size normally distributed with a mean of 6.0‚ and a standard deviation of 1.0. I am going to order 5000 garnet wedding rings from my reliable Siberian source. They will manufacture ring size from 4.0‚ 4.5‚ 5.0‚ 5.5‚ 6.0‚ 6.5‚ 7.0‚ 7.5‚ 8.0‚ 8.5‚ 9.0‚ and 9.5. How many wedding rings should I order for each of the ring size if I order 5000 rings altogether? (Note: It is natural to assume that if your ring size falls between two of the above standard manufacturing size‚ you will take the bigger of
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average total of 360 drives per day. The company runs quality checks called PDQ tests on one of their drives every hour of production. The test takes up to 20 minutes. Their historical “in control” process is defined with a mean of 7.0 and a standard deviation of .3. Four-D performs their own PDQ tests on the drives that DataStor ships them. They sample ten drives at random. If any of the drives have a PDQ score of 6.2 or below‚ then the entire shipment will be rejected. Penalties are assessed
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P is approximated by a normal distribution if Where this applies: Mean = Standard Error = Z-Values for Proportions Using the sample distribution for Proportions Determine the population proportion‚ Calculate the sample proportion‚ p Derive the mean and standard deviation of the sampling distribution Define the event of interest If n and n(1- are both > 5‚ the convert p to z-value Use the standard normal table to determine probability Chapter 8: Estimating Single Population Parameters
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opportunities available in the economy. 4.) Two factors that influence the nominal risk-free rate are: A. The relative ease or tightness in capital markets and the expected rate of inflation 5.)The total risk for a security can be measured by its: C. Standard Deviation or returns 6.) Which of the following is an underwriting function? B. Risk-bearing 7.) An ETF (exchange fund): C. Is priced continuously during the trading day 8.) Which of the following are reasons that U.S. investors should consider foreign
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* 5S should be one of the Lean tools that should be implemented first. If a process is in total disarray‚ it does not make sense to work on improvements. The process needs to be first organized (stabilized) and then improved. | | | Standard Work | Standard work is work in which the sequence of job elements has been efficiently organized and is repeatedly followed by a team member. It is an important prerequisite for successful implementation of Kaizen and many other aspects of Six Sigma.
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entire weekend. However‚ the bank will lose out on interest payments on any excess cash stocked into the cash machines. A particular bank believes that the mean withdrawal rate per transaction is normally distributed with a mean of $150 and a standard deviation of $50. Is there any evidence that the bank has got its calculations wrong‚ if a random sample of 36 customer transactions gives a mean sample of $160? State your null and alternative hypotheses. 4. A random sample is obtained from a population
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Supply Chain Management Application in E-Commerce Company Taking JD.com as an example MACC 5P31 Advanced Management Accounting Section 2 Instructor: Dr. Hemantha Herath Yifan ZHU 5294269 Zhulai LI 5608690 Ying GONG 5727086 Yahong HU 5718697 Due date: April 2nd‚ 2015 Abstract The target of this paper is to figure out the best way for the JD.com which is the largest B2C online shopping website in China in the area of supply chain management. The main issue is under
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Fama-Macbeth (1973) CAPM test on size and value effects. The average return and standard deviations are shown in Table I: Table I: Average returns and standard deviations of the 25 portfolios‚ from 07/1926 to 09/2012. There are a total of 1035 observations. | Portfolios | 1(Low) | 2 | 3 | 4 | 5 (High) | 6(Low) | 7 | 8 | 9 | 10(High) | Mean Return | 0.73 | 1.09 | 1.30 | 1.45 | 1.67 | 0.87 | 1.23 | 1.31 | 1.36 | 1.47 | Standard dev. | 12.19 | 10.54 | 9.19 | 8.61 | 9.54 | 7.96 | 7.85 | 7.32 | 7.59 |
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household size data is 3.42 and the standard deviation is 1.739. According to the histogram the data is mostly skewed to the right. The Years data shows that most customers that were sampled have lived at their current location for more than ten years. There is a high concentration of customers located within the 10-18 year range and since both 14 and 18 had the most single occurrences of 5 apiece both of these are used as the mode. The standard deviation for this data is 5.086. The
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Name__Solutions_______________ Date_________________________ Answer the following questions from the given situation. Suppose a Normal model describes the fuel efficiency of cars currently registered in your state. The mean is 24 mpg‚ with a standard deviation of 6 mpg. -3σ - 2σ -1σ μ 1σ 2σ 3σ 1. Sketch the Normal model (label). 68% 95% 99.7 % 2. What percent of cars get less than 15 mpg? 15 24 z 1.5 P(y<15)=P(z<-1.5)=6.7% 6 12 18 24 30 36 42 6 3. What percent of cars get between 20 and
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