sailboat moves north for a distance of 10.00 km when blown by a wind from the exact southeast with a force of 2.00 × 104 N. The sailboat travels the distance in 1.0 h. How much work was done by the wind? What was the wind’s power? Your response should include all of your work and a free-body diagram. Answer: Power is work done per unit time and workdone is force times the displacement. Hence power equal force * displacement / time. P = 2e4*10 / 3600s = 55.56 W. (10 points) Score 0. A sailor
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SPH4U: Forces – Context Rich Problems I do not have answers to these problems‚ and I haven’t thought about how to solve them. They are all fairly challenging and fair game for a test question. Work with friends on them‚ explain your solutions and convince yourselves that you understand the problems. I can’t tell you if you are right - I just don’t know! 1. Tension‚ Weight‚ Friction: You are taking advantage of an early snow to go sledding. After a long afternoon of going up and down hills with
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acceleration = sum of all net forces is zero * An object in orbit around the earth is not truly weightless * Sitting half as far away from your class mate the gravitation force is four times as strong. (re2) * Newton’s First Law- inertia an object that is not moving will remain at rest (ex: and apple hanging from a tree) * The reason you head feels like it jerks back ward is when pulling away from a stop sign is due to Newtons first law * If two forces that are identical in strength
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2. Inertia is ________. A. A property of matter B. A type of force C. The speed of an object D. Any of the above 3. P and Q are two objects with masses 100 kg and 75 kg respectively‚ then ________. A. Both will have the same inertia B. Q will have more inertia C. P will have more inertia D. Both will have less inertia 4. Newton’s second law of motion states that an unbalanced force that acts upon an object causes it to: A. Accelerate B. Not accelerate
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Centripetal Force Lab Activity Analysis: 1. A) Average Percent Difference: 50g: (values expressed in newtons) Step 1: Calculate the average value of the two variables Average Value= Value 1+ Value 2 /2 = 0.49+ 0.61/2 = 1.1/2 = 0.55 Step 2: Calculate the difference between the two variables Difference= Value 2- Value 1 = Fc- Fg = 0.61- 0.49 = 0.12 Step 3: Calculate % difference % difference= difference
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Assignment – Physics 1 1. Two carts‚ one twice the mass of the other‚ experience the same force for the same time. What is their difference in momentum? What is their difference in kinetic energy? 2. A 12 g bullet is fired horizontally into a 96 g wooden block initially at rest on a horizontal surface. After impact‚ the block slides 7.5 m before coming to rest. If the coefficient of kinetic friction between block and surface is 0.60‚ what was the speed of the bullet immediately before impact
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found out that all that force applied exert about 1600 pounds of force to his arms. Not even the worlds strongest man can lift that much!! Next we talk about spider-man and his trickery. In his the movie spider-man 3 is basically immortal‚ never dying person. For example In a climatic battle scene spider man fall 80 stories and survives without breaking a bone‚ concussion‚ or presumably any internal bleeding. Lets use Newton’s second law to calculate (Fnet=ma) how much force the ground exerts on spider-man
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it is close to Earth then it is around 8km/s. 17. Why is it important that such a satellite be above Earth’s atmosphere? It is important because it avoids the heating effects of atmospheric friction. 18. What force acts on a satellite that is above Earth’s atmosphere? The only force is gravity. Plug and Chug 1-5 1. Calculate the resultant velocity of an airplane that normally flies at 200 km/h if it encounters a 50 km/h tailwind. If it encounters a 50 km/h headwind? 200+50=250km/h 200-50=150km/h
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Intermolecular forces exist between independent particles‚ such as atoms‚ ions‚ or molecules. They can be forces of either attraction or repulsion. The amount of charge‚ how it is distributed‚ and the length of time that a charge distribution exists can affect the strength of intermolecular forces. And despite having variable force strengths‚ all intermolecular forces are considered weak compared to chemical bonds‚ or intramolecular forces. Chemical bonds are not only stronger; they are also more
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