of 0.1M Sodium phosphate Monobasic‚ which equal 2.9995g‚ we added it to the 250ml beaker and added 50.0ml of water to dissolve it. On the same time‚ we prepared 250ml of 0.1 Sodium phosphate Dibasic‚ which equal to 3.549g; we added 50.0ml of water to be dissolved. We made these two solutions in order to get their PH. We started with PH 6.0 buffer from Sodium phosphate monobasic solution‚ we added 50ml of Sodium phosphate Dibasic to 250ml beaker‚ placed PH probe‚ then added solution Sodium phosphate
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Solar‚ Hydrogen and Fuel Cell : Current & Future Wan Nadia Kamaruddin‚ Azman Zainal Abidin‚ Noorly Akmar Ramli Yuzlina Mohd Yusop‚ Siti Indati Mustapa Policy Analysis and Research Management Pusat Tenaga Malaysia Level 8‚ Bagunan Sapura @ MINES 7 Jalan Tasik‚ The Mines Resort City 43300 Seri Kembangan Selangor‚ Malaysia http://www.ptm.org.my Abstract In its quest to become a developed country by year 2020‚ Malaysia fully subscribes to the concept of sustainable development. The
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Reagents used: Distilled Water Hydrated Sodium Borate 1.0 M Hydrochloric acid Screened methyl orange Sodium Borate solution Method: Prepare a standard solution of hydrated sodium borate (250cm3 solution) Place the weighing bottle on the balance and record the mass of the empty bottle. Add approximately 4.80 grams of the hydrated sodium borate compound into the weighing bottle and record their weight together. Transfer the measured hydrated sodium borate to the 250 cm3 beaker then find the
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How reaction rate varies with sodium thiosulphate concentration Background information Sodium thiosulphate and hydrochloric acid are both colourless liquids‚ when the two reactants are reacted together they produce sulphur. The sulphur that is produced from the reaction changes the solution to yellow and cloudy‚ this is a precipitation reaction‚ where a two solutions react and a solid forms in the solution‚ the solid is said to precipitate out. Some reactions will occur quickly such as fireworks
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slide with 5% sodium chloride solution. * Examine the cells through the microscope. Draw and label 3 plant cells. * After a few minutes draw out the sodium chloride solution with a piece of filter paper placed at the edge of the coverslip. Replace it with distilled water added at the other side of the coverslip. QUESTIONS 1 Describe the cells in distilled water. How are the cells in 5% sodium chloride different from this? Describe what happens when you take away the sodium chloride solution
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The Effects Sodium Chloride has on pond water Introduction Ponds are depressions in the ground that fill with water from either run offs or melting snow or rain fall from many different weather changes. There are two types of ponds permanent and temporary. Ponds tend to be much smaller in size and are usually only six to ten feet in depth. This differs from a lake because the size of a lake is much larger and is much deeper. The temperature of a pond is usually the same from top to bottom and
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Neutralization experiment AIM:- To investigate how heat is given out in neutralizing sodium hydroxide (NaOH) using different concentrations of Hydrochloric Acid. Background Information:- Substances that neutralize acids are called alkalis. An acid is a substance that forms hydrogen ions (H+ ) when placed in water. It can also be described as a proton donor as it provides H+ ions. An example of an acid is hydrochloric acid (HCl)‚ Sulphuric acid (H2SO4) etc. An alkali is a
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PurposeIn this experiment‚ sodium hypochlorite (NaOCl) in acetic acid mixture was used to oxidize emdo-borneol (an alcohol) to camphor (a ketone). The product would then be purified by sublimation and then be analyzed by Infrared spectroscopy and melting point test. Procedure and ObservationsPlease refer to the lab manual and the carbon copy attached. Data and CalculationsWeight of endo-borneol = 0.2013gNo of moles of endo-borneol = 0.2013g/154.25g mol-1 = 1. 305mmolSince one mole of endo-borneol
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will be attainable. Hypothesis: In a reaction between calcium carbonate and hydrochloric acid‚ the products calcium chloride‚ carbon dioxide and water are formed. I predict that the higher temperature of HCl acid‚ the higher the reaction rate will be‚ this is because at a higher temperature there will more fast-moving hydrochloric acid molecules per set volume. This means that there will be a higher chance of the calcium carbonate molecules colliding with the hydrochloric acid and reacting‚ with
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Gracen Seiler April 7th‚ 2015 Section- 109 Investigating Stoichiometry with Sodium Salts of Carbonic Acid Introduction- This experiment is intended to help find a better understanding of chemical stoichiometry through titrations of NaHCO3 and NA2CO3 with HCl. A chemical reaction is a process that involves rearrangement of the molecular or ionic structure of a substance‚ as opposed to a change in physical form in a nuclear reaction. Titration is when a measured amount of
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