distillation and recrystallization using a suitable solvent determined through a solubility test. The identification method used was through Melting Point Determination. By obtaining data of the melting points of the 2 purified compounds and cross-referencing from a list of possible organic compounds‚ the 2 organic compounds were identified to be Dibenzalacetone (Neutral) and o-Chlorobenzoic acid (Acidic). Results A solubility test was conducted to determine the recrystallization solvent to be used for
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Lead (III) nitrate‚ and to eliminate anions. 2. If the reaction with is soluble‚ it would allow me to narrow down my options to fewer suspected anions. Since only a few anions formed percipitates with Lead (III) nitrate according to my table of solubilities‚ it would be easier to eliminate anions. 3. This test requires a spot plate cleaned
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technique that relies on the differing solubility of compounds within a mixture separating to form a pure crystalline solid of the desired product. Often the desired compound is present in a larger quantity within the solution. Therefore‚ a pure sample of this compound can be crystallized from the solution while leaving the impurities dissolved within the solvent. Recrystallization is highly dependent upon the solubility of the two mixed compounds. Solubility is the property of how well a solute dissolves
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Final Organic Study Guide: Be able to develop an Experiment Beginning to End * Find a good reaction * Good reaction is defined by high yield‚ green chemistry (less waste‚ less harmful chemicals) * Reaction found on Reaxys * Find MSDS Sheet for all Compounds (Reactants‚ Products and Side Products) * It is important to know what you are working with * The toxicity category numbers are there to gauge how toxic the chemical is‚ 4 being most severe and 1 being least
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met; 1. The desired substance must be completely precipitated. In most determinations the precipitate is of such low solubility that losses from dissolution are negligible. An additional factor is the "common ion" effect‚ this further reduces the solubility of the precipitate. When Ag+ is precipitated out by addition of Cl- Ag+ + Cl- =<-> AgCl(s) the (low) solubility of AgCl is reduced still further by the excess of Cl- which is added‚ pushing the equilibrium to the right. 2. The weighed
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Samples | Physical State | Color | Appearance | Solubility in Water | | | | | | Group IA and Group IIA Elements | | | | Li2CO3 | Solid | White | Shiny Powder | Soluble | Na2CO3 | Solid | White | Refined Powder | Soluble | K2Co3 | Solid | White | Powder | Soluble | MgCO3 | Solid | White | Unrefined Powder | Insoluble | CaCO3 | Solid | White | Powder | Insoluble | BaCO3 | Solid | White | Crystalized Powder | Insoluble | | | | | | Some Group IVA Elements | | |
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Unit 2 – Disposition of Toxicants Ch 5 – Absorption‚ Distribution‚ and Excretion of Toxicants Ch 7 - Toxicokinetics Chapter 5 Absorptions‚ Distribution‚ and Excretion of Toxicants © The McGraw-Hill Companies‚ Inc‚ 2011 Factors Affecting Disposition • If fraction absorbed or rate absorbed is low‚ may never reach high enough concentration to cause toxicity • Concentrated in a tissue other than the target organ‚ thus decreasing toxicity • Biotransformation may result in formation of less toxic
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Stoichiometry of a Precipitation Reaction Purpose: The purpose of this lab is to calculate the theoretical‚ actual‚ and percent yield of the product from a precipitation reaction. Also‚ to learn concepts of solubility and the formation of a precipitate. Procedure: Weigh out your 1.0g of CaCl2-2H20 and put it into the 100mL beaker‚ Add your 25mL of distilled water and stir to form the calcium chloride solution. Next‚ use stoichiometry to determine how much Na2CO3 and put it into a small
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that the analyte precipitates quantitatively from solution‚ that is‚ >99.99% In aqueous solution silver ion undergoes the following reaction with chloride: Ag+(aq) + Cl-(aq) ?? AgCl(s) Silver chloride is a relatively insoluble compound with a solubility product Ksp =[Ag+][Cl-] = 1.8 x 10-10. Introduction Gravimetric analysis‚ which by definition is based upon the measurement of mass‚ can be generalized into two types; precipitation and volatilization. The quantitative determination of a substance
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color‚ it indicates that there is more than one molecule present. Due to the different chemical structures of each kind of molecule‚ each one will have a slightly different polarity‚ giving each molecule a different solubility level when placed in the solvent. The unequal solubility levels from the various colors in the sample cause different color molecules to leave traces of the solution at different spots as the solvent moves up the paper. The more soluble a
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