Observations: Part I: Reaction between iron and oxygen Appearance of steel wool after 20 minutes From (relatively) shiny metal strips to notsoshiny strips that are stained with dark‚ reddishbrown stuff. Part II: Decomposition of hydrogen peroxide Appearance of potato and hydrogen peroxide combination: Lots of white‚ foamy bubbles around the potato slices. Day 2 Observations: Part III: Reaction between zinc and acetic acid Appearance of penny in vinegar after 30 minutes: Pretty dark coloured
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CHAPTER 8: ACID – BASE EQUILIBRIUM 4 U CHEMISTRY P 526 – SEE KEY IDEAS - examples f acids and bases. 8.1: The Nature of Acid – Base Equilibria: - Arrhenius acids – H ions in water‚ bases – hydroxide ions in water - acids – sour‚ turn blue litmus to red (pink)‚ conduct electricity - bases – bitter‚ soapy taste‚ slippery‚ conduct electricity‚ turn red litmus to blue Bronsted – Lowry Theory: - acids – donate proton‚ bases accept proton - ex: HCl donates proton to water
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CBSE Continuous and Comprehensive Evaluation (CCE) Sample Question Papers Solutions Term 1 (April to September 2013) Science Class OSWAAL BOOKS CONTENTS l Solutions q Sample Question Paper 6 q Sample Question Paper 7 q Sample Question Paper 8 q Sample Question Paper 9 q Sample Question Paper 10 1 - 7 8 - 13 14 - 20 21 - 26 27 - 32 ll SAMPLE QUESTION PAPER–6 Section-A 1. Moving charges / electric current / magnet (any two). 2. (i) To develop male secondary sex organs
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azo dye was created by reaction of diazonium salt with N‚N-Dimethylanaline. The final product created was 4-dimethylaminoazobenzene-4-sulfonic acid‚ an orange clay-like substance. Sulfanilic acid was chemically manipulated by using sodium carbonate followed by cooled sodium nitrate and hydrochloric acid to form the diazonium salt used in the reaction. The products were washed in ethanol. The product was obtained at an 84% yield and was characterized by its physical attributes. Results and Discussion:
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of industrially important sodium and calcium compounds including Portland cement; the biological significance of sodium‚ potassium‚ magnesium and calcium. • appreciate The s-block elements of the Periodic Table are those in which the last electron enters the outermost s-orbital. As the s-orbital can accommodate only two electrons‚ two groups (1 & 2) belong to the s-block of the Periodic Table. Group 1 of the Periodic Table consists of the elements: lithium‚ sodium‚ potassium‚ rubidium‚ caesium
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1. Indicators were identified with the observation that the colour of some flowers depend on soil composition Classify common substances as acidic‚ basic or neutral * An acid is a substance which in solution produces hydrogen ions‚ H+ or more strictly H3O+‚ sometimes called hydronium ions * A base is a substance which either contains the oxide O2- or hydroxide ion OH- or which in solution produces the hydroxide ion. * A soluble base is called an alkali Common properties of all acids:
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Subject Content Most of the objectives specified in this section relate to Knowledge with Understanding‚ although some indication has been given as to where the skills of Handling Information and Solving Problems may be developed. Teachers are reminded that‚ in the written papers‚ 40% of the marks are allocated to these higher ’thinking’ skills. In almost every section‚ students should therefore be given practice at dealing with unfamiliar situations so that these higher thinking skills can be developed
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for copper from its ore? (A) (B) (C) (D) FeO (s) + SiO2 (s) → FeSiO3 (l) 2CuFeS2 (s) + 5O2 (g) → 2Cu (l) + 2FeO (s) + 4SO2 (g) Cu → Cu2+ + 2e– CuO (s) + Mg (s) → MgO (s) + Cu (s) 4 Which of these processes is endothermic? (A) (B) (C) (D) decomposition of silver chloride to silver and chlorine burning methane condensing steam adding
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The decomposition of sodium carbonate is definitely‚ Na2CO3(s)+CO2(g)+H2O(g). The was the only equation that matched up exactly with my data in terms of percentage. To start off with‚ when I balanced out the equation‚ I got 2 NaHCO3→ 1 Na2CO3(s)+ 1 CO2(g)+ 1 H2O(g). Therefore when I set up my stoichiometry problem I got 3.2 grams NaHCO3 over 1 x 1 mol NaHCO3 over 84.007g NaHCO3 x 1mol Na2CO3 over 2 mol NaHCO3 x 105.987g Na2CO3 x 1 mol Na2CO3. Hence‚ I multiplied 3.2 x 1 x 1 x 105.987 and got 339
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Chemistry Experiment Double Indicator Titration 1 Aim The purpose of this experiment is to find the composition of a sample of sodium carbonate mixture by titration. Introduction The reaction between sodium carbonate and hydrochloric acid occurs in 2 stages‚ with the formation of hydrogen carbonate ion as the intermediate product. Na2CO3(aq) + HCl [pic] NaHCO3(aq) + NaCl(aq) NaHCO3(aq) + HCl(aq) [pic] NaCl(aq) + H2O(l) + CO2(g) [pic] Requirements Hydrochloric
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