When combining one gummy bear‚ which is composed mostly of sucrose with molten potassium chloride‚ a violent reaction occurs. A surprising amount of energy us released by the reactant‚ and in process‚ the atom and molecule rapidly rearrange to form 3 products(CO2/H2O and KCl). This reaction is said to be products favor. A favoured product reaction is where almost all of the reactants‚ react to form products. In this case its sucrose and potassium chlorate react completely to form carbon dioxide‚
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r Lab Report 5 Introduction to the Classes of Chemical Reactions Course: Chem. 1151L‚ Tuesday & Thursday June 23‚ 2011 Mr. Nasir Uddin Pre Lab Questions: 1. CaBr2 (aq) + K3PO4 (aq) → CA(PO4)2(S) + KBr (aq) = Ca3(PO4)2 + 6 KBr Double Replacement 2. Li(s) + O2(g) = Li2O(s) =2 Li2O Decomposition 3. CH4 + O2 = CO2 + H2O = CO2 + 2 H2O Combination 4. AgBr(s) = Ag (s) + Br2(l) = 2 Ag + Br2 Combination 5. Mg(s) + H2SO4 (aq) = MgSO4 + H2
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CHM1022 Tutorial 2 – Semester 2‚ 2012 (Chemical Equilibria) 1. The reaction 2 HCl(g) +I2(s) [pic] 2 HI (g) + Cl2(g) has Kc = 1.0 x 10-34 at 25˚C. If a 1.00 L reaction vessel initially contains 0.100 mol of each HCl and solid I2‚ what are the concentrations of HI and Cl2 at equilibrium? 2. Consider the following gas-phase reaction and equilibrium constant at 25 oC: 4 HCl(g) + O2(g) [pic] 2 Cl2(g) + 2 H2O(g) The concentrations of all species were measured at a particular
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The experiment is based on the fact that all acids in the experiment have a unique Ka value. However‚ the only difference between the possible acids is the number of chlorine atoms attached to the carbon atom that is not in the functional group. The reason for the number of chlorine atoms attached to the carbon atom affecting the Ka is that there is a large electronegativity difference between chlorine and carbon‚ pulling the electrons to tend to the chlorine side. This forms a domino effect where
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but when you observe it‚ only one phase is visible. (1 mark lost) 43. Sodium Carbonate will be very soluble in water because of the positive ions of sodium attached to the negative ions of the carbonate. Methanol will be partly soluble in water due to it’s small size and the presence of the OH group in the molecule and it’s very polar nature. Gasoline (Octane)‚ is completely insoluble since it is non-polar.
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Solutions Chem 1290-016 03-05-2010 ------------------------------------------------- Purpose: The purpose of this lab was to use acid-base titrations to find the mass percent of ascorbic acid in a Vitamin C tablet. A known concentration of sodium hydroxide was used and the value found was compared to the stated amount of ascorbic acid listed on the vitamin container. Also in this lab the acidity of different salt solutions were tested using different indicators including litmus paper.
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Purpose: The purpose of the practical that we completed was to determine the molar mass of carbon dioxide (CO2) by experimental means and to observe the reaction of hydrochloric acid and sodium carbonate. Using the balanced equation: Na2CO3 + 2HCl → 2NaCl + H2O + CO2 Materials / Apparatus: 1) 8.00g of sodium carbonate‚ 2) 30mL of hydrochloric acid (6molL-1) 3) 100mL of hydrochloric acid (6molL-1) 4) 100mL conical flask‚ 5) 150mL glass beaker 6) 50mL glass beaker 7) Glass funnel‚ 8) Digital scales
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ammonium ions (NH4+) are called ammonium salts. NOTE: •An anion is a negatively charged ion. Hence:•Hydrochloric acid gives chlorides. E.g. sodium chloride‚ ammonium chloride. •Nitric acid gives nitrates. E.g. barium nitrate‚ copper nitrate. •Sulphuric acid gives sulphates. E.g. silver sulphate‚ iron (ii) sulphate. •Phosphoric acid gives phosphates. E.g. sodium phosphate‚ ammonium phosphate. •Each acid gives rise to a series of salts named by the ANION which they contain. •Some acids can donate more
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Name: Kamaal Thomas |Date: January 4‚ 2011 | |Graded Assignment Lab Report Answer the questions below. When you have finished‚ submit this assignment to your teacher by the due date for full credit. (8 points) |Score | | | 1. For Part 2: Single-Displacement Reactions: For each of the four single-displacement reactions‚ describe what happened in each well. If a chemical reaction occurred‚ write a balanced equation for it. Then using the A‚ B symbols‚
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and depth research report on China Sodium Hyaluronate Injection industry. The report firstly introduced Sodium Hyaluronate Injection basic information included Sodium Hyaluronate Injection definition classification application industry chain structure industry overview; international market analysis‚ China domestic market analysis‚ Macroeconomic environment and economic situation analysis and influence‚ Sodium Hyaluronate Injection industry policy and plan‚ Sodium Hyaluronate Injection product specification
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