ampicillin sodium (mg) What weight (in mg) of ampicillin sodium (C16H18N3NaO4S) will provide 144 mg of ampicillin base (C16H19N3O4S)? 27. Weight of potassium permanganate (g) Potassium permanganate is normally made as a concentrated solution which is then diluted prior to use. The concentrated solution is normally made as a 1 in 800 solution. You are asked to supply a patient with sufficient of this solution to allow them to make of use 25 mls of the further diluted solution (1 in
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of Potassium Hydroxide affecting the temperature of water that it is dissolved in. One person stirred in the different concentrations of Potassium Hydroxide while the other measured the temperature as it rose after the pellets dissolved. At times it was difficult to ensure that the pellets were completely dissolved within the solution. Raw Data Table: The temperature of water after dissolving different concentrations of Potassium Hydroxide in it. Concentration of Potassium Hydroxide (g/ml) (±0.01
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22nd‚ 2011. 1. What is a true solution? Explain why the solute does not settle out of a solution. Is it possible to have one solid dissolved in another? Explain. In metals it would be called an alloy. 2. An aqueous solution of KCl is colorless‚ KMnO4 is purple‚ and K2Cr2O7 is orange. What color would you expect of an aqueous solution of Na2Cr2O7? Explain. Orange. 3. Explain why hexane will dissolve benzene but will not dissolve sodium chloride. Sodium chloride is an ionic compound.
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Investigating the solubility of Group II hydroxides Jiyeon Kim Aim: To investigate the solubility of Group II hydroxides (Mg(OH)2‚ Ca(OH)2‚ Sr(OH)2‚ Ba(OH)2) Research Question: What is the trend of solubility of Group II hydroxides going down the group as determined through measuring the volume of hydroxides needed to titrate with a known concentration of hydrochloric acid? Background Information: Solubility is when a solute forms a homogeneous solution by dissolving in solvent. The solubility
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Title : Expt.1 Determination of the enthalpy (heat) of reaction of a monobasic acid with sodium hydroxide Experiment no : 1 Experiment title : Determination of the enthalpy (heat) of reaction of a monobasic acid with sodium hydroxide Objectives: 1) To understand the enthalpy chemistry. 2) To determine the calorimeter constant. 3) To determine the enthalpy reaction of acid-base reactions. 4) To study the exothermic reaction. Apparatus and Materials : * Dewar flask
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Prior to begin the experiment‚ preparation for some solutions is required to enhance the lab performance. The solutions needed are standardized potassium bromate‚ standardized sodium thiosulfate‚ and starch indicator. First‚ to prepare a starch indicator‚ pulverize 1g of soluble starch and add 15mL of water to make it as a paste-like substance. Dilute it with about 500mL of boiling water‚ and continue to heat until the mixture becomes clear. Cool it to room temperature and save it into a stoppered
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extracellular solution‚ this was deemed the baseline. When we punctured each of the DEM‚ DEL1‚ and DEL2 crayfish muscles‚ we observed a large drop in voltage (refer to Figure 1)‚ therefore indicating that inside the muscle was more negative in relation to the outside solution. The time when the pipette was intramuscular‚ the recording showed a steady reading of the intramuscular voltage potential (Figure 1). When the pipette was removed from the crayfish muscle and was back in the extracellular solution‚ the
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In the experiment‚ we tested a sodium chloride solution. Along with the tested solution‚ control groups (water and sodium phosphate) were used to be help understand whether or not NaCl was a buffer. Water was the negative control group and sodium phosphate was the positive control group. If NaCl was a buffer than the pH would be stabled as the sodium phosphate buffer. If NaCl was not a buffer than the pH would fluctuate like the negative control‚ water. During the first trial and prior to the drops
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were added from the burette is 0.00327 moles (1 tablet of Gaviscon). However‚ for Quick-eze‚ the number of moles is 0.00216 moles (1 tablet). This means the average volume of the NaOH have affected the number of moles as the concentration of the sodium hydroxide is 0.1M. This means that if less NaOH was required to neutralise the acid‚ the number of moles of HCl neutralized by the ant-acid would be greater. For example; by using mole ratio‚ the number of moles of HCl reacted with the NaOH is 0.00216
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of 0.1M Sodium phosphate Monobasic‚ which equal 2.9995g‚ we added it to the 250ml beaker and added 50.0ml of water to dissolve it. On the same time‚ we prepared 250ml of 0.1 Sodium phosphate Dibasic‚ which equal to 3.549g; we added 50.0ml of water to be dissolved. We made these two solutions in order to get their PH. We started with PH 6.0 buffer from Sodium phosphate monobasic solution‚ we added 50ml of Sodium phosphate Dibasic to 250ml beaker‚ placed PH probe‚ then added solution Sodium phosphate
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