costs by $50. $225 The profit per acre of cantaloupes would have to increase by $99.50. 11. a. No. e. Yes. 13. c. Yes. Profits would increase by $7×1‚000=$7‚000. 15. b. This constraint is nonbinding and its RHS could by 0.15 without affecting the solution. 17. c. Regular octane rating = 90.0‚ supreme octane rating = 102.11. 19. b. Location 6. 21. b. Macon. Each additional unit of capacity there increases costs by $36.45 (which is the cheapest way to increase capacity). e. $1 extra. 23. c. $0. 25.
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Level J Algebra First Two Weeks Sample Questions Exam 1. Solve‚ x ( x + 9 ) = 0. Reference: Algebra 1‚ Part 2‚ Chapter 8.7‚ Activity (1a)‚ Page 78 Solution: x = 0 or x = −9 2. Factor‚ x 2 + 5 x + 2 xy + 10 y. . Reference: Algebra 1‚ Part 2‚ Chapter 8.6.1 Activity 1 #(d)‚ Page 73 Solution: x 2 + 5 x + 2 xy + 10 y = x( x + 5) + 2 y ( x + 5) = ( x + 5)( x + 2 y ) 3. Factor‚ a 2 + 4 a − 32. Reference: Algebra 1 Part 2‚ Chapter 8.4.3‚ Activity (a)‚ Page 61 Solution: a 2
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Chapter 2 An Introduction to Linear Programming 18. a. Max 4A + 1B + 0S1 + 0S2 + 0S3 s.t. 10A + 2B + 1S1 = 30 3A + 2B + 1S2 = 12 2A + 2B + 1S3 = 10 A‚ B‚ S1‚ S2‚ S3 0 b. c. S1 = 0‚ S2 = 0‚ S3 = 4/7 23. a. Let E = number of units of the EZ-Rider produced L = number of units of the Lady-Sport produced Max 2400E + 1800L s.t. 6E + 3L 2100 Engine time L 280 Lady-Sport maximum
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I met with my College Algebra Professor‚ Sarah Hawkins on October 12‚ 2016 at 11 am. The reason I met with her was to discuss my grade in College Algebra and to improve it. I also discussed upcoming tests and how to study for them. When I first walked into her office I was really down about my grade because I recently failed my first test and it brought my average really down. I asked if there was any way I can bring my grade up and she told me how a student can retake one test out of three for
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BUFFER SOLUTIONS CONTENTS 1. Introductions. 2. Principles of buffering. 3. Applications a. Simple buffering agents. b. "Universal" buffer mixtures. c. Common buffer compounds used in biology. 4. Buffer capacity. 5. Calculating buffer pH a. Monoprotic acids. b. Polyprotic acids. 6. Biblography. INTRODUCTION A buffer is an aqueous
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Linear Regression & Best Line Analysis Linear regression is used to make predictions about a single value. Linear regression involves discovering the equation for a line that most nearly fits the given data. That linear equation is then used to predict values for the data. A popular method of using the Linear Regression is to construct Linear Regression Channel lines. Developed by Gilbert Raff‚ the channel is constructed by plotting two parallel‚ middle lines above and below a Linear Regression
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signals generated by the human voice are small. Voice quality needs to focus on small signals. To solve this problem‚ adaptive DPCM is developed. 4. Linear Predictive Coding Linear Predictive Coding (LPC)‚ a powerful‚ good quality‚ low bit rate speech analysis technique for encoding a speech signal. The source filter model used in LPC is also known as the linear predictive coding model. It has two main components LPC analysis (encoding) and LPC synthesis (decoding). The goal of the LPC analysis is to estimate
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Interview Project: Learning Experience with Linear and Systemic Questioning Nasheena Richardson Capella University COUN 5220 Introduction to Marriage and Family Therapy April 20‚ 2013 Abstract In this paper I will have a detailed interview process laid out in order of focus. First‚ I am focusing my interview on the background of my partner and what motivates her to go to school and further her education. Secondly‚ I will ask her why she chose to specialize in her field
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CHAPTER 4 – THE BASIS OF STATISTICAL TESTING * samples and populations * population – everyone in a specified target group rather than a specific region * sample – a selection of individuals from the population * sampling * simple random sampling – identify all the people in the target population and then randomly select the number that you need for your research * extremely difficult‚ time-consuming‚ expensive * cluster sampling – identify
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Name of Property Example Explanation Zero Exponent Property x0 = 1 (x ≠ 0) Any number (except 0) with an exponent of 0 equals 1. Negative Exponent Property x−n = 1 xn (x ≠ 0) Any number raised to a negative power is equivalent to the reciprocal of the positive exponent of the number. Product of Powers Property xn•xm = xn+m (x ≠ 0) To multiply two powers with the same base‚ add the exponents. Quotient of Powers Property xn xm = xn−m (x ≠ 0) To divide two powers with the same base‚ subtract the exponents
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