Lab 3: Stoichiometry of a Precipitation Reaction NOTE: All photos should be taken so the reading on the electronic balance is readable. Photo 1: filter paper being weighed on electronic balance‚ along with your student information card. Photo 2: beaker with precipitate slurry in it (after step 5) ‚ along with your student information card Photo 3: dried precipitate/filter paper being weighed on electronic balance‚ along with your student information card Additional Question Guidelines:
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carbonate. This formula is: Na2CO3(aq) + CaCl2. 2H2O(aq) à CaCO3(s) + 2NaCl(aq) + 2H2O 1. Put on your goggles. 2. Weigh out 1.0 g of CaCl2·2H2O and put it into the 100-mL beaker. Add 25 mL of distilled water and stir to form the calcium chloride solution. Use only distilled water since tap water may have impurities that interfere with the experiment. 3. Use stoichiometry to determine how much Na2CO3 you will need for a full reaction. 4. Weigh the calculated amount of Na2CO3 and put it in a small
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AP Chemistry Unit 2 Notes Stoichiometry You should understand all that is presented in chapter 3 of your text (Zumdahl: Chemistry‚ 8th edition). Some of the highlights are presented below. Atomic Masses (Section 3.1) Nearly every element is made up of atoms of more than one isotope for that element. A few‚ like Be‚ only have one isotope. Others can have a large number of isotopes. Tin (Sn) has ten isotopes. (No pun intended.) Isotopic abundance is determined by the use of
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Experiment 3: Stoichiometry of a Precipitation Reaction Abstract: In this experiment the objectives were to try and predict the amount of product that was produced in the precipitation reaction of calcium carbonate by using stoichiometry. Then learn how to figure out the actual yield‚ theoretical yield and percent yield of the experiment. Experiment and Observation: The first step in the experiment was to weigh 1g of CaCl2 +2 H2O‚ then pour it into the 100mL
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purpose of this was to determine the concentration of sodium carbonate in an unknown sample by titration. The solution of hydrochloric acid was prepared and standardized using Na2CO3. Observations: Week 1: Standardizing hydrochloric acid using sodium carbonate with bromocresol green indicator Table 1: Titration of sodium carbonate using hydrochloric acid Trial | Mass of Na2CO3 (g) | Burette Reading (mL) | Final Volume of HCl (mL) | | | Initial | Final | | 1 | 0.2123 | 0.00 |
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Title: Stoichiometry of a Precipitation Reaction Purpose: The purpose is to predict the amount of precipitation using stoichiometry. Another purpose is to measure and calculate percentage yield. Procedure: 1. Weigh out 1.0g of CaCl2*2H2O and put it into a 100mL beaker. 2. Add 25mL of distilled water and stir. 3. Using stoichiometry to determine how much Na2CO3 is needed for a full reaction. 4. Weigh the calculated amount and put it in a small paper cup. Add 25mL distilled water and stir
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Name: Brian James|Date:3/10/13| Exp 9: Stoichiometry of a Precipitation Reaction|Lab Section: 73426| Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 CaCl2.H2O(aq)= m/M =1/147 =0.0068 mol CaCO3(s)=0.0068*1/1 =0.0068 mol CaCO3(s)= CaCO3 (s)= CaCO3 mol *CaCO3 g =0.0068 mol*100.01 g =.68 g Step 4: Mass of weighing dish _0.6_g Mass of weighing dish and Na2CO3 .72_g Net mass of the Na2CO3 .12_g Step 6: Mass of filter paper
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Stoichiometry lab 1 Purpose: The purpose of this lab is to find the limiting reactant‚ also to find the percentage yield and percentage purity of the reaction that happens between Calcium Chloride and Sodium Carbonate. The other purpose was to know how the reaction can be balanced and created. Hypothesis: In this lab we are going to see a precipitation reaction. This is a reaction where two soluble salts Sodium Carbonate and Calcium Chloride are added together and the result is the precipitation
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|| || Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 Convert 1.0g of CaCl2-.2H2O to moles of CaCl2-.2H2O 1.0g x 1 mole CaCl2-.2H2O 147.0 g CaCl2-.2H2O = 0.00680 moles CaCl2-.2H2O The mole ratio is 1:1 Hence if we have 0.00680 moles of CaCl2-.2H2O we will as well need 0.00680 moles of Na-2CO3 Convert moles of Na-2CO3 to grams of Na2CO3 = 0.00680 moles Na-2CO3 x 105.99g Na-2CO3 1
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Stoichiometry of a Precipitation Reaction Purpose: The purpose of this lab is to calculate the theoretical‚ actual‚ and percent yield of the product from a precipitation reaction. Also‚ to learn concepts of solubility and the formation of a precipitate. Procedure: Weigh out your 1.0g of CaCl2-2H20 and put it into the 100mL beaker‚ Add your 25mL of distilled water and stir to form the calcium chloride solution. Next‚ use stoichiometry to determine how much Na2CO3 and put it into a small
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