sample mean to be 26.8 miles per gallon. From previous studies‚ the population standard deviation is known to be 5 miles per gallon. Could we reasonably expect that we could select such a sample if indeed the population mean is actually 28 miles per gallon? 2. Computing World has asserted that the amount of time owners of personal computers spend on their machines averages 23.9 hours per week and has a standard deviation of 12.6 hours per week. A random sampling of 81 of its subscribers revealed a
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pizza delivery order and letting the customers inform their own pick-up times. The data is fine and appropriate for statistical use‚ and hence we can go through the statistical calculations. Statistical Efforts Using Excel‚ we found the standard deviation and mean of the sample data for the total delivery time‚ preparation time‚ waiting time and travel time. First‚ in order to discuss the viability of the company’s 29-minute delivery guarantee strategy‚ we computed the following statistical
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Aerobic respiration in yeast Research question: What was the effect of anaerobic respiration in different environments determined the increase in size of a dough by the temperature? Hypothesis: It is hypothesized that if the temperature increases the dough will become bigger and bigger. Independent variable: (change) • Temperature • Height of the dough Dependent variable: (doesn’t change) • Amount of vegetable oil • Time • Volume of yeast solution Control variables: Variable
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symbol in the book Steps: 1. Calculate Returns: Rt=Pt-Pt-1Pt-1= PtPt-1-1 2. Mean Monthly Returns and Standard Deviations for Each Stock: Mean Monthly Return: R= 1T*t=1TRt → AVERAGE Standard Deviation: STDEV = Var = 1T-1*t=1T(Rt-R)2 → STDEV.S 3. Convert Monthly to Annual Returns and Standard Deviations: Annual Mean Return: RA=12*RM Annual Standard Deviation: STDEVA= 12* VarM= 12*STDEVM 4. Portfolio (equally weighted): Monthly Return: RP= iwiRi equally weighted:
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____ 1. The pie chart describes the distribution of state tree types for the 50 states in the United States. The category “Other” include all trees that are the state tree for two or fewer states. Which of the following conclusions can we draw from this chart? a. Some states have not designated a “state tree.” b. The cottonwood is the state tree for 12 states. c. Taken together‚ oak‚ pine‚ and maple are the state trees for more than half the states. d. There are 10 states that have designated
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Two Practice Problems Prepare a written response to the following questions. Chapter 2 12. For the following scores‚ find the mean‚ median‚ sum of squared deviations‚ variance‚ and standard deviation: 1‚112; 1‚245; 1‚361; 1‚372; 1‚472 Mean is 1312 Median is 1361 Sum of squared deviations is 76089.2 Variance is 15218 Standard deviation is 123.361 16. A psychologist interested in political behavior measured the square footage of the desks in the official office for four U.S. governors and of
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Threesamma Joseph HLT-362V 9/7/2012 1. The answer is C‚ interval/ratio. The researchers analyzed the data as though it were interval/ratio level. They calculated the mean and standard deviation which is only appropriate for interval/ratio level data. 2. The mean post-test empowerment score for the control group is 97.12. This data is found explicitly in the chart of data given. 3. The baseline score mean is 14 and the post-test depression score mean is 13.36‚ meaning they were less depressed
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module 1 3 6 4 7 5 4 6 4 7 1 8 1 More 0 Q1 Descriptive Statistics Excel Worksheet b Q2 d Q3 e Q4 b 5. For the following sample of scores: 2‚ 6‚ 1‚ 4‚ 2‚ 2‚ 4‚ 3‚ 2 Mean variance standard deviation 2.889 2.099 1.537 Find the mean‚ variance and standard deviation 6. A sample of size 7 (n = 7) has a mean of M = 9. One of the sample scores is changed from x = 19 to x = 5. What is the value for the new sample mean? New Sample Mean 7 7. Using Excel create a histogram
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customer. The company uses an automatic lathe to produce the pins. Due to many causes- vibration‚ temperature‚ wear and tear and the like-the length of the pins made by the machines are normally distributed with a mean of 1.012 inches and a standard deviation of
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difference in the mean purchase for men customers versus women customers. It wishes to estimate this difference using a 95 percent confidence level. If the sample size is n = 10 from each population‚ the samples are independent‚ and sample standard deviations are used‚ and the variances are assumed equal‚ then the critical value will be t = 2.1009. Answer: TRUE Diff: 2 Keywords: confidence interval‚ mean difference‚ independent‚ sample Section: 10-1 Estimation for Two Population Means Using
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