Introduction A titration is a technique used to find the solution of known concentration in the concentration of another unknown solution. Typically‚ the known solution is added from a known quantity of unknown solution until the reaction is complete. Titrations are also often used to determine the pH of a solution. This is important because without knowing how acid or basic a solution is people could hurt themselves and others but mixing chemicals together that are lethal. The objective of the
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HKCEE Chemistry 2007 Paper 1 Section A 1. A is a compound formed from oxygen and magnesium‚ while B is a compound formed from oxygen and fluorine. a) Draw the electronic diagram of A‚ showing electrons in he outermost shells only. (1) b) Draw the electronic diagram of B‚ showing electrons in the outermost shells only. (1) c) Compare the melting points of A and B. Explains your answer. Melting point of A is higher than that of B. Ions of A are linked by strong ionic bonds /
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definition of indicator. Indicator- a substance added at the beginning of the titration that changes color at (or very near) the equivalence point. 3. Suppose a sodium hydroxide solution were to be standardized against pure solid primary standard grade KHP. If 0.4538 g of KHP requires 44.12 mL of the sodium hydroxide to reach a phenolphthalein endpoint‚ what is the molarity of the NaOH solution? DATA: Standardization of NaOH Titrant | Sample 1 | Sample 2 | Sample 3 | Weight of
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14 2.14 5 Sodium Acetate 1M NaC2H3O2 Weak Base 9.42 9.42 6 Potassium Dihydrogen Phosphate 0.1M KH2PO4 Weak Acid 5.47 5.47 7 Andy Potassium Hydrogen Phosphate 0.05M K2HPO4 Weak Base 7.71 7.73 8 Ammonium Chloride 0.2M NH4Cl Weak Acid 4.65 4.67 9 Sodium Hydroxide 0.1M NaOHStrong Base 11.95 11.95 10 Rachel Sodium hydroxide 0.01M NaOHBase 11.61 11.72 11 Ammonia 0.1M NH3 Base 9.53 9.48 12 Vinegar 0.83M HC2H3O2 Acid 2.83 2.94 13 Petr Sodium 0.5M NaC6H5O7 Weak Base 9.23 9.21 14 Sodium Sulfate 0
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THIS IS A LEGACY SPECIFICATION H Thursday 26 January 2012 – Morning GCSE GATEWAY SCIENCE ADDITIONAL SCIENCE B B623/02 Unit 1 Modules B3 C3 P3 (Higher Tier) * B 6 2 0 7 6 0 1 1 2 * Candidates answer on the Question Paper. A calculator may be used for this paper. Duration: 1 hour OCR supplied materials: None Other materials required: • Pencil • Ruler (cm/mm) * B 6 2 3 0 2 * INSTRUCTIONS TO CANDIDATES • • • • • • Write your name‚ centre number
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Tara Keller Finding the Ratio of Moles of Reactants in a Chemical Reaction 9/6/13 Introduction The purposes of this lab are to measure the temperature change of the reaction between solutions of sodium hydroxide and phosphoric acid‚ calculate the enthalpy‚ H‚ of neutralization of phosphoric acid‚ and compare the calculated enthalpy neutralization with the accepted value. Theory Calorimetry is the measurement of change of heat in a reaction. A calorimeter is a tool to measure the amount of
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concentration of acetic acid of vinegar‚ in terms of (m/m). Introduction Neutralization is a reaction of an acid with a bases to produce a salt and water. For example‚ the reaction of the strong acid HCl with the strong base NaOH produces the salt sodium chloride and water HCl(aq) NaOH(aq) ( NaCl(aq) H2O(l) Since the acid‚ base‚ and salt in this reaction are all strong electrolytes‚ the net ionic equation for this reaction is H(aq) OH-(aq) ( H2O(l) This same result occurs in the reaction
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For the acid-base properties‚ sample of 1 mL for aqueous solution of the potassium hydroxide‚ hydrochloric acid and the oxides of each sample element was placed in a spot plate and added 2 drops of litmus indicator to each one. Observe the color change. DATA SHEET (Please see attached) TREATMENT OF RESULTS Elements that show metallic properties in the third row of the periodic table of elements are sodium (Na) and aluminum (Al). Those of magnesium (Mg)‚ silicon (Si)‚ phosphorus (P)‚ sulfur
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Three errors that may have occurred during this lab are having the wrong measured amount of supplies‚ the wrong speed of drip‚ and faulty equipment. First off‚ when the lab was prepared‚ the amount of vinegars‚ sodium hydroxide solution and phenolphthalein for each titration may not have been exact. To prevent this error and make sure that the data collected was most correct would include a group member with a steady hand and a good eye for measuring the meniscus when
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Date: 19th February 2011 Topic: Lab report 03 Synthesis of organic Sun Screen Introduction: Aldol Condensation‚ a useful carbon-carbon bond-forming is the an example of a reaction named based on the type of product formed. This product formed involves two aldehydes or ketones in the presence of dilute base‚ yields a molecule having both aldehyde and alcohol. The aldol products are β-hydroxyaldehydes or β- hydroxyketones. Condensation reaction is the transformation
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