1. Provide a general discussion of the solubility/miscibility behavior observed in procedure A-D. For part A of the procedure we worked with the solubility of solid compounds in various solvents. The three solid compounds that were worked with during this procedure were benzophenone‚ malonic acid‚ and biphenyl. These three solids were then mixed with water (highly polar)‚ methyl alcohol (intermediately polar)‚ and hexanes (nonpolar). When benzophenone is mixed with water the results turned out to
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! ! ! ! ! ! ! Determining the solubility of Sodium hydroxide ! ! ! ! ! ! ! ! ! ! ! ! Yunha Kim! Gyeonggi Suwon International School ! IB DP Chemistry SL! Research Question! How is the solubility of sodium hydroxide (NaOH) in water affected by temperature? ! ! Introduction ! Sodium hydroxide is categorised as metal halide salt‚ composed of sodium and chlorine.! The ions present in the solid crystals of potassium chloride dissolve and gain mobility in water
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TITLE: Solubility and Thermodynamics PURPOSE: The purpose of the lab was to determine the thermodynamics variables of ∆H‚ ∆S‚ and ∆G for the dissolution reaction of potassium nitrate in water. The solubility of potassium nitrate in mol/L was measured over a range of various temperatures by finding out at what temperature crystallization began for solutions of different molarities. Then‚ the equilibrium constant was calculated and a graphical relationship between the natural logarithm of the
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Bond By INSTRUCTOR: PURPOSE/INTRODUCTION The purpose of this experiment is to examine the properties of six common chemicals based upon their inherent molecular properties. Though this experiment‚ we can study and compare the bond properties of these chemicals. This experiment is also an introduction comparison of ionic and covalent bonding through real world testing. The properties of each type of bond will be exploited to the fullest during these tests. MATERIALS Materials required
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produce a milky substance‚ they are insoulubale. All of my phosphates formed a insoluble precipitate which is correct accourding to the solubility rules. All of my iodine reactions should have been soluble‚ my exception was Sodium Iodide and Copper(II) Nitrate. My barium Nitrate combined with Sodium sulfate was insoluble with is correct accourding to the solubility rules. All reactions with Chloride should have been soluble and they were. All Bicarbonate were in soluble‚ these I thought were soluble
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developed primarily in the context of immediate release (IR) solid oral dosage forms. It is the scientific framework for classifying drug substances based on their aqueous solubility and intestinal permeability. It is a drug development tool that allows estimation of the contributions of three major factors‚ dissolution‚ solubility and intestinal permeability that affect oral drug absorption from immediate release solid oral dosage forms. The interest in this classification system is largely because
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Principle predicts that the system would shift towards the product’s side in order to alleviate this stress. By shifting towards the product’s side‚ more of the solid is dissociated when equilibrium is again established - which equates to increased solubility. Second‚ imagine an exothermic reaction (heat is on the products side where the dissociated ions from the solid are). Increasing the temperature would result in stress on the products side from the additional heat. Le Châtelier’s Principle predicts
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KF 1(a) SOLUBILITY OF AN SALT BY TITRATION Date : __________________________ Name : _____________________________________________________ Matric no. : __________________________ 1. Objective(s) of Experiment To measure the change in solubility product of potassium periodate (KIO4)‚ when an inert salt (NaNO3) is added to the solution. 2. Why important to determine solubility? The solubility product expression can be used for predicting whether or not precipitation will occur
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didn’t have any reaction with other solution like B and D beside A‚ so if we look at the solubility chart‚ SO2- have only one precipitation with Ba2-. So we come to conclusion that C is CuSO4 and A is Ba(NO3)2 _ So now that we know C is CuSO4‚ other blue solution must be CuCl2 which is D‚ so according to chemical reaction experiment‚ D didn’t have any reaction with other solution beside B‚ if we look at solubility chart CuCl3 only have one precipitation with AgNO3. So we come to conclusion that B is
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familiar with dissolution and precipitation equilibria‚ develop a lab technique suitable for the determination of the solubility for a sparingly soluble salt‚ Ba(NO3)2 (s) at room temperature and measure the common ion effect in solubility of Ba(NO3)2 (s) in an acidic solution‚ HNO3 (aq). Procedure: In this lab‚ the evaporation technique was used to determine the solubility of the salt at room temperature in water. First a 250ml beaker was weighed and the mass was recorded. Then 5.0g of barium
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