water 1 Paper towels 1 Small paper cup 1 Coffee cup or mug 1 Beaker‚ 100 mL‚ glass 1 Funnel 1 Cylinder‚ 25 mL 1 Goggles-Safety 1 Scale-Digital-500g 1 Weighing boat‚ Plastic 1 CaCl2·2 H2O-Calcium
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purpose of this lab was to find the theoretical and experimental percentage yields of the double displacement reaction between the solutions Lead (II) Nitrate (PbNO3) and Potassium Iodide (KI). It is important to obtain amounts of Lead (II) Nitrate and Potassium Iodide as close to 1.44g as possible. This reaction creates Lead (II) Iodide and Potassium Nitrate. The precipitate during this reaction is Lead (II) Iodide. The balanced equation is Pb(NO3)2 + 2KI= PbI2 + 2KNO3. In this lab the Lead (II) Iodide
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The purpose of this lab was to find out the reaction of iron nails and CuSO4‚ copper sulfate solution. Before starting the experiment‚ there were two possible outcomes of the reactions. CuSO4 + Fe → FeSO4 + Cu or 3CuSo4 + 2Fe → Fe2(SO4)3 + 3Cu. The ion chart showed that iron can only make two charges‚ +2 and +3. As the liquid evaporated‚ the weight changed because the liquid added to the nail’s weight. In a real world situation‚ scientists can use ratios to determine how much of a substance that
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