India and Indian Bank reported a massive increase in the nonperforming assets that were above 35% in gross magnitude in the same fiscal. Cause for the steep rise in NPA percentage * With a quick rise in the disbursal of restructured loans in the standard category‚ NPA has really risen over the limit although the limiting ratio is not so much alarming. With the net NPA rate standing steady at the 1.5% for public sector banks‚ restructured loans is a matter of primary concern. Moreover‚ the contribution
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The average (mean) annual income was less than $50‚000‚ One-Sample Z: Income ($1000) Test of mu = 50 vs < 50 The assumed standard deviation = 14.64 95% Upper Variable N Mean StDev SE Mean Bound Z P Income ($1000) 50 43.74 14.64 2.07 47.15 -3.02 0.001 α 0.05= -1.645 H0 μ = 50‚000 Ha μ < 50‚000 The hypothesis test claims that the average annual income was less than $50‚000. H0 claims equal
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10 pounds the first two weeks with a standard deviation of 2.8 pounds. A random sample of 50 people who joined the new weight reduction program revealed the mean loss to be 9 pounds. At the .05 level of significance‚ can we conclude that those joining Weight Reducers on average will lose less than 10 pounds? Determine the p-value. 32. Dole Pineapple‚ Inc.‚ is concerned that the 16-ounce can of sliced pineapple is being overfilled. Assume the standard deviation of the process is .03 ounces. The quality
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DGHG - CCResort Business Analytics Department’s (BAD) Report Executive Summary: The Business Analytics Department has compiled this report based on data supplied by DGHG. The purpose of this report is to use this data to answer several key questions set out by DGHG‚ along with providing information as to whether the company has been meeting its key performance indicators‚ as set out in the business plan. The questions this report will primarily address‚ are as follows: * More than
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Range = Maximum – minimum Interquartile range (IQR) = Q3 –Q1 Standard deviation is the average distance values fall from the mean of graph. 3. Q1(lower quartile) is the 25th percentile of ordered data or median of lower half of ordered data Median (Q2) is the 50th percentile of ordered data Q3 (upper quartile) is the 75th percentile of ordered data or median of upper half of ordered data Z scores are standarized standard deviation measurments of how far from the center (mean) a data value falls
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02+16.04+16.05+16.01+16.02+16.02+16.03+16.01+16+16.07)/12=16.03 (b) Calculate the sample standard deviation. =0.0193 3.2. The bore diameters of eight randomly selected bearings are shown here (in mm): 50.001‚ 50.002‚ 49.998‚ 50.006‚ 50.005‚ 49.996‚ 50.003‚ 50.004 (a) Calculate the sample average. (50.001+50.002+ 49.998+50.006+50.005+49.996+50.003+50.004)/8=50.001 (b) Calculate the sample standard deviation. =3.2186 3.4. Consider the furnace temperature data in Exercise 3.3 (The nine measurements
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Joey Stevens QMM 240 TR 10:00-11:15 Computer Assignment #1 1. a. Excel Histograms Bins MPG | Frequency | 11 | 1 | 16 | 3 | 21 | 16 | 26 | 34 | 31 | 13 | 36 | 9 | 41 | 2 | 46 | 2 | Bins Weight | Frequency | 1300 | 1 | 1780 | 7 | 2260 | 18 | 2740 | 12 | 3220 | 22 | 3700 | 11 | 4180 | 7 | 4660 | 2 | b. I chose the number of classes based on the Sturges’ Rule table. I knew I had 80 observations so that put me between either 7 or 8
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the mean parts per million of dissolved solids in a 25-week sample to be 52 with a standard deviation of 32. Has there been a change in the average level of dissolved solids in this stream? 2 An exhaustive survey of all users of a wilderness park taken in 1960 revealed that the average number of persons per party was 2.6 In a random sample of 25 parties in 1985‚ the average was 3.2 persons with a standard deviation of 1.08. a. Test the hypothesis that the number of persons per party has changed
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Terms: Forecast vs Forecast Error We clarify the terms used in the practice problems and the final exam problems. Some statisticians speak of the standard deviation or variance of the forecast. The forecast here is the distribution of future values. It is a random variable‚ which has a standard error (standard deviation and variance). Other statisticians use the term forecast for the mean of the distribution of future values. The forecast error (the error term in the forecast) is the distribution
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organization‚ analysis‚ interpretation‚ and presentation of data. It provides a more accurate way of expressing data rather than mere observation. This experiment used the different statistical concepts such as the Q test‚ mean‚ standard deviation‚ relative standard deviation‚ range‚ relative range‚ and confidence limits or confidence intervals. The results generated from these tests are used as a basis to check whether the values obtained from weighing 10‚ 25 centavo coins using an analytical balance
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