12 4.1 The main goal 12 4.2 Objectives 12 5 Preconditions and criteria 14 6 Solutions 15 6.1 Possible solutions 15 6.2 Time investment 15 6.3 Resources‚ advantages and disadvantages 15 7 Assessment of possible solutions 16 7.1 Solution requirements 16 7.2 Testing against preconditions and criteria 17 7.3 Advantages and disadvantages of solutions 18 8 Conclusion and recommendation 20 9 Guidelines on implementation 21 Appendixes
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the Case Analysis your objective is to analyze the management problem and make a recommendation for solving that problem. By applying concepts to actual cases‚ you improve your ability to think analytically when identifying problems and creating solutions. Preparing the Case Analysis There are four basic steps to follow when preparing a Case Analysis. However‚ because you will encounter a wide variety of cases and problems‚ you should determine the appropriate approach to each situation. Generally
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takes place when a solute dissolves in a solvent? How would this be determined? b. What process in the molecular level takes place to explain what is observed? c. Do all solutes dissolve in the same way? Do acids and bases dissolve in the same way? Solutions capable of conducting electricity‚ such as ionic compounds‚ are referred to as electrolytes. There are three major classifications
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would have a higher rate of osmosis and the cell filled with water and placed in 40% sucrose solution would have the highest negative weight change. Introduction The
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semi permeable membrane and wouldn’t be able move in and out of cells affectively. Because potatoes have sucrose inside them a concentration gradient is present and if placed in any solution osmosis movement of water through semi permeable membranes would naturally occur. If the concentration of sucrose in the solutions is less than the concentration in the potato then the potato will gain mass and vice versa. In conducting this experiment sucrose concentrations can be used in the future to
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there is no net diffusion of water. Water will move in one direction or the other‚ and this is determined by the solute or solvents concentration levels. If the two solutions are of equal concentrations‚ they will be isotonic. If the concentrations are unequal‚ the solution with the higher concentration is hypertonic‚ and the solution with the lower concentration is hypotonic. What is the solute concentration of potatoes? We can determine this by conducting an experiment in which involves the process
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Define a saturated solution. 4. Define an unsaturated solution. 5. What is meant by solubility? 6. On the “Solubility Table” what‚ precisely‚ does the word soluble mean? 7. If 25.0 mL of 0.90 M HCl is added to 125.0 mL of water‚ what is the final [HCl]? 8. Calculate the [Fe3+] in a 0.25 M solution of Fe2(SO4)3? 9. Calculate the [Na+] in a 0.55 M solution of sodium acetate. (Write the proper formula for sodium acetate first). 10. Calculate the [Na+] in a 0.55 M solution of sodium carbonate
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and stays the same shape. All the carrots we put in the salt solution was from the same carrot‚ the 0% carrots mass was 6.8grams‚ the 5% salt solution is 14.6 grams‚ the 10% salt solution is 6.3grams and the 15% salt solution is 6.8 grams. My hypothesis was that the carrot would shrink and be very small and gooey‚ but it was wrong. The controlled variable in this lab is the carrot and time‚ the manipulated variable is the salt solution‚ and the resulting variable in this lab is what happens to
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The Effect of Osmosis on Differences of Amount of Sucrose Osmotic Pressure and its Influence on the Concentration of Sucrose in Solution Brennan Montoni Movement of molecules and Ions Names of Lab Partners Biology 110 March 23‚ 2011 Code of Academic Integrity INTRODUCTION: During the process of osmosis‚ water will move across a differentially permeable membrane. The water will transfer from a region of lesser solute concentration to a region of greater solute concentration
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Lab : Iodine-starch Clock Reaction Pre-lab: Before the lab was conducted‚ the concentration of the Iodate ions to be in the mixture made by dissolving specific volumes of solution A with a constant concentration and water was calculated using the dissolution formula: C1V1 = C2V2 Sample Calculation 1: Concentration of the Iodate ions: For mixture 1: C2 = C1V1/ V2 = (0.020mol/L) x (0.003L)/(0.01L) = 0.006mol/L The same calculations were used in the calculating of the
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